research30 min studyLesson 997 in Physics

Uncertainty budgets and negative results

Separate averaging noise, common calibration error and correlation before interpreting a null-force measurement.

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What you’ll understand

  • Propagate independent and correlated uncertainty components with units.
  • Identify a common-error floor that averaging cannot remove.
  • Calculate and interpret a stated Gaussian one-sided upper confidence construction.

A negative result is a quantitative constraint produced by a measurement model, rather than the absence of a striking plot. Its interpretation depends on which errors vary independently, which are shared, and whether their distributions are justified. Repeating a force measurement can reduce independent sensor noise while leaving one calibration offset common to the entire batch. Treating every error bar as independently redrawable would exaggerate the benefit of averaging. A useful uncertainty budget connects each component to a physical mechanism and then propagates the resulting covariance into the reported observable.

Write the error model before combining its terms

For a transparent Gaussian example, let every reading equal one constant true force plus a batch-wide calibration error plus independent reading noise. Both errors have zero mean in the stipulated repeated-measurement model; their known standard deviations are given. The calibration error is shared within a batch, while new independent calibration and noise errors are drawn across hypothetical repetitions of the full procedure. Averaging divides only the independent-noise variance by the number of readings.

This is stronger than merely calling an unknown offset systematic. A completely unmodeled fixed bias has no automatically justified Gaussian distribution or coverage probability. Calibration information must support the adopted uncertainty model. NIST’s Type A and Type B labels classify evaluation methods, not a universal split into random and systematic physics. Components obtained by different methods can still be correlated, and a known correction should be applied rather than hidden inside an enlarged error bar.

Xi=F+B+ϵi,u2(X‾)=σB2+σϵ2NX_i=F+B+\epsilon_i,\qquad u^2(\overline X)=\sigma_B^2+\frac{\sigma_\epsilon^2}{N}
F and Xi are forces. B is a shared zero-mean Gaussian calibration error with known standard deviation σB; independent εi are Gaussian with known standard deviation σε and independent of B. The formula concerns complete-procedure repetitions under that model.↔ Scroll wide equations horizontally.

Propagate covariance into the actual comparison

For a linear combination, uncertainty follows from the covariance matrix, not from indiscriminately adding absolute errors or dividing every component by a square root. Positive correlation increases uncertainty in a sum but decreases uncertainty in a difference with opposite coefficients. Two detectors with shared calibration can therefore agree unusually well while both remain wrong relative to an external standard. A difference test and an absolute calibration test answer different physical questions.

For a nonlinear derived quantity, first-order propagation uses sensitivities evaluated at the estimated inputs. It requires that linearization represent the input uncertainty adequately; near singularities or hard boundaries, numerical propagation or a fuller likelihood may be necessary. Uncertainty in a fitted model is also distinct from an omitted physical effect. A narrow statistical interval cannot absorb an unexamined change in temperature, background coupling or instrument response simply by being labeled a precision result.

u2(c1X1+c2X2)=c12u12+c22u22+2c1c2ρu1u2,F95up=X‾+1.645 u(X‾)u^2(c_1X_1+c_2X_2)=c_1^2u_1^2+c_2^2u_2^2+2c_1c_2\rho u_1u_2,\qquad F_{95}^{\mathrm{up}}=\overline X+1.645\,u(\overline X)
ρ is the correlation coefficient. The final expression is a predeclared one-sided 95% upper confidence construction for an unconstrained Gaussian location parameter with known uncertainty; it is not a two-sided interval or a universal rule for a bounded physical parameter.↔ Scroll wide equations horizontally.

A null result limits an alternative under stated assumptions

If the estimated force is small compared with its standard uncertainty, the data may be consistent with zero without establishing that zero is exactly true. An upper confidence construction states how an analysis procedure covers the parameter over hypothetical repetitions under its model. It is not, by itself, a posterior probability that the force lies below the observed limit. A Bayesian probability statement would additionally require a prior and a specified likelihood.

The chosen alternative matters as well. A bound on a constant positive force does not constrain an oscillating force with unknown phase in the same way, and a search over many frequencies needs its search procedure included in its significance calculation. Physical parameter boundaries can require another interval construction rather than clipping an unconstrained Gaussian interval. Report the estimator, uncertainty components, correlation assumptions and tested signal form so a negative result can be compared or combined without silently changing its meaning.

