advanced35 min studyLesson 514 in Physics

Derive diode current and diagnose recombination

Obtain the diffusion diode law and identify which physical assumptions an observed ideality factor can test.

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What you’ll understand

  • Connect boundary injection to minority-carrier diffusion.
  • State the assumptions behind a long-base diode law.
  • Distinguish diffusion, depletion recombination, and misleading slope diagnoses.

Forward bias lowers a junction barrier and injects minority carriers into the opposite neutral regions. Their subsequent diffusion and recombination determine the current delivered by the contacts. This mechanism explains an exponential current without treating the depletion region as a simple resistor. Recombination inside the depletion layer adds another contribution with a different bias dependence, while high injection and series resistance can produce similar measured slopes for entirely different reasons.

Translate barrier lowering into a boundary condition

In a nondegenerate p region, equilibrium minority electrons have density np0=ni2/NAn_{p0}=n_i^2/N_A for complete ionization and strong p-type doping. A forward junction voltage V sets their density at the depletion edge to np0eV/VTn_{p0}e^{V/V_T} under the ideal injection assumptions. The excess above equilibrium is therefore proportional to eV/VT−1e^{V/V_T}-1. Holes injected into the n region obey the corresponding relation. Applied terminal voltage equals this junction voltage only when other voltage drops are negligible.

In a neutral region with low-level injection, the majority density stays close to its equilibrium value. A linear minority lifetime approximation then gives a steady diffusion equation for excess carriers. Its long-base solution decays exponentially away from the depletion edge, with diffusion length equal to the square root of diffusion coefficient times lifetime. Taking the derivative at the edge produces minority diffusion current. The electron and hole edge contributions add because their conventional forward currents point in the same terminal direction.

I=Is(eV/VT−1),Is=qAni2(DnLnNA+DpLpND),Ln,p=Dn,pτn,pI=I_s\left(e^{V/V_T}-1\right),\qquad I_s=qA n_i^2\left(\frac{D_n}{L_nN_A}+\frac{D_p}{L_pN_D}\right),\qquad L_{n,p}=\sqrt{D_{n,p}\tau_{n,p}}
This long-base, low-injection homojunction law assumes nondegenerate carriers, isothermal operation, negligible depletion-region recombination, and negligible series voltage drop. A is area, τ denotes minority lifetime, and the neutral widths must greatly exceed their diffusion lengths. I_s is in amperes.↔ Scroll wide equations horizontally.

Locate the recombination mechanism

A defect level can capture an electron and a hole sequentially, enabling Shockley–Read–Hall recombination without direct band-to-band emission. The net rate vanishes in thermal equilibrium because capture and emission balance. Away from equilibrium its numerator measures the departure of the electron-hole product from the intrinsic square, while the denominator contains carrier densities, trap energy through n1,p1n_1,p_1, and capture-lifetime parameters. It is not generally proportional to either carrier density with one universal lifetime.

For a roughly midgap trap with comparable capture times, depletion-region forward recombination is strongest near the location where electron and hole populations are comparable. Their local growth can yield a current approximately proportional to eV/(2VT)e^{V/(2V_T)} over an appropriate bias range. This gives an ideality factor near two. Recombination in a neutral region can still support an ideality-one diffusion current, so the phrase recombination current alone does not determine an ideality factor. Spatial location and injection regime matter.

USRH=np−ni2τp(n+n1)+τn(p+p1),nid=1VTdVdln⁡Ifor forward I>0U_{\rm SRH}=\frac{np-n_i^2}{\tau_p(n+n_1)+\tau_n(p+p_1)},\qquad n_{\rm id}=\frac1{V_T}\frac{dV}{d\ln I}\quad\text{for forward }I>0
U_SRH is net recombination per volume per second in the single-trap model; n₁ and p₁ encode trap energy. The differential ideality definition is useful where forward current dominates offsets. An approximate factor two from depletion recombination requires additional trap and bias assumptions, not just the existence of defects.↔ Scroll wide equations horizontally.

Treat slope as evidence rather than a unique label

In the forward exponential regime, ideality one gives a voltage increment VTln⁡10V_T\ln10 for a decade increase in current. A nearly constant slope near twice that value suggests a different transport regime, but does not prove a unique defect mechanism. High injection can also change the exponential scale. At large current, a series-resistance drop increases terminal voltage without the same increase in junction bias, producing an apparent ideality factor that grows with current rather than remaining a pure exponential constant.

Reverse current likewise need not equal a perfectly constant saturation value. Generation in a widening depletion region, surface leakage, tunneling, and avalanche can all change it. The elementary diode law is valuable precisely because its assumptions are explicit and its departures can be diagnosed. Temperature dependence, geometry, and independent lifetime measurements help distinguish mechanisms that a single current-voltage trace cannot identify. Current conservation still holds throughout the device even as electron current converts into hole current through recombination.

