advanced32 min studyLesson 971 in Physics

Lorentz force, beam rigidity and bending magnets

Infer momentum from curvature while keeping charge sign, units and magnetic work distinct.

On this page

What you’ll understand

  • Derive magnetic rigidity from transverse momentum balance.
  • Track bend direction independently of the momentum magnitude.
  • Estimate a track momentum from a small sagitta and state its limitations.

A bending magnet changes a charged particle’s direction and thereby makes its momentum measurable. The field does not supply the energy increase that an accelerator ultimately needs: electric fields do that work. Separating these roles prevents a common mistake in interpreting a curved track as evidence of magnetic acceleration in energy. Begin with one particle in a known static field, then ask what geometric information survives finite measurement precision, unknown pitch angle and passage through material.

Derive the force and its work

Use SI electromagnetic fields, mechanical momentum and a right-handed laboratory coordinate system. The Lorentz equation applies to relativistic momentum as well as to its low-speed limit. Taking the scalar product with velocity gives the rate of change of total relativistic energy. The magnetic contribution vanishes because a cross product is perpendicular to velocity. A static magnetic field can therefore rotate momentum while preserving its magnitude when energy losses and electric fields are negligible.

For motion perpendicular to a uniform field, the rate of turning of the momentum vector is momentum times speed divided by the circular radius. Equating its magnitude to the magnetic force cancels the speed. With a component parallel to the field, the orbit becomes a helix: the measured transverse radius determines transverse momentum, while the pitch supplies the parallel component. Using the helical radius as though it measured total momentum underestimates the latter.

dpdt=q(E+v×B),dEdt=qE⋅v,p⊥=∣q∣Bρ\frac{d\mathbf p}{dt}=q(\mathbf E+\mathbf v\times\mathbf B),\qquad \frac{dE}{dt}=q\mathbf E\cdot\mathbf v,\qquad p_\perp=|q|B\rho
E denotes total energy, q is signed charge, B is field magnitude and rho is the positive transverse radius. No nonrelativistic replacement p=mv is assumed.↔ Scroll wide equations horizontally.

Specify the rigidity convention and magnet length

Define the positive magnetic rigidity as transverse momentum divided by charge magnitude for a perpendicular reference orbit. A signed rigidity can also be used, but its sign must then be carried consistently through lattice equations. The practical conversion between gigaelectronvolt-per-c momentum and tesla-meter rigidity contains the speed of light and elementary charge. We use a rounded coefficient for classroom arithmetic, while a precision spectrometer uses the more accurate conversion and a calibrated field map.

In a uniform dipole, the integrated bending angle is arc length divided by radius. For a short magnet at approximately constant momentum, the same result follows from its transverse field integral. Magnet length in that formula follows the reference path through the field; it is not automatically the straight chord between endpoints. Fringing fields, misalignment and a varying field require an effective integral or trajectory calculation. Reversing either charge or field reverses curvature without changing the positive radius.

Bρ=p⊥∣q∣,p⊥[GeV/c]≃0.300 ∣q/e∣ B[T]ρ[m],∣θ∣=ℓρB\rho=\frac{p_\perp}{|q|},\qquad p_\perp[\mathrm{GeV}/c]\simeq0.300\,|q/e|\,B[\mathrm T]\rho[\mathrm m],\qquad |\theta|=\frac{\ell}{\rho}
The rounded conversion 0.300 is stipulated here; the more precise coefficient is approximately 0.299792458. The final angle formula assumes a uniform transverse dipole.↔ Scroll wide equations horizontally.

Connect a sagitta to a reconstructed track

The sagitta is the maximum displacement of a circular arc from a straight chord joining two measured endpoints. Expanding the exact circle geometry for a short chord produces an inverse-radius estimate. This geometry explains why a longer tracking lever arm improves curvature sensitivity: at fixed radius the sagitta grows quadratically with chord length. It also explains why a tiny sagitta is vulnerable to alignment offsets, which can imitate a change in momentum or even obscure the charge sign.

A real fit combines several hit positions and their covariance, material scattering, energy loss and field uncertainty. Multiple scattering particularly degrades low-momentum tracks, whereas a fixed spatial measurement error makes relative momentum precision worsen at high momentum. The simple circle inference assumes the relevant projection and a sufficiently small bend. It is a diagnostic estimate, not a full detector likelihood or a universal resolution formula, and it does not turn every visible curve into a unique particle identification.

s=ρ−ρ2−(Lc/2)2≃Lc28ρ(Lc/ρ≪1)s=\rho-\sqrt{\rho^2-(L_c/2)^2}\simeq\frac{L_c^2}{8\rho}\qquad(L_c/\rho\ll1)
s and the chord length Lc have length units. The approximation retains the leading small-angle geometric term and concerns the plane perpendicular to the magnetic field.↔ Scroll wide equations horizontally.

Bend a beam without changing its energy

A singly positively charged particle travels perpendicular to a 2.00 T uniform dipole field with momentum 3.00 GeV/c. Use the rounded conversion 0.300. Find its rigidity, radius and bend magnitude for an arc length 0.50 m.

  1. Divide momentum by 0.300 for unit charge: the positive rigidity is 10.0 T m. This uses momentum, not kinetic energy, in the conversion.

  2. Divide rigidity by the field: the transverse radius is 5.00 m. The radius stays positive; the force direction must be found separately from the signed charge and field vector.

  3. The bend magnitude is 0.50/5.00 = 0.100 rad. Under the assumed purely magnetic, loss-free conditions the total energy is unchanged even though the direction rotates.

The result

The rigidity is 10.0 T m, radius 5.00 m and bend 0.100 rad; a magnetic bend supplies no energy gain.

Explore the model

Interactive lab

Interactive lab · vectors

A force-direction projection only

Reset and set BOTH Angle = 0 degrees and Magnitude = 2; predict x component 2. For a fresh comparison Reset and set Angle = 90 degrees and Magnitude = 2; predict y component 2. This ordinary vector projection illustrates a change of direction, not a Lorentz-force trajectory, helical fit or magnetic energy gain.

A force-direction projection onlyPlayback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Current readings: x component: 1.393; y component: 0.975; Magnitude: 1.7. All parameters are adjustable with the labeled controls below.−7.46−3.7303.737.46−3.5−1.7501.753.5xyvvₓ = 1.39
Vectorx / y projectionsTrace marker
x component
1.393
y component
0.975
Magnitude
1.7
t = 0 s

Playback traces a fixed vector and its projections. Angle and magnitude set the geometry; the moving marker does not change them. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forChanging direction and changing energy are different physical operations.

Check your understanding

What does a uniform magnetic field alone do to a loss-free charged particle?

Try it yourself

A nearly circular transverse track in a 1.00 T field has chord length 2.00 m and sagitta 0.0100 m. For unit charge, estimate its radius and momentum using the leading sagitta formula and rounded conversion. What changes if the charge sign is reversed?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

First infer radius from the chord and sagitta, then convert rigidity to momentum; keep magnitude separate from orientation.

Compare with the solution

The inferred radius is 2.00 squared divided by eight times 0.0100, or approximately 50.0 m. The chord-to-radius ratio is 0.04, consistent with a small-angle estimate. The momentum is approximately 0.300 times 1.00 times 50.0 = 15.0 GeV/c. Reversing charge reverses the bending orientation for the same incident direction and field but leaves these positive magnitudes unchanged. A precise result would use the exact circle, multiple hits, material model and calibrated field.

Take it with you

  • Static magnetic bending measures rigidity, not energy gain.
  • A helical radius determines transverse momentum.
  • Sagitta sensitivity depends strongly on lever arm and alignment.

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