advanced20 min studyLesson 859 in Physics

Baryogenesis conditions and model dependence

Separate evidence for a baryon excess from conditional mechanisms that could generate or redistribute it.

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What you’ll understand

  • Explain the assumptions behind the Sakharov conditions.
  • Track baryon and lepton number in an electroweak topological transition.
  • Use a sphaleron conversion coefficient only under its chemical-equilibrium assumptions.

The matter abundance inferred from primordial nuclei and cosmic microwave background patterns requires a net baryon density in our observable region. It does not reveal the microscopic process that established this density. Baryogenesis asks how dynamics could generate an excess from specified initial conditions, while leptogenesis first creates a lepton-related asymmetry that other reactions can partly convert into baryon number. A viable mechanism must explain generation, transport, and survival. Finding one symmetry-violating interaction or reproducing one final number is not sufficient, because later reactions can erase an asymmetry and several different early histories can lead to the same late abundance.

Define the asymmetry before proposing its origin

Let net baryon density mean baryon number carried by particles minus that carried by antiparticles, with a proton assigned unit baryon number. Divide by entropy density to define a yield that stays fixed during adiabatic expansion once baryon-changing reactions cease. The baryon-to-photon ratio is another useful normalization, but photon number can change during entropy transfer. Their familiar late-time conversion factor assumes the standard photon-neutrino entropy inventory and no additional late reheating.

Nucleosynthesis responds to nuclear reaction rates and the baryon density, while microwave anisotropies respond to baryon loading and the expansion model. Agreement between such inferences supports a consistent baryon abundance, conditional on the cosmological and microphysical model. Neither observable labels a particular heavy particle, CP phase, or phase transition as the cause. The nonzero abundance can be supplied as an initial condition for those later calculations even while its dynamical origin remains an open question.

YB=nb−nbˉs,ηB=nb−nbˉnγ,ηB≃7.04YBY_B=\frac{n_b-n_{\bar b}}s,\qquad \eta_B=\frac{n_b-n_{\bar b}}{n_\gamma},\qquad \eta_B\simeq7.04Y_B
The final approximate factor uses the standard post-electron-annihilation entropy-to-photon ratio, including the ideal relic-neutrino contribution. It is not the ratio at every early temperature or in an arbitrary entropy history.↔ Scroll wide equations horizontally.

The Sakharov conditions describe necessary ingredients under assumptions

Starting from a baryon-symmetric state, baryon-number-changing dynamics is required to create a total baryon excess. Charge conjugation and combined charge-conjugation-parity symmetries must be broken so opposite asymmetries are not produced with exactly compensating weights. Under the usual local, unitary, CPT-invariant framework with no imposed charge chemical potentials, complete thermal equilibrium cannot generate a baryon excess from the symmetric state. A departure from that equilibrium supplies the third standard Sakharov ingredient.

These conditions do not guarantee an adequate surviving abundance. A calculation must quantify the asymmetry source, inverse reactions, flavor redistribution, and washout. The existence of CP violation in laboratory particle physics alone does not demonstrate successful baryogenesis. Mechanisms that modify standard assumptions, such as an effective CPT-breaking background, require their own equilibrium argument instead of an unconditional appeal to the textbook list. A preexisting conserved charge also changes what an equilibrium ensemble is allowed to retain.

Sphalerons redistribute charges subject to plasma chemistry

In the three-generation Standard Model, an electroweak transition between neighboring gauge vacua changes baryon and lepton number equally. Define the integer change of the usual unmultiplied Chern–Simons vacuum label as ΔNCS\Delta N_{\rm CS}. Then both charge changes equal three times that label change, while their difference is conserved. A thermal sphaleron rate is a transition rate per volume before conversion to charge relaxation; it must not be confused directly with the per-particle rates used earlier.

When electroweak sphalerons, the relevant Yukawa reactions, and gauge reactions equilibrate in the electroweak-symmetric plasma, chemical-potential constraints redistribute an initial baryon-minus-lepton yield. For three generations, one Higgs doublet, hypercharge neutrality, small chemical potentials, and no equilibrated additional charge-carrying species, the ideal result is a baryon fraction of twenty-eight seventy-ninths of that yield. Different equilibrium subsets, particle content, or passage through the electroweak crossover alter this conversion; it is not a universal leptogenesis efficiency.

