research31 min studyLesson 564 in Mathematics

Projective space and the Proj construction

Build projective geometry from homogeneous prime ideals and degree-zero localizations while tracking the grading assumptions.

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What you’ll understand

  • Identify which homogeneous primes belong to Proj.
  • Compute standard affine charts using the degree-zero part of a localization.
  • Separate general graded-ring constructions from standard degree-one projective embeddings.

Homogeneous coordinates identify nonzero scalar multiples over a field, but schemes need a construction that also works over rings and keeps local functions. Proj supplies it using homogeneous prime ideals and graded localization. The word homogeneous is not a cosmetic restriction: it determines which equations respect coordinate scaling and which fractions define regular functions on a chart. We will first state the construction for a nonnegatively graded ring, then add finite generation in degree one when asserting a closed embedding into ordinary projective space or the usual behavior of its twisting line bundle.

Remove the irrelevant homogeneous primes

Write S as a direct sum of nonnegative graded pieces and let S_+ be the ideal of positive-degree elements. Proj S consists of homogeneous prime ideals that do not contain S_+. Its closed sets come from homogeneous ideals. A standard open D_+(f), where f is homogeneous of positive degree, consists of primes avoiding f. These opens cover Proj and intersect by multiplying their defining homogeneous elements. The excluded ideal reflects the fact that all homogeneous coordinates cannot vanish simultaneously.

For a polynomial ring A[X₀,…,Xₙ] with each variable in degree one, these standard charts build projective n-space over A. Over a field its rational points have the familiar nonzero-coordinate description modulo common scalar multiplication. That description does not exhaust its scheme points or describe all families over arbitrary test rings. In particular, a collection of homogeneous coordinates over a ring requires appropriate local generation conditions; a field-based quotient picture is not a replacement for the scheme construction.

Proj⁡S={p⊂S:p homogeneous prime, S+⊈p},D+(f)≅Spec⁡(Sf)0\operatorname{Proj}S=\{\mathfrak p\subset S:\mathfrak p\text{ homogeneous prime},\ S_+\not\subseteq\mathfrak p\},\qquad D_+(f)\cong\operatorname{Spec}(S_f)_0
The chart ring is the degree-zero subring of the graded localization, rather than the entire localization. The element f must have positive degree.↔ Scroll wide equations horizontally.

Equal total degrees make chart functions invariant

If f has degree d, the degree-zero fractions are represented by g/f^r with g homogeneous of degree rd. The numerator and denominator have equal total degree, so the fraction is unchanged by homogeneous scaling. In ordinary projective space the chart where X_i is nonzero has coordinates X_j/X_i, giving a polynomial ring in n variables over the base. Overlaps are ordinary localizations of these chart rings, which is what allows the structure sheaves to glue.

If S is generated by finitely many degree-one elements over S₀, a homogeneous presentation realizes Proj S as a closed subscheme of a finite-dimensional projective space over S₀. In this setting the sheaf O(1) is invertible and is the hyperplane line bundle. Arbitrary positive gradings still allow Proj, but these conclusions cannot simply be transferred unchanged: degree-one generators may be absent, and a chosen twist need not be an invertible sheaf. The grading hypotheses must travel with every statement about charts, twists, or embeddings.

(Sf)0={gfr:g homogeneous, deg⁡g=rdeg⁡f},D+(Xi)≅Spec⁡A[X0/Xi,…,Xi/Xi^,…,Xn/Xi],D+(Xi)⊂PAn(S_f)_0=\left\{\frac{g}{f^r}:g\text{ homogeneous},\ \deg g=r\deg f\right\},\qquad D_+(X_i)\cong\operatorname{Spec}A[X_0/X_i,\ldots,\widehat{X_i/X_i},\ldots,X_n/X_i],\qquad D_+(X_i)\subset\mathbf P_A^n
The hat omits the coordinate equal to one. The displayed chart is for the standard polynomial grading; other weights require solving the degree-zero condition again.↔ Scroll wide equations horizontally.

A homogeneous equation becomes an affine relation on each chart

A projective closed subscheme defined by a homogeneous ideal is computed chart by chart by dividing its equations by matching powers of the chosen nonvanishing coordinate. This dehomogenization retains the quotient-ring structure, including possible nilpotents. Passing to another chart requires checking the transition maps, rather than merely joining drawings of the affine zero sets. A point omitted by one chart may be a perfectly ordinary point of the projective scheme, often interpreted as lying at infinity for that affine description.

The smooth conic provides a useful example in which quadratic homogeneous coordinates describe a projective line. Its local affine coordinate is a ratio, and another ratio supplies the reciprocal chart. This does not make every plane curve a projective line: the equation and transition maps are doing substantive work. More broadly, different graded presentations can lead to isomorphic underlying schemes while specifying different polarizations. Later Hilbert polynomials will depend on the chosen ample line bundle, not only on the abstract space.

Compute two charts of a projective conic

Let S=k[X,Y,Z]/(XZ−Y²) with all variables in degree one. Compute the charts D_+(X) and D_+(Z), show they cover, and identify their overlap transition.

  1. On D_+(X), put u=Y/X and v=Z/X. The relation becomes v=u², so the chart ring is k[u,v]/(v−u²)≅k[u]. On D_+(Z), put w=Y/Z and r=X/Z; the relation is r=w², so this chart is Spec k[w].

  2. A homogeneous prime containing both X and Z also contains Y² and therefore Y. It would contain the irrelevant ideal, so it is excluded from Proj. Hence the two stated charts cover the entire conic.

  3. On their overlap u is invertible, and w=Y/Z=(Y/X)/(Z/X)=u/u²=1/u. Thus the two affine lines glue by the reciprocal transition, giving a scheme isomorphic to P¹.

The result

The conic is covered by two affine lines with the usual projective-line transition. The homogeneous quadratic presentation records more than a single affine parabola.

Explore the model

Interactive lab

Interactive lab · function

Inspect the local quadratic chart without losing its parameter

Pause and Reset; set a=1,x=−1 and predict v=x²=1. For a fresh comparison Reset and set a=1,x=1 and predict the same v but a different horizontal coordinate. In the conic chart the retained parameter u distinguishes these two points; projecting onto v alone would identify them. This instrument draws the affine relation v=u² only. It does not add the second projective chart, perform weighted localization, or compute a Proj.

Inspect the local quadratic chart without losing its parameterThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA coordinate projection can discard information that remains present in an affine chart of a projective scheme.

Check your understanding

For a homogeneous element f of positive degree, which ring defines D_+(f) in Proj S?

Try it yourself

For S=k[a,b] graded by deg a=2 and deg b=3, compute (S_a)₀ and (S_b)₀. Explain why b/a is not a degree-zero chart coordinate.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

For a monomial numerator, solve the equality between its weighted degree and the degree of the denominator.

Compare with the solution

A degree-zero monomial in S_a has the form a^i b^j/a^r with 2i+3j=2r. Thus j is even, and the monomial is a power of b²/a³. Hence (S_a)₀=k[b²/a³]. Similarly (S_b)₀=k[a³/b²]. The fraction b/a has degree 3−2=1, so it is not a regular function in either degree-zero chart ring merely by being a fraction.

Take it with you

  • Proj uses homogeneous primes avoiding the irrelevant ideal.
  • Projective chart functions come from degree-zero localizations.
  • Degree-one generation is an additional hypothesis behind standard projective embeddings and O(1).

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