research29 min studyLesson 783 in Physics

Four-dimensional chiral supermultiplets

Match chiral component transformations and degrees of freedom, then eliminate the auxiliary field without changing the physical particle count.

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What you’ll understand

  • Distinguish off-shell components from on-shell excitations.
  • Identify the role of an auxiliary field in algebra closure.
  • Eliminate a complex auxiliary field with consistent potential signs.

The algebra constrains physical particle multiplets, but a local action is written in fields before their equations of motion are imposed. Those are different counting problems. A four-dimensional chiral multiplet contains a complex scalar, a Weyl fermion, and an auxiliary complex scalar. The last field completes the off-shell transformation algebra while adding no propagating particle. We continue the mostly-minus metric, epsilon conventions, Grassmann ordering, and factor-two four-dimensional supercharge normalization established in the first lesson.

Off-shell matching includes an algebraic field

Write the fields as ϕ\phi, ψα\psi_\alpha, and F. Before equations of motion, a complex scalar supplies two real bosonic components, whereas a two-component complex Weyl spinor supplies four real Grassmann components. Adding a complex F supplies the missing two real bosonic components. This four-against-four off-shell count is formal component bookkeeping, not eight physical particle polarizations. On shell the fermion equation removes half the independent propagating components, matching the scalar's two real physical degrees of freedom.

For a free massless chiral field the physical states include the complex scalar's particle and antiparticle and the Weyl fermion's corresponding helicity states. A supersymmetric mass reorganizes them into two scalar states and a massive spin-one-half doublet, still with equal bosonic and fermionic state counts. The auxiliary field never appears as an additional external particle. Confusing its off-shell components with a new scalar resonance would give the wrong spectrum even in the simplest free theory.

δϕ=2 εψ,δψα=2i(σμεˉ)α∂μϕ+2εαF,δF=2iεˉσˉμ∂μψ\delta\phi=\sqrt2\,\varepsilon\psi,\qquad \delta\psi_\alpha=\sqrt2 i(\sigma^\mu\bar\varepsilon)_\alpha\partial_\mu\phi+\sqrt2\varepsilon_\alpha F,\qquad \delta F=\sqrt2 i\bar\varepsilon\bar\sigma^\mu\partial_\mu\psi
Parameters epsilon and fields psi are Grassmann odd and their written ordering is retained. These off-shell transformations use the module's (+---) spinor convention and do not require the fermion or scalar equations of motion.↔ Scroll wide equations horizontally.

Auxiliary elimination fixes the potential sign

For canonical scalar kinetic normalization and holomorphic superpotential W, the auxiliary terms are F∗F+FWϕ+F∗Wϕ∗F^*F+FW_\phi+F^*W_\phi^*. Treat F and its conjugate as independent variables in the variation. The stationary equations give F=−Wϕ∗F=-W_\phi^* and its conjugate. Substitution produces minus the modulus squared of the superpotential derivative in the Lagrangian. Since a static potential enters the mostly-minus scalar Lagrangian as minus V, the physical potential is nonnegative rather than negative. Completing the square provides a direct sign check.

F has no derivative kinetic term and is determined locally by an algebraic equation, so it has no independent wave equation or freely chosen propagating initial condition. Removing it yields the same physical dynamics, but transformations written only on the remaining fields generally close using equations of motion. That is the meaning of on-shell closure. Keeping F is often preferable for constructing interactions or superspace expressions because symmetry remains manifest before imposing dynamics. Neither formulation is more physical merely because it has more displayed component symbols.

LF=∣F+Wϕ∗∣2−∣Wϕ∣2,F=−Wϕ∗,VF=∣Wϕ∣2,[ϕ]=1, [ψ]=32, [F]=2, [W]=3\mathcal L_F=|F+W_\phi^*|^2-|W_\phi|^2,\qquad F=-W_\phi^*,\qquad V_F=|W_\phi|^2,\qquad [\phi]=1,\ [\psi]=\tfrac32,\ [F]=2,\ [W]=3
Dimensions are powers of energy in four spacetime dimensions. In particular F has energy-squared units and V has energy-to-the-fourth units. The square completion applies to canonical Kähler metric; a general positive metric inserts its inverse in V.↔ Scroll wide equations horizontally.

