Lumped elements and Kirchhoff laws
Identify when fields can be compressed into circuit variables and apply node and loop balances without discarding induction or charge storage.
On this page
The question for today
What you’ll understand
- Assess electrical size using propagation delay and signal timescale.
- Derive node and loop balances from local conservation laws.
- Separate intended element storage from unwanted interconnect effects.
A circuit diagram compresses a spatial electromagnetic system into a few voltages and currents. This is useful because a small device can store substantial electric or magnetic energy while propagation across its connecting wires is negligible on the timescale being studied. The approximation concerns electrical size, material behavior, and geometry together. Calling a component a capacitor does not guarantee that it remains an ideal capacitor at every frequency.
Small compared with which timescale?
Let the largest relevant interconnect dimension be d and the propagation speed along its environment be v. A sinusoidal signal accumulates a phase of order angular frequency times travel time across that dimension. Lumped modeling requires this phase to be small wherever one voltage or current is assigned to an extended object. For a pulse, use the fastest significant rise time rather than its repetition period; a slow clock can still have electrically long connections.
Electrical smallness is necessary but does not remove every parasitic effect. A tightly wound coil can have appreciable capacitance between turns even while its outer dimensions are small. A narrow wire can contribute inductance that matters relative to a small intended inductance. The useful test is whether ignored storage, radiation, delay, and loss are small compared with the quantities retained at the accuracy required. There is no universal dimension in centimetres that guarantees success.
A node has a charge balance
Integrating charge continuity over a small junction says that inward conduction currents increase the charge stored there. The usual Kirchhoff current law replaces this charge accumulation by explicit capacitive branches, leaving an ideal node with negligible unmodeled storage. Thus current through a capacitor branch is included in circuit accounting even though conduction electrons do not cross its dielectric. The capacitor terminal current records charging of its plates, not a violation of conservation.
A circuit voltage is a consistently defined difference between terminals. In an electroquasistatic region, it can be associated with a nearly path independent potential difference. An inductive loop requires more care because Faraday induction creates a circulating electric field. Assign induced electromotive force to an inductor, transformer, or explicit source; then use a loop balance with that contribution included. A bare statement that every physical electric-field loop integral vanishes would contradict Maxwell's equations.
Storage belongs somewhere in the model
For linear ideal elements, a capacitor stores electric energy and an inductor stores magnetic energy. Their constitutive laws introduce time derivatives, so lumped does not mean static. A resonant circuit can alternate rapidly between electric and magnetic storage while remaining electrically small. Its resonance wavelength can greatly exceed its dimensions because the element geometry concentrates fields. A resistor instead converts electrical energy into other forms and need not carry a storage variable in the ideal model.
Choose current entering the positive terminal so that voltage times current is absorbed power. This passive sign convention makes a resistor's power positive and gives storage rates directly for constant capacitance and inductance. If a supposed ideal wire has a measurable phase difference between its ends, promote it into an element or transmission line. Improving a circuit model usually means assigning omitted field effects explicitly, rather than deciding that charge conservation or induction has stopped working.
Work it through
Check a short board connection
A 2.0 cm connection carries a 10 MHz sinusoid in an environment with propagation speed 2.0 × 10⁸ m/s. Find its travel time and phase delay, then assess a one-node approximation.
The travel time is distance divided by speed: . This is 0.10 ns.
The angular frequency is . Therefore radians, about 0.36 degrees.
The phase is much smaller than one radian. Treating this connection as one node is reasonable for percent-scale phase accuracy, provided its resistance, inductance, capacitance, and return path are also negligible for this circuit.
The delay is 0.10 ns and the phase change is about 0.0063 rad. The delay criterion supports a lumped connection at 10 MHz.
The living notebook
Explore the model
Interactive lab · vectors
A phase angle can be small or appreciable
For each fresh comparison Reset and set BOTH controls. First set Angle to 1 degree and Magnitude to 1; predict a small y projection. Then Reset, set Angle to 60 degrees and Magnitude to 1, and compare the projections. This static vector illustrates phase geometry only; it does not calculate wire delay or electromagnetic fields.
- x component
- 1.393
- y component
- 0.975
- Magnitude
- 1.7
Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA small phase permits nearly common values across a connection, but geometric projections alone do not validate a circuit model.
Pause & reason
Check your understanding
Your turn
Try it yourself
A junction receives 3 mA and sends 1 mA into a resistor. The remaining current charges an ideal 2 μF capacitor. Find the capacitor voltage change over 4 ms, assuming the currents remain constant.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Apply the node balance first, then integrate the capacitor current law with the initial voltage left symbolic.
Compare with the solution
The capacitor receives . Its slope is . Over 0.004 s the voltage rises by 4 V. The final voltage is its initial value plus 4 V; no initial voltage was specified. The ideal node does not accumulate charge because the explicit capacitor branch accounts for it.
Keep the idea
Take it with you
- Electrical size depends on propagation time relative to the fastest relevant signal change.
- Kirchhoff balances retain charge conservation and induction through explicit elements.
- A lumped resonator can be dynamic while its interconnections remain electrically short.
Read further
Original sources and deeper explanations to follow at your own pace.
Optional progress, saved in this browser when available. Revisit any lesson at any time.
Lesson not marked complete.