A null force estimate with a calibration floor

Nine readings estimate a constant force. Independent noise on each reading has known standard deviation 0.90 μN; a shared independent batch-calibration error has known standard deviation 0.40 μN. The measured mean is 0.20 μN. Under the stated Gaussian model, calculate the mean uncertainty, standardized distance from zero and the predeclared one-sided 95% upper confidence value.

  1. Independent reading noise contributes 0.90/√9=0.30 μN to the mean. The shared calibration contribution remains 0.40 μN; it is not divided by three.

  2. Adding independent variance components gives u=√(0.30²+0.40²)=0.50 μN. The observed standardized distance from zero is 0.20/0.50=0.40, which is not strong evidence against a zero mean.

  3. For the specified one-sided Gaussian construction, add 1.645u to the estimator: 0.20+1.645×0.50=1.0225 μN. This coverage calculation assumes the complete noise-and-calibration repetition model and known standard deviations.

The result

The result is 0.20 μN with standard uncertainty 0.50 μN and an upper confidence value about 1.02 μN under the declared construction. Increasing N alone cannot lower the standard uncertainty below 0.40 μN.

Explore the model

Interactive lab

Interactive lab · sampling

Isolate the independent-averaging contribution

Reset and set both controls to Success probability p=0.5 and Independent samples n=4; predict mean 0.5 and sample-mean variance 0.0625. For a fresh comparison, Reset and set both controls to p=0.5 and n=16; predict the same mean and variance 0.015625, displayed approximately 0.01563.

Isolate the independent-averaging contributionExact binomial masses for the mean of n independent Bernoulli trials, compared with normal mass between adjacent half-count boundaries; normal tails outside the finite support remain outside the bars. Playback highlights outcomes, not random samples. The Berry–Esseen bound applies to standardized CDFs, not individual bars or continuity-corrected errors. At p = 0 or 1, normal comparison and that bound are disabled. Normal-CDF evaluation uses a numerical approximation with absolute error below 7.5×10⁻⁸ (at most 1.5×10⁻⁷ per interval, before rounding). Current readings: Mean sample proportion: 0.5; Sample-mean variance: 0.0125; Uniform CDF error bound: ≤ 0.1062. All parameters are adjustable with the labeled controls below.Exact distribution of the mean of 20 independent Bernoulli variables with success probability 0.5; playback highlights outcome 0.00.250.50.75100.0580.1150.1730.23Sample mean · k / nProbability massNormal bin masses are an approximationk = 0 · exact probability = 9.54e-7
Exact binomial massNormal interval massHighlighted outcome / mean
Mean sample proportion
0.5
Sample-mean variance
0.0125
Uniform CDF error bound
≤ 0.1062
t = 0 s

Exact binomial masses for the mean of n independent Bernoulli trials, compared with normal mass between adjacent half-count boundaries; normal tails outside the finite support remain outside the bars. Playback highlights outcomes, not random samples. The Berry–Esseen bound applies to standardized CDFs, not individual bars or continuity-corrected errors. At p = 0 or 1, normal comparison and that bound are disabled. Normal-CDF evaluation uses a numerical approximation with absolute error below 7.5×10⁻⁸ (at most 1.5×10⁻⁷ per interval, before rounding). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe instrument shows exact binomial probabilities for independent Bernoulli sample means. Playback highlights outcomes rather than resampling. It has no common calibration error, Gaussian force likelihood or confidence-limit calculator, so its narrowing cannot represent the full uncertainty budget.

Check your understanding

Under the worked example’s error model, what happens to the standard uncertainty as N tends to infinity?

Try it yourself

Two force estimates each have standard uncertainty 0.40 μN and correlation coefficient ρ=0.50. Their observed difference is 0.80 μN. Calculate the uncertainty of the difference and its standardized size. Compare with the result obtained by incorrectly assuming zero correlation.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The coefficients in a difference are +1 and −1, so the covariance term is subtracted.

Compare with the solution

The difference variance is 0.40²+0.40²−2(0.50)(0.40)(0.40)=0.16 μN². Its standard uncertainty is therefore 0.40 μN and the standardized difference is 0.80/0.40=2. With zero correlation the variance would instead be 0.32 μN², giving uncertainty about 0.566 μN and standardized size about 1.414. Shared error partly cancels from a difference. This does not imply that either estimate has improved absolute calibration, and a significance claim still requires the predeclared comparison and its probability model.

Take it with you

  • Averaging reduces only error components that vary independently across the observations.
  • Covariance changes uncertainty differently for sums and differences.
  • A negative result states a model-dependent constraint rather than proving an exact absence.

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