research29 min studyLesson 787 in Physics

F- and D-flat vacuum moduli

Solve zero-potential conditions before quotienting gauge orbits and identify which continuous vacuum parameters survive an added superpotential.

On this page

What you’ll understand

  • Apply F and D flatness as simultaneous conditions.
  • Describe gauge-inequivalent vacua using invariant coordinates.
  • Count generic moduli and explain how interactions can lift them.

A vanishing supersymmetric potential can occur along a continuous set of field configurations. Physical vacuum parameters are the gauge-inequivalent points in that set, not every scalar value appearing in a convenient gauge. These parameters form a vacuum moduli space when they label genuinely degenerate vacua. We will analyze a canonical Abelian toy theory whose invariant coordinate is elementary, then add a superpotential that fixes it. The exercise separates flatness, gauge redundancy, and massless excitations instead of treating them as interchangeable.

Zero potential imposes several equations at once

For rigid supersymmetry with positive canonical kinetic metrics, the static potential is a sum of auxiliary absolute squares. A zero-energy scalar background must therefore set every superpotential derivative and every gauge moment map to zero. It is insufficient for different positive contributions merely to balance; they cannot cancel one another. These conditions describe constant bosonic vacua, not general space-dependent solutions that may also carry gradient energy or topological charges. The existence of a finite normalizable quantum vacuum is a further question when the classical set is noncompact.

Take a vectorlike U(1) pair ϕ+\phi_+ and ϕ−\phi_- of charges plus and minus one, nonzero gauge coupling, no FI term, and initially no superpotential. F flatness is automatic, and D flatness requires equal magnitudes. The family can be written as a common nonnegative radius r with two phases. A gauge transformation shifts those phases oppositely, leaving their sum unchanged. Thus not all apparent phase freedom describes independent vacua. Eliminating the redundant phase is as necessary as imposing the zero-potential equation.

V=∑i∣Wi∣2+12∑a(Da)2,Wi=0, Da=0,∣ϕ+∣=∣ϕ−∣,M=ϕ+ϕ−V=\sum_i|W_i|^2+\frac12\sum_a(D^a)^2,\qquad W_i=0,\ D^a=0,\qquad |\phi_+|=|\phi_-|,\qquad M=\phi_+\phi_-
This expression assumes rigid supersymmetry and canonical matter metrics. M is a gauge-invariant scalar coordinate with energy-squared units. For a noncanonical positive Kähler metric, the inverse metric changes the F potential but not the zero-derivative condition.↔ Scroll wide equations horizontally.

Quotient gauge orbits rather than counting them

At a generic nonzero radius, two complex fields have four real parameters. The real D equation removes one, and the one-dimensional compact gauge orbit removes another. Two real parameters remain, organized by the complex invariant M. Its magnitude is r squared and its phase is the sum of the field phases. Gauge fixing one scalar real does not fix that sum; it transfers the remaining phase into the other scalar. Confusing a gauge choice with a physical restriction would incorrectly remove half the moduli.

At the origin the gauge symmetry is unbroken, whereas at a generic point the charged expectation values Higgs the Abelian vector. The simple generic dimension count assumes a freely acting orbit and should be interpreted carefully where the stabilizer changes. Extra light gauge degrees of freedom at such loci can make the effective low-energy description different. A moduli coordinate describes gauge-invariant vacuum information; it does not count every massless field at every point. The induced kinetic metric is additional physical data, not fixed by knowing only the coordinate's algebraic definition.

(ϕ+,ϕ−)↦(eiαϕ+,e−iαϕ−),dim⁡RMgeneric=4−1−1=2,M↦M(\phi_+,\phi_-)\mapsto(e^{i\alpha}\phi_+,e^{-i\alpha}\phi_-),\qquad \dim_{\mathbb R}\mathcal M_{\mathrm{generic}}=4-1-1=2,\qquad M\mapsto M
The subtraction removes one real D constraint and one real compact gauge orbit at generic nonzero configurations. The holomorphic invariant is unchanged, while its phase remains a physical vacuum parameter in the model without a superpotential.↔ Scroll wide equations horizontally.