Degeneracy refers to an unbroken vacuum

At a supersymmetric stationary vacuum, the auxiliary expectation vanishes and the quadratic bosonic and fermionic actions organize into equal-mass multiplets. For W=mϕ2/2W=m\phi^2/2, the scalar potential is ∣m∣2∣ϕ∣2|m|^2|\phi|^2, and the fermion mass coefficient is m. The physical mass is its absolute value, not its complex phase. Away from a vacuum, a local second derivative of W is a background-dependent coefficient and need not equal every eigenfrequency obtained from the full scalar Hessian.

Gauge-charged chiral fields obey additional representation constraints and interact with vector-multiplet auxiliary fields. Multiple chiral fields also produce a matrix of superpotential second derivatives and possible mixing. These extensions preserve the distinction between algebraic auxiliaries and propagating states. The present single-field calculation isolates the sign and count that remain essential in more complicated models. All numerical parameters below are chosen to make this theoretical bookkeeping transparent; no proposed field content or mass scale is an experimental superpartner observation.

Eliminate F in a massive toy multiplet

Take canonical normalization and W=mϕ2/2W=m\phi^2/2 with real m=3 GeVm=3\,\mathrm{GeV}. At the real background ϕ=2 GeV\phi=2\,\mathrm{GeV}, compute F and V. Then state the common particle mass about the supersymmetric vacuum.

  1. Differentiate the superpotential: Wϕ=mϕ=6 GeV2W_\phi=m\phi=6\,\mathrm{GeV^2} at the stated background. The auxiliary equation gives F=−6 GeV2F=-6\,\mathrm{GeV^2}.

  2. Substitution into the auxiliary Lagrangian gives LF=−36 GeV4\mathcal L_F=-36\,\mathrm{GeV^4}, hence potential V=+36 GeV4V=+36\,\mathrm{GeV^4}. The nonzero background is not the vacuum.

  3. At the vacuum phi equals zero, F vanishes. The scalar potential has mass squared nine GeV squared and the Weyl mass coefficient is three GeV, so the common physical mass is three GeV.

The result

The background has F = −6 GeV² and V = 36 GeV⁴. About the supersymmetric vacuum the propagating scalar and fermion masses are both 3 GeV.

Explore the model

Interactive lab

Interactive lab · quantum

Count probabilities without counting auxiliary particles

Reset and set BOTH Mixing angle θ = 60° and Relative phase φ = 0°; predict basis probabilities 0.75 and 0.25. For a fresh comparison, Reset and set θ = 120° and φ = 0°; predict 0.25 and 0.75. Both sums remain one.

Count probabilities without counting auxiliary particlesA normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Current readings: Probability |0⟩: 71.1%; Probability |1⟩: 28.9%; Bloch (x, y, z): 0.78, 0.45, 0.42. All parameters are adjustable with the labeled controls below.xyz|0⟩|1⟩Basis probabilitiesP(0)71.1%P(1)28.9%
Bloch vector / P(0)P(1)Phase latitude
Probability |0⟩
71.1%
Probability |1⟩
28.9%
Bloch (x, y, z)
0.78, 0.45, 0.42
t = 0 s

A normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThis normalized two-state illustration distinguishes weights from numbers of fields. It does not contain a chiral multiplet, Grassmann variables, auxiliary dynamics, or a supersymmetry solver.

Check your understanding

Why does the complex auxiliary F not add a physical scalar particle?

Try it yourself

At another background suppose Wϕ=(3+4i) GeV2W_\phi=(3+4i)\,\mathrm{GeV^2}. Find F, the on-shell auxiliary contribution to the Lagrangian, and the potential. Also give the real off-shell bosonic component count of one chiral multiplet.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Conjugate the derivative before applying the minus sign, and count phi and F separately only off shell.

Compare with the solution

The auxiliary value is F=(−3+4i) GeV2F=(-3+4i)\,\mathrm{GeV^2}. Its elimination contributes minus the squared derivative magnitude, or −25 GeV4-25\,\mathrm{GeV^4}, to the Lagrangian, giving potential +25 GeV4+25\,\mathrm{GeV^4}. Off shell phi contributes two real bosonic components and F two more, totaling four. The latter count matches the four real Grassmann components of the Weyl field before equations of motion and does not imply four propagating scalar states.

Take it with you

  • Auxiliaries match off-shell components without enlarging the particle spectrum.
  • F elimination gives a negative Lagrangian contribution and a positive scalar potential.
  • Equal physical masses apply about an unbroken supersymmetric vacuum with the full quadratic dynamics.

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