advanced36 min studyLesson 520 in Physics

Use partition noise to learn beyond conductance

Calculate a Fano factor from transmission eigenvalues and distinguish shot noise from thermal noise and interaction effects.

On this page

What you’ll understand

  • Compute the conductance and partition-noise transmission sums.
  • Apply a declared noise-spectrum convention with correct units.
  • Explain how equal conductances can conceal different channel distributions.

Average conductance measures how much charge is transmitted, but not how regularly it arrives. A partially transmitting channel partitions occupied incoming states into transmitted and reflected outcomes, creating current fluctuations even at zero temperature under bias. The resulting shot noise depends on a different combination of transmission probabilities than conductance does. Measuring both can therefore distinguish conductors with the same average current while still leaving some ambiguity about their complete microscopic channel structure.

Separate incoming occupation from partition randomness

For noninteracting elastic transport at zero temperature, occupied incoming states inside the bias window provide the available attempts. Fermi statistics suppress the occupation fluctuations that an unconstrained classical Poisson arrival model would assign to these filled states. A channel with transmission T still randomly partitions each attempt, giving a variance proportional to T(1−T)T(1-T). A closed channel contributes neither current nor partition noise. A perfectly transmitting channel carries current but has no zero-temperature partition noise in this model.

For spin-degenerate orbital channels, conductance is G0∑nTnG_0\sum_nT_n with G0=2e2/hG_0=2e^2/h. Noise weights the same channels by Tn(1−Tn)T_n(1-T_n), so spin must follow the same counting convention in both sums. If transmissions mix modes, the relevant numbers are the eigenvalues of the transmission-probability matrix, rather than arbitrary diagonal amplitudes in a chosen basis. The ratio of these two sums is the Fano factor, a dimensionless measure of noise relative to the Poisson reference.

I=GV,G=2e2h∑nTn,F=∑nTn(1−Tn)∑nTn,SI=2e∣I∣FI=GV,\qquad G=\frac{2e^2}{h}\sum_nT_n,\qquad F=\frac{\sum_nT_n(1-T_n)}{\sum_nT_n},\qquad S_I=2e|I|F
These low-frequency zero-temperature formulas assume elastic noninteracting transport and transmissions approximately constant across the bias window. The orbital sum includes spin through the prefactor two. S_I uses the one-sided convention in A²/Hz; the Poisson reference is 2e|I|. F is undefined when every channel is closed and I = 0.↔ Scroll wide equations horizontally.

Check the temperature and spectral convention

A noise spectral density is not a variance in amperes squared until integrated over a measurement bandwidth with its specified convention. Here a one-sided low-frequency spectrum is used, so a Poisson stream of elementary charges has SI=2e∣I∣S_I=2e|I|. Using a two-sided convention changes factors of two. A quoted numerical noise value without its bandwidth or spectral units can therefore be misleading even when its current and Fano factor are correct. This convention should also match the thermal-noise formula used for comparison.

At finite temperature, a perfectly transmitting conductor still has equilibrium Johnson–Nyquist noise 4kBTG4k_BTG in the classical low-frequency one-sided limit. The simple zero-temperature partition expression is most useful when the bias energy greatly exceeds thermal energy, with negligible heating and otherwise valid scattering assumptions. In the crossover region, the full Fermi-occupation integrals combine thermal and partition contributions. Subtracting an equilibrium background and calling the remainder excess noise does not make every finite-temperature expression equal to its zero-temperature limit.

SIeq=4kBTG,e∣V∣≫kBTfor the shot-dominated limit,0≤F≤1for noninteracting partition noiseS_I^{\rm eq}=4k_BTG,\qquad e|V|\gg k_BT\quad\text{for the shot-dominated limit},\qquad 0\le F\le1\quad\text{for noninteracting partition noise}
The thermal expression assumes measurement angular frequency much smaller than k_BT/ħ and equilibrium linear conductance G. The F bound applies to the stated independent elastic-channel model with nonzero current, since each transmission lies in [0,1]. It is not a universal bound for interacting, avalanche, or correlated charge transport.↔ Scroll wide equations horizontally.

Infer channel information without overclaiming uniqueness

Two channels with transmissions 0.8 and 0.2 have the same conductance sum as channels with transmissions one and zero. The former partition both streams and make noise; the latter transmit one stream deterministically and reject the other. Thus conductance alone cannot distinguish their channel composition. Noise supplies a second moment-like constraint, but many larger channel sets can still share both sums. Recovering every transmission eigenvalue generally requires additional information, assumptions, or higher current cumulants.