ΔB=ΔL=3ΔNCS,Δ(B−L)=0,YB=8Nf+4NH22Nf+13NHYB−L=2879YB−L\Delta B=\Delta L=3\Delta N_{\rm CS},\qquad \Delta(B-L)=0,\qquad Y_B=\frac{8N_f+4N_H}{22N_f+13N_H}Y_{B-L}=\frac{28}{79}Y_{B-L}
The final equality assumes the stated symmetric-phase equilibrium conditions with Nf=3N_f=3 fermion generations and NH=1N_H=1 Higgs doublet. BB and LL denote net baryon and lepton charges; the conserved seed need not be generated by the sphalerons themselves.↔ Scroll wide equations horizontally.

Convert a specified conserved seed, without claiming to generate it

Assume the ideal Standard Model chemical-equilibrium conditions just stated and a supplied seed YB−L=2.37×10−10Y_{B-L}=2.37\times10^{-10}. No later washout or entropy injection occurs. Find the converted baryon yield and its late baryon-to-photon ratio using 7.047.04. State what this computation leaves unexplained.

  1. Apply the conditional conversion coefficient rather than treating all the seed as baryon number. Since 2.37/79=0.032.37/79=0.03, multiplying by 28/7928/79 gives YB=8.4×10−11Y_B=8.4\times10^{-11}. The sign follows the positive supplied baryon-minus-lepton seed.

  2. Carry the yield through adiabatic expansion and use the late entropy normalization. The photon ratio is 7.04(8.4×10−11)=5.9136×10−107.04(8.4\times10^{-11})=5.9136\times10^{-10}. This conversion would change if extra entropy were injected after the baryon number became fixed.

  3. Identify the missing dynamical input: the seed was specified, not produced by a CP-violating model. Its creation efficiency, survival before equilibrium redistribution, and consistency with other constraints remain to be calculated. A plausible magnitude alone is not evidence for a particular source.

The result

The conditional output is YB=8.4×10−11Y_B=8.4\times10^{-11} and ηB≃5.91×10−10\eta_B\simeq5.91\times10^{-10}. These are consequences of the supplied seed and assumptions, not an observational determination or a complete baryogenesis model.

Explore the model

Interactive lab

Interactive lab · markov

Biased occupancy is only a restricted analogy

Reset and set both controls to p=0.3p=0.3, q=0.1q=0.1: the stationary probability of state 1 is 0.750.75. Reset and set both controls to p=0.1p=0.1, q=0.3q=0.3: it is 0.250.25. The finite-step distribution starts in state 0 in each run and approaches its selected stationary law during playback. This classical imposed bias is not CP violation, a baryon-number source, or a realization of Sakharov's conditions.

Biased occupancy is only a restricted analogyExact finite-step probabilities for a two-state chain starting in state 0, not sampled trajectories. Playback advances two transitions per second. When p = q = 0 every distribution is stationary; when p = q = 1 the chain alternates forever. A single zero transition creates an absorbing state. Current readings: P(state 1) at step 0: 0%; Stationary P(state 1): 60%; Chain behavior: Monotone convergence. All parameters are adjustable with the labeled controls below.Two-state Markov distribution after 0 steps: state zero probability 1, state one probability 0.Initial distribution (1, 0) · step 0p = 0.3q = 0.201100%0%1−p1−qP(0)P(1)Monotone convergence
P(state 0)P(state 1)Stationary distribution
P(state 1) at step 0
0%
Stationary P(state 1)
60%
Chain behavior
Monotone convergence
t = 0 s

Exact finite-step probabilities for a two-state chain starting in state 0, not sampled trajectories. Playback advances two transitions per second. When p = q = 0 every distribution is stationary; when p = q = 1 the chain alternates forever. A single zero transition creates an absorbing state. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA final asymmetry requires specifying dynamics and normalization; a biased toy chain cannot establish a microscopic cosmological mechanism.

Check your understanding

Under the stated three-generation electroweak transition convention, which quantity is unchanged by a single sphaleron transition?

Try it yourself

A selected electroweak topological transition has ΔNCS=2\Delta N_{\rm CS}=2 in a three-generation model. Initially the net charges are B=10B=10 and L=4L=4 in common charge units. Compute the final charges and both their sum and difference. Does this arithmetic determine the probability of the transition?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Apply the same change to both charges, using the unmultiplied vacuum-label convention.

Compare with the solution

Both charges increase by six, giving B=16B=16 and L=10L=10. Their difference remains six, while their sum increases from fourteen to twenty-six. The sum change is twelve. Charge counting determines the selection rule, not the thermal rate, the sign bias of an ensemble, or whether any generated asymmetry survives. Those require a specified plasma and nonequilibrium dynamics.

Take it with you

  • Evidence for net baryon density does not identify its generation mechanism.
  • Sakharov's conditions are necessary ingredients under conventional assumptions, not a sufficient quantitative model.
  • Sphaleron conversion factors depend on particle content, charge constraints, and equilibrium conditions.

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