A superpotential can lift a flat direction

Add a neutral chiral field X and W=hX(Φ+Φ−−v2)W=hX(\Phi_+\Phi_--v^2), with nonzero h and positive real v. The X equation fixes M to v squared. The charged-field equations require X times each oppositely charged field to vanish. Since their product is nonzero, X must vanish. D flatness then fixes both charged magnitudes to v, while the gauge quotient removes the remaining opposite phase. The continuous invariant M is no longer a modulus: one isolated gauge-inequivalent supersymmetric classical vacuum remains.

This example shows why a D-flat direction does not guarantee a flat direction of the full theory. Superpotential interactions can fix it, and quantum effects can modify some classical moduli spaces or generate effective superpotentials. Conversely, a genuinely protected family need not have an uncorrected kinetic metric. Low-energy descriptions must therefore distinguish the existence of vacua, their invariant coordinates, and the geometry controlling fluctuations. The count just derived belongs to a specified anomaly-free toy model and its classical regime; it is not a general prediction of a realistic supersymmetric matter sector.

An invariant phase survives gauge fixing

In the model with no superpotential, set ϕ+=3eiπ/3 GeV\phi_+=3e^{i\pi/3}\,\mathrm{GeV} and ϕ−=3eiπ/6 GeV\phi_-=3e^{i\pi/6}\,\mathrm{GeV}. Check flatness, calculate M, and choose a gauge making the positive-charge scalar real.

  1. Both magnitudes are three GeV, so their squared difference and D vanish. With no superpotential all F values vanish as well, giving zero classical static potential.

  2. The invariant is M=9ei(π/3+π/6) GeV2=9i GeV2M=9e^{i(\pi/3+\pi/6)}\,\mathrm{GeV^2}=9i\,\mathrm{GeV^2}. Its phase is the sum, not the difference, of the field phases.

  3. Choose gauge parameter α=−π/3\alpha=-\pi/3. The transformed fields are three GeV and three i GeV, respectively. Their product remains nine i GeV squared; gauge fixing did not erase the physical invariant phase.

The result

The configuration is F and D flat, with M = 9i GeV². A real-positive first field is compatible with an imaginary second field and the same invariant vacuum coordinate.

Explore the model

Interactive lab

Interactive lab · vectors

An invariant complex coordinate can have a physical phase

Reset and set BOTH Angle = 0° and Magnitude = 2; predict components (2, 0). For a fresh comparison, Reset and set Angle = 90° and Magnitude = 2; predict (0, 2). Inspect the components while the magnitude stays fixed.

An invariant complex coordinate can have a physical phasePlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forInterpreting this vector as a schematic invariant M changes its physical complex phase. This is not the opposite-phase gauge transformation, which leaves M fixed. The lab computes no F equations, D quotient, or supersymmetric moduli metric.

Check your understanding

Why does a generic D-flat charged pair without a superpotential leave one complex modulus?

Try it yourself

Add the neutral X and W=hX(Φ+Φ−−v2)W=hX(\Phi_+\Phi_--v^2) with nonzero h and v=2 GeVv=2\,\mathrm{GeV}. Find X, M, and both charged magnitudes in a supersymmetric vacuum. Does the previous continuous M family remain?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Start with the X derivative, then use the charged derivatives and finally the D equation.

Compare with the solution

The X derivative requires M=v2=4 GeV2M=v^2=4\,\mathrm{GeV^2}, so neither charged field is zero. Their own superpotential derivatives then require X to vanish. D flatness gives equal magnitudes, and their product fixes each magnitude to two GeV. The product phase is zero; the remaining opposite phases are gauge equivalent. Hence the former complex M family is lifted to one gauge-inequivalent classical supersymmetric vacuum under these nonzero-parameter assumptions.

Take it with you

  • F and D flatness must hold simultaneously for zero rigid supersymmetric potential.
  • Gauge-related scalar backgrounds are one vacuum, while invariant coordinates label distinct vacua.
  • Superpotential interactions can lift a D-flat family without breaking supersymmetry.

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