Current and local differential resistance

Use an ideal long-base diode with Is=1.0 nAI_s=1.0\,\mathrm{nA} and VT=0.025 VV_T=0.025\,\mathrm V. At V=VTln⁡1001V=V_T\ln1001, find the current and differential resistance. Use ln⁡1001=6.909\ln1001=6.909 and estimate the voltage needed for a decade increase when the forward current greatly exceeds saturation.

  1. The applied junction voltage is 0.025(6.909)=0.1727 V0.025(6.909)=0.1727\,\mathrm V. Since the exponential is exactly 1001 at the stated bias, the full law gives I=(1 nA)(1001−1)=1.000 μAI=(1\,\mathrm{nA})(1001-1)=1.000\,\mu\mathrm A.

  2. Differentiate before approximating: dI/dV=(I+Is)/VTdI/dV=(I+I_s)/V_T. Thus rd=dV/dI=0.025/(1.001×10−6)=2.498×104 Ωr_d=dV/dI=0.025/(1.001\times10^{-6})=2.498\times10^4\,\Omega, about 25.0 kΩ25.0\,\mathrm{k\Omega}. This is a local slope, not the static ratio V/I.

  3. Far above saturation, a tenfold current ratio needs ΔV=VTln⁡10=0.0576 V\Delta V=V_T\ln10=0.0576\,\mathrm V. The offset minus one is negligible for this slope estimate, but was retained when computing the exact example current.

The result

The current is 1.000 μA and differential resistance is about 25.0 kΩ at 0.1727 V. In the diffusion-dominated forward limit, the slope is 57.6 mV per decade at the stated temperature.

Explore the model

Interactive lab

Interactive lab · markov

Distinguish trap occupancy from relaxation speed

Reset and set both controls to p = 0.2 and q = 0.2; predict stationary state-1 probability 0.5 and first-Step probability 0.2. Reset and set both controls to p = 0.4 and q = 0.4; predict the same stationary probability but first-Step probability 0.4 and faster approach. This exact two-state chain starts in state 0 and illustrates occupancy relaxation; it has no electron-hole densities, SRH rate, or diode current.

Distinguish trap occupancy from relaxation speedExact finite-step probabilities for a two-state chain starting in state 0, not sampled trajectories. Playback advances two transitions per second. When p = q = 0 every distribution is stationary; when p = q = 1 the chain alternates forever. A single zero transition creates an absorbing state. Current readings: P(state 1) at step 0: 0%; Stationary P(state 1): 60%; Chain behavior: Monotone convergence. All parameters are adjustable with the labeled controls below.Two-state Markov distribution after 0 steps: state zero probability 1, state one probability 0.Initial distribution (1, 0) · step 0p = 0.3q = 0.201100%0%1−p1−qP(0)P(1)Monotone convergence
P(state 0)P(state 1)Stationary distribution
P(state 1) at step 0
0%
Stationary P(state 1)
60%
Chain behavior
Monotone convergence
t = 0 s

Exact finite-step probabilities for a two-state chain starting in state 0, not sampled trajectories. Playback advances two transitions per second. When p = q = 0 every distribution is stationary; when p = q = 1 the chain alternates forever. A single zero transition creates an absorbing state. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forAn unchanged stationary occupancy does not imply an unchanged relaxation time; the chain is only a trap-occupancy analogy.

Check your understanding

What can a forward ideality factor near two establish by itself?

Try it yourself

Consider the explicitly assumed phenomenological law I=IR0[eV/(2VT)−1]I=I_{R0}[e^{V/(2V_T)}-1], with IR0=1 nAI_{R0}=1\,\mathrm{nA} and VT=0.025 VV_T=0.025\,\mathrm V. Find I at V=2VTln⁡11V=2V_T\ln11, then after raising V by 2VTln⁡22V_T\ln2. Explain why the second current is not exactly twice the first.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The voltage increment doubles the exponential, rather than doubling the exponential minus one.

Compare with the solution

Initially I=1(11−1)=10 nAI=1(11-1)=10\,\mathrm{nA}. The extra voltage is 0.050ln⁡2=0.0347 V0.050\ln2=0.0347\,\mathrm V, making the exponential 22 and the current 21 nA21\,\mathrm{nA}. Thus it is the quantity I+IR0I+I_{R0} that doubles exactly. In the large-forward-current limit the offset becomes negligible and the model gives 115 mV per decade. This specified ideality-two fit is an illustrative law, not an exact general solution of spatially varying SRH recombination.

Take it with you

  • Boundary injection and minority diffusion produce the ideal diode law.
  • Depletion recombination can change the exponent under specific trap and bias assumptions.
  • Ideality factor is a diagnostic slope, not a unique microscopic identification.

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