advanced32 min studyLesson 972 in Physics

Quadrupole focusing and betatron motion

Use signed transverse kicks and a stable cell map rather than assuming one magnet focuses both planes.

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What you’ll understand

  • Derive the opposite quadrupole forces in the two transverse planes.
  • Apply a thin-lens kick with declared slope coordinates.
  • Diagnose linear periodic stability using the cell trace.

A beam has a finite spread of positions and directions, so bending its central orbit is not enough to keep particles inside a narrow aperture. Quadrupoles provide restoring forces that grow with transverse displacement in one plane. Maxwell’s equations impose an accompanying defocusing action in the other plane. Alternating the orientation of these elements can nevertheless give stable motion in both planes. Understanding that result requires following a complete sequence of kicks and drifts, rather than averaging the signed gradients before transporting the particle.

Fix axes before assigning a focusing sign

Take the reference beam along positive z and a positive charge with nearly constant reference momentum. Near the axis use a normal quadrupole field whose horizontal component is gradient times y and whose vertical component is gradient times x. This field has vanishing divergence and curl in the ideal current-free aperture. The transverse components of velocity cross field then have opposite signs, so a positive gradient restores horizontal displacement and increases vertical displacement.

Use path distance s as independent variable and define slopes as transverse derivatives with respect to s. In the paraxial approximation the longitudinal momentum dominates, allowing force to be converted into a slope derivative. A negative charge or reversed gradient exchanges the focusing planes. Real quadrupoles have finite length, higher multipoles and fringe fields; the linear equations describe a local small-amplitude approximation, not every trajectory that fits inside the pole gap.

Bx=Gy,By=Gx,x′′+kx=0,y′′−ky=0,k=qGpB_x=Gy,\quad B_y=Gx,\qquad x^{\prime\prime}+kx=0,\quad y^{\prime\prime}-ky=0,\qquad k=\frac{qG}{p}
Primes mean d/ds; k has inverse-square-meter units. The displayed positive-gradient focusing assignment uses q>0 and the declared beam direction.↔ Scroll wide equations horizontally.

Transport a lens and a drift in the correct order

When the magnet is short compared with the scale of transverse motion, integrate the horizontal force while holding position approximately fixed. The slope receives a kick proportional to negative position; the position itself is continuous across the ideal thin lens. A drift then changes position according to the new slope. Reversing those two operations generally changes the final position, which is why beam-line matrix products must state the order in which elements are encountered.

Write a column vector of position and slope. Each ideal lens and drift has determinant one at fixed reference momentum, reflecting area preservation in this uncoupled linear approximation. This property alone does not guarantee confinement: a map can preserve area while stretching one direction exponentially and squeezing another. Nor does it certify nonlinear dynamic aperture or account for momentum spread, which changes the quadrupole strength and introduces chromatic effects.

Q(f)=(10−1/f1),D(L)=(1L01),1f=qGℓqpQ(f)=\begin{pmatrix}1&0\\-1/f&1\end{pmatrix},\quad D(L)=\begin{pmatrix}1&L\\0&1\end{pmatrix},\qquad \frac1f=\frac{qG\ell_q}{p}
Q is the horizontal focusing lens for positive f, D is a drift, and ellq is the magnet length. Positions are meters and slopes are dimensionless radians.↔ Scroll wide equations horizontally.

Test a periodic lattice rather than an isolated kick

For a real two-by-two cell matrix with determinant one, eigenvalues solve a reciprocal-pair quadratic. A trace strictly between minus two and two gives complex unit-modulus eigenvalues and a nondegenerate stable linear cell. The cell phase advance follows from half the trace. At the endpoints, repeated unit eigenvalues need separate analysis and can produce secular growth, so equality is not automatically a robust operating point.

A simple equal-strength focusing–defocusing cell with equal intervening drift lengths has a trace reduced by the squared drift-to-focal-length ratio. Both transverse planes can satisfy the same strict stability condition even though each individual quadrupole defocuses one plane. Betatron motion in a ring is the corresponding oscillation about the closed orbit, with an envelope set by the lattice. Resonances, errors and collective forces require additional analysis beyond this ideal linear trace check.

det⁡M=1,∣tr⁡M∣<2,cos⁡μ=12tr⁡M,M=Q(f)D(L)Q(−f)D(L): tr⁡M=2−(L/f)2\det M=1,\quad |\operatorname{tr}M|<2,\quad \cos\mu=\tfrac12\operatorname{tr}M,\qquad M=Q(f)D(L)Q(-f)D(L):\ \operatorname{tr}M=2-(L/f)^2
The rightmost element acts first. Here L is the spacing between neighboring thin lenses; a cell has two such drifts. mu is phase advance per cell.↔ Scroll wide equations horizontally.

A signed thin-lens kick

A positive-charge beam has rigidity 10 T m and passes through a quadrupole with integrated gradient G ellq = 5 T. A particle enters at x = 2 mm, xprime = 1 mrad, y = 2 mm and yprime = 0. Find both outgoing slopes in the ideal thin-lens approximation.

  1. The focusing strength is 1/f = 5/10 = 0.5 per meter, hence f = 2 m in the horizontal plane for the declared orientation.

  2. The horizontal slope kick is minus 2 mm divided by 2 m, or minus 1 mrad. Adding it to the initial 1 mrad leaves zero horizontal slope.

  3. The vertical sign is opposite: its kick is plus 1 mrad, so the outgoing vertical slope is 1 mrad. Positions are unchanged at this ideal thin lens; subsequent drifts change them.

The result

The outgoing horizontal slope is zero and vertical slope is +1 mrad; one quadrupole does not focus both planes.

Explore the model

Interactive lab

Interactive lab · oscillator

A constant-focusing analogy

For each fresh run Reset and set BOTH Damping ratio = 0 and Natural frequency = 1, then compare a Reset run with Damping ratio = 0 and Natural frequency = 2. After two Steps, time is one second: predict displacements cos(1) about 0.5403 and cos(2) about -0.4161. This fixed initial-value oscillator illustrates a focusing frequency, not a quadrupole lattice, a second transverse plane or a beam envelope.

A constant-focusing analogyUnit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Current readings: Displacement x(t): 1; Velocity v(t): 0; Regime: underdamped. All parameters are adjustable with the labeled controls below.02.557.510−1.15−0.5700.571.15Time · sDisplacementunderdamped
Displacement x(t)Current time
Displacement x(t)
1
Velocity v(t)
0
Regime
underdamped
t = 0 s

Unit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forStable local oscillation is only one ingredient of lattice transport.

Check your understanding

What follows from determinant one for a linear cell map?

Try it yourself

For the stated thin-lens cell compare L/f = 1 and L/f = 3. Find each trace, and determine whether the strict linear stability criterion holds. Find the phase advance for the stable case.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the full cell expression, then take the cosine only when the trace lies in the allowed interval.

Compare with the solution

At L/f = 1 the trace is 2 minus 1 = 1, so the cosine of the phase advance is one half and mu is 60 degrees for the principal stable branch. At L/f = 3 the trace is 2 minus 9 = -7, outside the strict interval; the reciprocal eigenvalues are real and the ideal cell is unstable. Both maps still have determinant one. These results concern the specified linear cell, not nonlinear acceptance or every possible focusing lattice.

Take it with you

  • Quadrupole signs depend on charge, direction and gradient convention.
  • Thin lenses change slope while drifts convert slope into displacement.
  • Area preservation is necessary structure but is not a stability guarantee.

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