Wess-Zumino model and superpotentials
Derive a scalar potential and Yukawa coupling from one holomorphic function and distinguish vacuum masses from background coefficients.
On this page
The question for today
What you’ll understand
- Construct canonical Wess-Zumino interactions with fixed component factors.
- Solve supersymmetric stationary vacua in a cubic example.
- Compute masses at a vacuum while respecting complex-field normalization.
The Wess-Zumino model turns the chiral multiplet into an interacting field theory. Its scalar self-interactions and scalar-fermion coupling are not independent: derivatives of one holomorphic superpotential determine both. This relationship is a useful diagnostic of supersymmetry, provided kinetic normalization and component factors are fixed. We use canonical Kähler normalization and the module's spinor and measure conventions, then analyze a cubic toy model whose vacua and local masses are exactly hand calculable at the classical level.
One holomorphic function fixes several interactions
The canonical action consists of the full superspace integral of and the chiral integral of W plus its conjugate. A renormalizable single-field superpotential is at most cubic in four dimensions. Choose , with mass parameter m and dimensionless coupling lambda. The factors one half and one third are conventions chosen so that its first derivative is m phi plus lambda phi squared. A source using a cubic factor one sixth has a differently normalized coupling.
The chiral highest component yields the auxiliary coupling and a fermion bilinear with coefficient minus one half times the second derivative of W. Eliminating F gives the positive modulus-squared potential. The same lambda consequently controls the quartic scalar interaction and the Yukawa interaction, with related cubic scalar terms when m is nonzero. Adjusting only one of these component couplings would generally break supersymmetry. This is stronger than requiring matching free-particle masses; interactions must also fit the common superfield construction.
Find vacua before extracting a common mass
For a canonical ungauged model, a supersymmetric classical vacuum has vanishing first derivative of W. When both m and lambda are nonzero, the cubic example has two roots: zero and minus m over lambda. Both have zero classical potential. Expand around either root as phi equals its vacuum value plus a complex fluctuation. The quadratic potential is the modulus squared of the second derivative at that root times the fluctuation modulus squared. Its two real scalar components therefore have the same mass magnitude as the Weyl fermion.
Writing the complex fluctuation as gives canonically normalized real kinetic terms and a potential with one half times mass squared multiplying each real square. Forgetting this square-root-two convention can introduce a spurious factor two in a scalar mass. The sign or complex phase of the fermionic mass coefficient can change between vacua without making a physical mass negative. At a supersymmetric root the scalar Hessian and fermion mass magnitude agree; at a general background additional terms involving the nonzero first derivative can split scalar curvatures.
Scope the classical model carefully
Holomorphy means W depends on chiral fields rather than their conjugates. The scalar potential is nevertheless a real function of both phi and its conjugate because it is a modulus square. A real polynomial potential cannot in general be declared supersymmetric merely by naming it a superpotential. The distinction between W and V is essential for finding vacua, couplings, and dimensions. A constant term in W drops out of this rigid nongravitational component dynamics, although that statement changes when gravity is coupled.
The two-vacuum result assumes the entire complex scalar field is available and no additional interactions or constraints modify the model. Restricting the field by hand to a real line can discard physical solutions in other examples. Quantum corrections may renormalize the Kähler metric even when perturbative superpotential corrections are absent, a distinction developed later. Our calculation is thus a classical controlled illustration of related interactions and vacuum degeneracy. It is neither a realistic particle spectrum nor evidence that supersymmetry describes a measured set of elementary particles.
Work it through
Two roots with equal mass magnitudes
Take real and . Find the supersymmetric classical vacua and the scalar and fermion masses about each, using canonical normalization.
The first derivative is . Its roots are phi equal to zero and phi equal to minus four GeV; the modulus-squared potential vanishes at each.
The second derivative is . It equals plus two GeV at the first root and minus two GeV at the second.
The physical fermion mass is the absolute coefficient, two GeV. Expanding the potential gives mass squared four GeV squared for each of the two real scalar fluctuations at either root, matching the fermion mass magnitude.
The vacua are 0 and −4 GeV. Each has zero classical potential and a chiral multiplet with common physical mass 2 GeV.
The living notebook
Explore the model
Interactive lab · function
A quadratic coefficient sets local curvature
Reset and set BOTH Coefficient a = 0.5 and Position x = 2; predict y = 2 and tangent slope 2. For a fresh comparison, Reset and set a = 2 and x = 2; predict y = 8 and slope 8. Inspect the value and slope readouts.
- y at chosen x
- 0.608
- Tangent slope · 2ax
- 1.35
- Signed area · ax³/3
- 0.182
This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe instrument models only y = a x², useful for a local real quadratic expansion. It does not evaluate a complex superpotential, a quartic Wess-Zumino potential, Yukawa terms, or supersymmetric masses.
Pause & reason
Check your understanding
Your turn
Try it yourself
Set real and . At the background , compute F, V, and the fermion bilinear mass coefficient. Can this background be treated as an unbroken supersymmetric vacuum?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Differentiate W first. A nonzero first derivative is a warning against interpreting the second derivative as a common vacuum mass.
Compare with the solution
The derivative is , so and . The second derivative is , the local fermion mass coefficient in this background. Because the first derivative is nonzero, this is not a supersymmetric vacuum. A physical scalar fluctuation analysis requires the full Hessian and a stationary background, rather than assigning every component a common five-GeV mass from the bilinear coefficient alone.
Keep the idea
Take it with you
- A holomorphic superpotential relates scalar and Yukawa interactions with fixed normalization factors.
- Supersymmetric vacuum masses follow from W-second after solving W-prime equals zero.
- A background coefficient is not automatically a physical vacuum mass.
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