When all transmissions are small, T(1−T)T(1-T) is approximately T, giving nearly Poissonian F near one for weak independent tunneling. Strongly transmitting channels suppress noise. Interactions and correlated transfer can produce super-Poissonian noise, so an observed F above one is evidence against this simple partition model rather than a violation of charge quantization. Coulomb blockade, dynamical trapping, and avalanche processes each require their own transport description; the elementary formula cannot identify one uniquely from a single excess-noise ratio.

Equal conductance does not mean equal noise

At zero temperature take two spin-degenerate orbital transmissions T1=0.8T_1=0.8 and T2=0.2T_2=0.2, G0=77.5 μSG_0=77.5\,\mu\mathrm S, and bias V=1.0 mVV=1.0\,\mathrm{mV}. Use e=1.6×10−19 Ce=1.6\times10^{-19}\,\mathrm C. Find current, Fano factor, and one-sided shot-noise density. Compare with channels 1 and 0 at the same bias.

  1. The transmission sum is one, so G=77.5 μSG=77.5\,\mu\mathrm S and I=GV=77.5 nAI=GV=77.5\,\mathrm{nA}. The supplied G₀ already includes the two equivalent spins of each orbital channel.

  2. The partition sum is 0.8(0.2)+0.2(0.8)=0.320.8(0.2)+0.2(0.8)=0.32. Dividing by the transmission sum gives F=0.32F=0.32, below the independent Poisson limit because these are partly open fermionic channels.

  3. The noise is SI=2(1.6×10−19)(77.5×10−9)(0.32)=7.94×10−27 A2/HzS_I=2(1.6\times10^{-19})(77.5\times10^{-9})(0.32)=7.94\times10^{-27}\,\mathrm{A^2/Hz}. Channels one and zero have the same transmission sum and current, but their partition sum is zero, hence no shot noise in this zero-temperature model.

The result

The device carries 77.5 nA with F = 0.32 and noise density 7.94 × 10⁻²⁷ A²/Hz. A fully open channel paired with a closed one carries the same current with zero partition noise, demonstrating the extra information in a fluctuation measurement.

Explore the model

Interactive lab

Interactive lab · probability

Compare partition variance with deterministic transmission

Reset and set both controls to success probability p = 0.5 and trials n = 20; predict mean 10 and variance 5, so variance divided by mean is 0.5. Reset and set both controls to p = 1 and n = 20; predict mean 20 and variance 0. These exact binomial bars illustrate partition statistics, not random resampling, a Fermi reservoir, or a calibrated current-noise spectrum in A²/Hz.

Compare partition variance with deterministic transmissionThese are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Current readings: Mean · np: 5; Variance · np(1−p): 2.5; Total probability: 1. All parameters are adjustable with the labeled controls below.03581000.070.150.220.3Successes kP(X = k)k = 0 · P = 9.77e-4
Exact probabilityHighlighted outcomeMean np
Mean · np
5
Variance · np(1−p)
2.5
Total probability
1
t = 0 s

These are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forPerfect transmission can carry a nonzero mean count with no partition variance; thermal and interaction noise require additional physics.

Check your understanding

Two zero-temperature conductors have orbital transmissions (0.8, 0.2) and (1, 0), with identical spin conventions. What differs in the independent elastic model?

Try it yourself

Three spin-degenerate orbital channels have transmissions 1, 0.5, and 0.5 and carry I=200 nAI=200\,\mathrm{nA} in the shot-dominated low-frequency regime. Find their conductance in units of G0G_0, Fano factor, and one-sided partition noise. Compare with transmissions 1, 1, and 0 at the same current, neglecting thermal noise.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Compute the transmission sum and partition sum separately. A fully open channel contributes to only the first sum.

Compare with the solution

The transmission sum is two, giving G=2G0G=2G_0. The partition sum is 0+0.25+0.25=0.500+0.25+0.25=0.50, hence F=0.25F=0.25. The noise is SI=2(1.6×10−19)(200×10−9)(0.25)=1.60×10−26 A2/HzS_I=2(1.6\times10^{-19})(200\times10^{-9})(0.25)=1.60\times10^{-26}\,\mathrm{A^2/Hz}. Transmissions (1,1,0) have the same conductance but zero partition sum, giving zero shot noise in this approximation. Neither comparison predicts zero finite-temperature equilibrium noise, and the noninteracting Fano bound does not exclude super-Poissonian noise in other transport regimes.

Take it with you

  • Partition noise weights channels by T(1 − T), while conductance weights them by T.
  • Spectral convention and temperature determine the correct numerical noise formula.
  • Noise adds channel information but does not generally identify a unique microscopic transmission set.

Read further

Original sources and deeper explanations to follow at your own pace.

Optional progress, saved in this browser when available. Revisit any lesson at any time.

Lesson not marked complete.