Coupled resonators and mode splitting
Derive the normal frequencies of two mutually coupled LC loops and distinguish eigenmodes, beating, detuning, and resolvable spectral peaks.
On this page
The question for today
What you’ll understand
- Find symmetric and antisymmetric modes of identical inductively coupled LC loops.
- Relate frequency splitting to mutual inductance with explicit orientation.
- Explain why damping and drive geometry affect observed peaks.
Two resonators can exchange energy without either being directly driven after preparation. Mutual inductance supplies one mechanism: changing current in one loop induces a voltage in the other. The collective modes can be simpler than the motion of either isolated loop. An initial excitation confined to one loop usually excites both modes, and their phase difference produces beating. Spectral splitting and time-domain exchange are related consequences of the same linear equations.
Write a coupling model before naming its strength
Take two identical series LC loops with negligible resistance. Choose current directions and coil dot orientations so that the mutual terms enter both loop equations with positive M. The loop charge coordinates then share an inductance matrix rather than independent inductances. Reciprocity makes that matrix symmetric in this ideal model. Positive magnetic energy requires the magnitude of mutual inductance to be smaller than self-inductance; treating the coupling coefficient as arbitrarily large would produce an unphysical storage matrix.
These equations assume a constant, instantaneous mutual inductance and electrically small loops. They neglect radiative coupling, frequency dependent materials, parasitic capacitance, and additional coil modes. A capacitor connecting two resonators produces a different coupling matrix and need not preserve the same uncoupled frequency shift. Reporting only a coupling number without specifying its definition, topology, sign convention, and units is therefore insufficient. The mode calculation must begin from the selected energy and circuit model.
Symmetry diagonalizes the equations
Adding and subtracting the loop equations separates equal-charge and opposite-charge motion. In the symmetric mode the inductive contribution is L plus M, while in the antisymmetric mode it is L minus M. For positive M the symmetric mode has the lower frequency because the effective inductance is larger. Swapping a coil's orientation changes which coordinate pattern is called symmetric, but the unordered pair of physical frequencies remains the same when the sign of M changes.
For weak coupling, expand the square roots to first order in M divided by L. The separation of angular frequencies is approximately the isolated angular frequency multiplied by the magnitude of that dimensionless ratio. This approximation is not the exact square-root expression, and it loses accuracy for strong coupling. Using ordinary frequencies in one part of a calculation and angular frequencies in another creates an extra factor of two pi, so specify the convention before converting a measured separation into a coupling rate.
Eigenmodes do not guarantee two measured peaks
If only the first capacitor starts charged and both currents initially vanish, its charge is the average of the two modal cosines, while the second charge is their difference. Trigonometric identities expose a fast carrier multiplied by a slow beat factor. The charge amplitude can migrate between loops; a zero charge envelope does not itself imply zero current or uniquely partition the mutual magnetic energy. Unequal bare frequencies bias the modes toward individual resonators, so an excitation may exchange only part of its energy. Dissipation reduces the amplitude available for later returns.
A measured spectrum also depends on which mode the source excites and which coordinate the detector observes. A symmetric drive may fail to excite the antisymmetric mode even when it exists. If damping widths are comparable with splitting, two eigenfrequencies need not appear as two distinct maxima. Conversely, interference can create a sharp dip between broad responses. Distinguish the mathematical eigenvalue problem from the driven transfer function and state the linewidth and excitation assumptions when interpreting an avoided crossing.
Work it through
Two exact collective frequencies
Two identical LC loops have L = 5 H, C = 0.05 F, and mutual inductance M = 3 H with the positive mutual-sign convention. Find the two modal angular frequencies and compare their ordering.
The isolated frequency is . The coupling ratio M/L = 0.6 is too large for a reliable first-order weak-coupling estimate.
The symmetric mode uses L + M = 8 H, giving .
The antisymmetric mode uses L − M = 2 H, giving . Both effective inductances remain positive.
The symmetric mode is at 1.58 rad/s and the antisymmetric mode at 3.16 rad/s. Positive mutual inductance lowers the symmetric frequency and raises the antisymmetric frequency.
The living notebook
Explore the model
Interactive lab · waves
Inspect equal-frequency modal superposition
Reset and set BOTH Phase difference to 0 degrees and Amplitude ratio to 1; predict reinforcement. Then Reset and set BOTH Phase difference to 180 degrees and Amplitude ratio to 1; predict cancellation. The lab adds equal fixed-frequency waves traveling in the same direction. It illustrates phase addition only and cannot produce the unequal-frequency beating or coupled-circuit dynamics derived here.
- Sum at x = 0
- 0.866
- Resultant amplitude
- 1.732
- Phase difference
- 60°
Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forRelative phase controls superposition, while beating additionally requires distinct temporal frequencies.
Pause & reason
Check your understanding
Your turn
Try it yourself
Identical loops have isolated angular frequency 100 rad/s and small positive M/L = 0.02. Estimate the splitting and the first time the slow charge envelope in the initially excited loop reaches zero.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use the first-order splitting and the cosine envelope at half the angular-frequency difference.
Compare with the solution
The estimated separation is . The first-loop charge contains the envelope . Its first zero occurs when , hence . This is a weak-coupling envelope estimate for identical lossless resonators. It is not the fast oscillation period, and appreciable damping could greatly reduce the observable transfer.
Keep the idea
Take it with you
- A coupling model specifies both the storage matrix and its allowed parameter range.
- Collective frequencies follow from symmetric and antisymmetric coordinates for identical loops.
- Damping, detuning, and drive symmetry affect whether mode splitting is visible.
Read further
Original sources and deeper explanations to follow at your own pace.
Optional progress, saved in this browser when available. Revisit any lesson at any time.
Lesson not marked complete.