Ionization loss and Bethe–Bloch regimes
Use the mean stopping power within its domain and distinguish it from deposited-signal distributions.
On this page
The question for today
What you’ll understand
- Read the charge, speed and material factors in the heavy-particle Bethe equation.
- Convert mass stopping power to a mean layer loss.
- Distinguish a mean loss from a most probable detector signal.
A charged particle crossing matter transfers energy through many microscopic interactions. Ionization and excitation provide detector signals, but the average stopping power is not the value deposited in every track. Rare energetic transfers create a long distribution tail, and some energy can leave the sensitive volume. A useful detector calculation must therefore specify the projectile, kinematic regime, material thickness and estimator. The heavy-particle Bethe equation supplies a mean electronic stopping power in a stated regime rather than a complete pulse-height spectrum.
Declare the heavy-particle approximation
Consider a projectile much heavier than an electron, with charge number z in units of the elementary charge. Its speed ratio and Lorentz factor enter the maximum energy transfer to a target electron and the logarithm of the Bethe expression. The material enters through atomic number, molar mass and mean excitation energy. That mean excitation energy is not the same as the mean energy required to create one measurable electron-ion pair in a detector.
Use mass thickness rather than ordinary length in the displayed stopping power. The coefficient K carries units that cancel the material molar-mass factor, leaving energy times area per mass. Multiplying by density gives linear stopping power. Keep all energies inside the logarithm in the same unit, especially when a material excitation energy is tabulated in electronvolts while electron rest energy is expressed in megaelectronvolts. A dimensionless logarithm is a useful units audit.
Identify where a formula stops being sufficient
At modestly relativistic speeds the inverse-speed factor first decreases with energy and a broad minimum appears. The relativistic logarithmic rise is moderated by polarization of the medium, represented by the density correction. At sufficiently low speed, atomic binding, charge exchange and effective projectile charge require corrections. At sufficiently high energy, radiative losses become important and depend on projectile mass. These boundaries depend on projectile and material, so a single energy threshold cannot label every detector.
Electrons and positrons need their own collision formulas because their mass is the same as that of target electrons, with exchange and distinct kinematics. Their bremsstrahlung losses and showers also become important on material-dependent scales. Heavy ions may not remain fully stripped at low speed, invalidating a naive fixed-z-squared extrapolation. Hadronic interactions add another loss and shower channel for hadrons. An electronic stopping calculation should not silently absorb these different processes into an unexplained correction factor.
Choose a detector estimator and containment model
A thin sensitive layer often has an asymmetric energy-loss distribution, with a most probable value below its mean. Energetic secondary electrons can escape or deposit charge in neighboring channels. A reconstructed track can use a truncated mean over many samples to reduce sensitivity to rare large transfers, but its calibration then differs from the unrestricted Bethe mean. The chosen estimator must be compared with a response model using the same selection and material geometry.
Energy lost by the projectile, energy deposited locally, and electrical signal finally measured are three distinct quantities. Quenching, recombination, trapping, collection inefficiency and electronic shaping affect the latter two steps. A mean layer-loss estimate is still valuable for checking orders of magnitude and material budgets, provided it is not called a prediction of every pulse. The quadratic lab tests only the explicit charge-squared factor at a frozen bracket; it does not model those fluctuations or extrapolate Bethe theory outside its regime.
Work it through
Convert a mass stopping power
For a thin layer stipulate constant mass stopping power 2.00 MeV cm^2/g, density 2.50 g/cm^3 and particle path length 0.0200 cm. Estimate the mean energy loss. Explain why it need not equal the most probable measured signal.
The traversed mass thickness is 2.50 times 0.0200 = 0.0500 g/cm^2. The path length must follow the particle through the layer, not just its normal thickness for an oblique track.
Multiplying by the stipulated stopping power gives 0.100 MeV, or 100 keV, for the mean projectile energy loss in this small-change approximation.
A long-tailed transfer distribution, escaping secondaries and detector collection response can shift the observed pulse distribution. The computed mean therefore is neither a universal most probable deposit nor a charge readout without further information.
The mean loss estimate is 0.100 MeV; predicting a pulse distribution requires a containment and detector-response model.
The living notebook
Explore the model
Interactive lab · function
Isolate a charge-squared prefactor
Reset and set BOTH Coefficient a = 1 and Position x = 1; predict y = 1. Compare a fresh Reset run at a = 1 and x = 2; predict y = 4. Interpreting x only as a dimensionless charge ratio illustrates the frozen z-squared prefactor. This is not a stopping-power calculation, a Landau distribution or a model of ion charge exchange.
- y at chosen x
- 0.608
- Tangent slope · 2ax
- 1.35
- Signed area · ax³/3
- 0.182
This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA simple prefactor does not replace a formula’s kinematic regime.
Pause & reason
Check your understanding
Your turn
Try it yourself
For a heavy projectile take beta=0.60, gamma=1.25 and neglect electron-to-projectile mass terms in Wmax. Use electron rest energy 0.511 MeV. Find Wmax. Under the same-speed frozen-bracket approximation, what stopping-power ratio follows for fully stripped charge two versus charge one?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
The product beta squared times gamma squared is 0.5625; the second comparison isolates charge rather than changing speed.
Compare with the solution
The maximum electron transfer is approximately twice 0.511 times 0.5625 = 0.574875 MeV, about 0.575 MeV. The neglected denominator terms require the projectile mass to be large compared with the relevant electron-mass factors. Holding the bracket and speed fixed gives a ratio four from the charge-squared prefactor. This does not compare equal-momentum particles of different mass, does not describe partially stripped slow ions, and does not predict individual secondary-electron transfers or a measured most probable pulse.
Keep the idea
Take it with you
- Mass stopping power and linear stopping power have different units.
- The heavy-particle formula has explicit kinematic and material limits.
- Mean loss, local deposit and measured pulse are not interchangeable.
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