research29 min studyLesson 687 in Physics

Finite coordinate changes move coefficients while preserving predictions

Transform a beta function and an observable consistently, and identify which perturbative invariants require assumptions.

On this page

What you’ll understand

  • Transform a single-coupling beta function by the chain rule.
  • Derive the invariance of its first two coefficients under specified redefinitions.
  • Translate observable coefficients and interpret residual higher-order differences.

A renormalization scheme assigns coordinates to a theory rather than directly labeling an observable. A finite analytic change of coupling reshuffles both the beta function and the perturbative coefficients of predictions. Certain leading beta coefficients survive such a change, but that statement has specific single-coupling and mass-independent assumptions. We will derive the transformation and use an observable conversion to explain why holding the same numerical coupling in two schemes does not constitute a physical comparison.

A beta function transforms as a vector field

Take a dimensionless four-dimensional marginal coupling g and define a new coordinate g′=g+c₁g²+c₂g³ plus higher powers, with no explicit scale dependence. Applying the chain rule gives β′(g′)=(dg′/dg)β(g). Express the right-hand side back in terms of g′ rather than leaving a mixture of variables. The inverse series begins g=g′−c₁g′²+(2c₁²−c₂)g′³. Without this inversion, even the apparent coefficient of the next power can be misidentified.

For β=b₁g²+b₂g³+b₃g⁴, the first two coefficients remain b₁ and b₂, while the third changes as shown below. This invariance assumes a single marginal coupling, an analytic near-identity redefinition, and compatible mass-independent conventions without an explicit μ-dependent finite transformation. Several couplings, threshold-dependent definitions, dimensionful parameters, or a nonstandard leading normalization require a more general analysis. It is therefore safer to quote the transformation assumptions than to say that two beta coefficients are universal without qualification.

g′=g+c1g2+c2g3+O(g4),β′(g′)=dg′dgβ(g),b1′=b1,b2′=b2,b3′=b3−c1b2+(c2−c12)b1g'=g+c_1g^2+c_2g^3+O(g^4),\qquad \beta'(g')=\frac{dg'}{dg}\beta(g),\qquad b_1'=b_1,\quad b_2'=b_2,\quad b_3'=b_3-c_1b_2+(c_2-c_1^2)b_1
All quantities are dimensionless and β=dg/dlnμ in four dimensions. The beta expansion starts at g² in this chosen variable; a gauge coupling whose beta starts at g³ would use a different coefficient convention. The prime labels a scheme coordinate, not a derivative except in dg′/dg.↔ Scroll wide equations horizontally.

Physical series coefficients transform together with the coupling

Suppose a dimensionless physical quantity has expansion A=g+r₁g² through second order. Substituting the inverse transformation changes its next coefficient to r₁−c₁ in the primed scheme. This cancellation is the simplest example of scheme independence: the value assigned to a coupling and the coefficient multiplying its square are not separately observable. The same physical input must be used to determine g and g′. Comparing both formulas at the same numerical input generally violates that requirement.

Even after a consistent conversion, evaluating two truncated formulas as ordinary numbers can leave a difference of higher order. Such a difference is expected because the substitution itself generates unretained powers. It does not mean exact observables depend on arbitrary schemes. Conversely, the numerical size of a scheme variation is not a rigorous bound on all omitted terms. A pathological transformation can manufacture poor-looking coefficients or a misleading apparent convergence pattern without teaching anything about the underlying physical accuracy.

A=g+r1g2+O(g3)=g′+(r1−c1)g′2+O(g′3)\mathcal A=g+r_1g^2+O(g^3)=g'+(r_1-c_1)g'^2+O(g'^3)
A is a dimensionless physical prediction expressed in two consistently matched coupling coordinates at the same scale and kinematics. The equality is perturbative through second order, not equality of unexpanded truncated numerical polynomials at every finite coupling.↔ Scroll wide equations horizontally.

Fixed-point coordinates can move while critical slopes remain invariant

For an exact flow, an invertible smooth transformation maps a zero of β to a zero of β′. Its coordinate usually changes. At the fixed point, the derivative of β with respect to its coupling is invariant because the extra derivative of the coordinate map multiplies β itself and vanishes. This statement concerns an exact regular transformation near the fixed point. A zero produced by truncating a weak-coupling series at order-one coupling may move or disappear under allowed higher-order redefinitions and is not automatically a controlled physical fixed point.

The function lab illustrates the finite quadratic part of a coordinate change. Reset and set both controls to a=0.5 and x=0.20, predicting y=0.020. Reset and set a=1 and x=0.20, predicting y=0.040. Interpret y as δg=c₁g²; adding g=0.20 manually gives primed coordinates 0.220 and 0.240. This does not calculate an observable or beta coefficients. Its coefficient changes compare two independent coordinate definitions, not an actual scale trajectory or a change of the underlying interaction.

Transform the first scheme-dependent beta coefficient

Let β(g)=−g²+0.5g³+2g⁴+O(g⁵). Define g′=g+g² with c₂=0. Find the beta function through g′⁴ and identify the first coefficient that changes.

  1. Read b₁=−1, b₂=0.5, b₃=2 and c₁=1, c₂=0 in the stated single-coupling convention.

  2. The first two coefficients remain −1 and 0.5. The transformed third coefficient is 2−1×0.5+(0−1)×(−1)=2.5.

  3. Therefore β′=−g′²+0.5g′³+2.5g′⁴+O(g′⁵). This is a coordinate transformation of the same flow, provided the coupling conversion is also used.

The result

The transformed beta function is −g′²+0.5g′³+2.5g′⁴ through the stated order; the g⁴ coefficient is the first one changed here.

Explore the model

Interactive lab

Interactive lab · function

Display the finite coordinate correction

Reset and set BOTH controls to a=0.5 and x=0.20, predicting y=0.020. Reset and set a=1 and x=0.20, predicting y=0.040. Assign y=δg=c₁g², then add g manually. This is a coordinate illustration without RG integration.

Display the finite coordinate correctionThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forChanging a scheme coordinate does not by itself change a physical prediction when its coefficients are converted too.

Check your understanding

For the stated single-coupling analytic near-identity mass-independent transformation, which beta coefficients remain unchanged?

Try it yourself

A physical quantity has A=g+3g²+O(g³). Define g′=g+2g². Find the second-order primed expression. For g=0.050 use g′=0.055 and compare the two unexpanded second-order values. Explain their difference.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the inverse series g=g′−2g′²+O(g′³); the numerical substitution introduces terms beyond the retained order.

Compare with the solution

The primed series is A=g′+(3−2)g′²+O(g′³)=g′+g′²+O(g′³). The old polynomial gives 0.050+3×0.0025=0.0575; the new gives 0.055+0.003025=0.058025. Their difference 0.000525 starts at higher order when g′=g+2g² is expanded. It is a truncation effect, not physical scheme dependence.

Take it with you

  • A beta function transforms by the coupling-coordinate chain rule.
  • Leading-coefficient invariance has explicit assumptions.
  • Observable coefficients must be translated along with their running parameters.

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