advanced24 min studyLesson 151 in Physics

Inertia tensors and principal axes

Calculate rotational response from mass distribution, identify principal directions, and distinguish angular momentum from angular velocity.

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What you’ll understand

  • Construct a symmetric inertia tensor about a stated origin.
  • Find principal axes and interpret the associated moments.
  • Compute angular momentum and kinetic energy for a nonprincipal rotation.

A wheel mounted on its axle makes rotational inertia look like a single number. A freely turning object asks a harder question: which axis, through which point, and in which direction? The inertia tensor answers these questions together. This lesson treats an ideal rigid body and measures positions from its center of mass, separating translation from rotation before calculating any moment.

Build the tensor from distances to axes

A point mass contributes to rotational inertia according to its distance perpendicular to the rotation axis. Mass lying on that axis contributes nothing to its moment, even when it lies far from the chosen origin. For many masses, add these contributions. The diagonal entries therefore contain sums of two squared coordinates; the off-diagonal entries contain negative products of different coordinates.

The tensor is symmetric because interchanging the coordinate labels leaves every mass contribution unchanged. It is positive semidefinite: rotational kinetic energy cannot be negative. An ideal collection confined to a line can have a zero moment about that line. A three-dimensional body with mass distributed away from every line through the origin instead has strictly positive principal moments.

Iij=∑ama(ra2δij−rairaj),L=IωI_{ij}=\sum_a m_a\left(r_a^2\delta_{ij}-r_{ai}r_{aj}\right),\qquad \mathbf L=I\boldsymbol\omega
Positions are measured from the chosen rotation origin. For a free body, use its center of mass; all vector components must be expressed in the same orthonormal frame.↔ Scroll wide equations horizontally.

Principal axes remove coordinate mixing

A real symmetric matrix has an orthonormal eigenbasis. Choosing those directions as body axes makes the inertia tensor diagonal. The associated eigenvalues are the principal moments. This is a choice of coordinates attached to the object, not an operation that changes the object. Degenerate moments allow multiple equally valid principal directions within the degenerate eigenspace.

Along a principal direction, angular momentum is parallel to angular velocity. Along a general direction, multiplying different components by different moments usually changes the direction. A constrained rotor can maintain such a rotation only when its bearings provide the necessary torque. A free body can instead change its orientation and angular velocity while preserving its inertial angular momentum.

Ibody=diag⁡(I1,I2,I3),Trot=12∑i=13Iiωi2I_{\rm body}=\operatorname{diag}(I_1,I_2,I_3),\qquad T_{\rm rot}=\frac12\sum_{i=1}^3 I_i\omega_i^2
The principal moments depend on mass distribution and origin. This expression is the rotational energy about the center of mass, excluding translational kinetic energy.↔ Scroll wide equations horizontally.

Check origins, units, and physical meaning

Shifting the origin changes inertia, even though changing only the orientation of axes does not change its eigenvalues. The parallel-axis theorem adds a tensor determined by the displacement from the center of mass. Never add a scalar shift independently to all diagonal entries without considering which direction the displacement points. The axis parallel to that displacement receives no added moment.

Use the vector lab to inspect one direction before doing tensor arithmetic. Predict that a unit vector at forty-five degrees has equal positive projections, then check it using the angle and magnitude controls. Multiplying those projections by unequal principal moments would tilt angular momentum toward the larger moment. The lab shows projections only; it neither multiplies a tensor nor simulates a rotating body.

Momentum that points away from the spin direction

A body has principal moments 2, 3, and 4 kilogram square meters. Its body-frame angular velocity is (1, 2, 0) radians per second. Find its angular momentum, rotational energy, and whether the two vectors are parallel.

  1. Multiply each principal component separately: the angular momentum is (2, 6, 0) kilogram square meters per second. Do not multiply all components by the same averaged moment.

  2. Compute the energy as one half of the sum 2 times 1 squared plus 3 times 2 squared. The two contributions sum to fourteen, giving seven joules.

  3. Compare component ratios: the momentum ratio of second to first component is three, whereas the angular-velocity ratio is two. The directions therefore differ despite both vectors lying in the same plane.

The result

The angular momentum is (2, 6, 0) and the energy is 7 joules. Nonparallel momentum and angular velocity reflect anisotropic inertia, not a violation of angular-momentum conservation.

Explore the model

Interactive lab

Interactive lab · vectors

Directions before tensor multiplication

Predict equal projections at 45 degrees with magnitude 1, then change the angle and compare the two components. Apply unequal inertia factors on paper.

Directions before tensor multiplicationPlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe model displays one planar vector and its projections. It does not compute an inertia tensor or a rigid-body trajectory.

Check your understanding

A symmetric inertia tensor has three distinct principal moments. Which statement is correct?

Try it yourself

Two point masses of one kilogram each sit at (1, 0, 0) and (-1, 0, 0) meters. Determine the three principal moments and the energy for angular velocity (0, 0, 3).

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

For each mass, the moment about the x axis uses y squared plus z squared. The other two moments use its nonzero x coordinate.

Compare with the solution

The tensor is diagonal with moments (0, 2, 2) kilogram square meters. Rotation about z has energy one half times two times nine, or nine joules. The zero x moment is a consequence of the ideal line-shaped mass distribution; a rod of finite thickness would have a small positive axial moment.

Take it with you

  • Specify an origin and a frame before interpreting any inertia component.
  • Principal axes diagonalize a symmetric tensor without changing the underlying body.
  • Anisotropic inertia allows angular momentum and angular velocity to point in different directions.

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