research39 min studyLesson 716 in Physics

Allocate a mixed anomaly without erasing its class

Use two background connections to distinguish exact global symmetries, dynamical gauge consistency, and counterterm-dependent Ward representatives.

On this page

What you’ll understand

  • Expand a mixed Abelian anomaly polynomial with correct combinatorial factors.
  • Explain what changes when a background symmetry is made dynamical.
  • Track how a local counterterm redistributes consistent Ward variations.

Coupling a global symmetry to an external gauge field is a diagnostic, even when that field is never integrated over. It lets the generating functional reveal an obstruction to preserving several background gauge invariances at once. Mixed anomalies involve more than one symmetry or gravity. Their physical meaning depends on which fields are external and which are dynamical, while local counterterms can shift the apparent violation among currents without removing the invariant obstruction.

Promote sources without silently gauging the theory

Let X and Y be Abelian symmetries with background connections aX,aYa_X,a_Y and curvatures fX,fYf_X,f_Y. A left-handed Weyl field with charges (xi,yi)(x_i,y_i) contributes a Chern character with exponent (xifX+yifY)/(2π)(x_if_X+y_if_Y)/(2\pi). Background gauge transformations encode Ward identities for the associated currents. They do not add propagating gauge bosons unless the connections are integrated over. An anomalous background response is allowed as data of a global symmetry, whereas an uncanceled redundancy of a dynamical gauge field is an inconsistency.

The distinction also affects whether a continuous symmetry is exact. A current anomalous only in external probes can describe an exact global symmetry at zero sources with a 't Hooft anomaly. If Y is dynamical and X has a nonzero X–Y-squared anomaly, gauge-field configurations can violate X charge even with no external X source. The full continuous X symmetry is then generally explicitly broken by quantum effects, sometimes leaving a discrete subgroup. It should not automatically be treated as an exact symmetry in later anomaly-matching arguments.

I6gauge=16∑i(xiX+yiY)3,X=fX2π,Y=fY2π,I6⊃CXYY2XY2,CXYY=∑ixiyi2I_6^{\rm gauge}=\frac16\sum_i(x_iX+y_iY)^3,\qquad X=\frac{f_X}{2\pi},\quad Y=\frac{f_Y}{2\pi},\qquad I_6\supset\frac{C_{XYY}}2XY^2,\quad C_{XYY}=\sum_i x_iy_i^2
The all-left-handed sign convention is the same as the descent lesson. The factor one half is 3/6 from expanding the cubic polynomial, not an extra fermion degeneracy. Other terms include X³, X²Y, Y³ and mixed gravitational terms; all independent coefficients matter when the corresponding sources are admitted.↔ Scroll wide equations horizontally.

Choose which Ward identity remains exact

For the displayed mixed term, a local descent representative can place the connection aXa_X in the five-form and leave only fYf_Y factors. Its Y gauge variation then vanishes, while its X variation produces a term proportional to λXfY∧fY\lambda_X f_Y\wedge f_Y. This representative is especially useful when Y is dynamical, because preserving Y gauge invariance is mandatory. Other anomaly terms must still be considered; isolating one mixed term is not a proof that a full spectrum is consistent.

A Bardeen counterterm involving aX∧aY∧fYa_X\wedge a_Y\wedge f_Y changes the local distribution of consistent anomalies. On a closed patch calculation, its X variation has the opposite sign from its Y variation after integration by parts. One can therefore move a mixed term from one Ward identity to another. If the original anomaly polynomial is nontrivial, however, no allowed four-dimensional local counterterm makes every background symmetry exact simultaneously. The obstruction is in the shared anomaly class, not in one arbitrarily preferred current representative.

I5(0)=CXYY2aX2π(fY2π)2⟹δXlog⁡Z=iCXYY8π2∫λXfY∧fY,δYI5(0)=0I_5^{(0)}=\frac{C_{XYY}}2\frac{a_X}{2\pi}\left(\frac{f_Y}{2\pi}\right)^2\quad\Longrightarrow\quad \delta_X\log Z=\frac{iC_{XYY}}{8\pi^2}\int\lambda_X f_Y\wedge f_Y,\qquad \delta_Y I_5^{(0)}=0
This is a local consistent representative of the isolated XYY polynomial term, preserving Y. It uses δlog Z = 2πi∫I₄⁽¹⁾ and dimensionless infinitesimal gauge parameters. It is not the symmetric single-current descent coefficient, and it does not claim that all X³, X²Y, or gravitational anomalies vanish.↔ Scroll wide equations horizontally.

Keep counterterm bookkeeping separate from transport

To see the relative signs directly, vary C=b∫aX∧aY∧fYC=b\int a_X\wedge a_Y\wedge f_Y in a locally trivial bundle with boundary terms absent. The result is δC=b[−∫λXfY∧fY+∫λYfX∧fY]\delta C=b[-\int\lambda_X f_Y\wedge f_Y+\int\lambda_Y f_X\wedge f_Y]. This shows precisely what is exchanged. Global bundle patching can restrict counterterms further, so the local expression should not be presented as a universal globally defined functional on every background. Consistent and covariant current redefinitions also require their own specified local polynomials.

An anomalous divergence fixes a source or Ward identity, not a complete constitutive equation. Turning it into a persistent current requires a state, boundary conditions, relaxation mechanisms, and a defined equilibrium or driven limit. In particular, no universal steady magnetic current follows just from reading a mixed polynomial coefficient. Background geometry organizes possible responses and constraints, while actual transport depends on additional dynamics. This separation prevents a regulator-dependent current split from being mistaken for a directly measurable charge-production rate in every physical setup.

An XYY anomaly with conserved Y

Two left-handed Weyl fields have charges (x,y)=(1,1)(x,y)=(1,1) and (1,−1)(1,-1). Compute C_XYY, C_XXY, and C_YYY. For the isolated XYY term use the Y-preserving representative and a small variation with ∫λXfY∧fY=4π2ϵ\int\lambda_X f_Y\wedge f_Y=4\pi^2\epsilon. Find its contribution to δlog⁡Z\delta\log Z.

  1. The mixed coefficient is CXYY=1(1)2+1(−1)2=2C_{XYY}=1(1)^2+1(-1)^2=2. In contrast, CXXY=12(1)+12(−1)=0C_{XXY}=1^2(1)+1^2(-1)=0 and CYYY=13+(−1)3=0C_{YYY}=1^3+(-1)^3=0. Squaring y before multiplying by x is crucial.

  2. The polynomial's mixed part is (2/2)XY2=XY2(2/2)XY^2=XY^2. Choosing aXa_X in the five-form allocates this mixed variation to X and preserves Y, giving coefficient i2/(8π2)i2/(8\pi^2) in front of the specified integral.

  3. The contribution is δlog⁡Z=[i2/(8π2)](4π2ϵ)=iϵ\delta\log Z=[i2/(8\pi^2)](4\pi^2\epsilon)=i\epsilon. The separate cubic X coefficient is two and its linear gravitational coefficient is also two, so this calculation has not made X anomaly free.

The result

The spectrum has C_XYY = 2, C_XXY = C_YYY = 0, and the specified mixed consistent phase variation is iε in the Y-preserving scheme. Other X-related anomaly terms remain part of the full theory.

Explore the model

Interactive lab

Interactive lab · matrix

Change a basis without removing its structure

Reset and set both controls to final scale a = 1 and shear b = 0; predict selected determinant 1. Reset and set both controls to a = 1 and b = 1; predict the same determinant while the selected final map shears the coordinate grid. Geometry starts at the identity after Reset and interpolates during Play; readouts always describe the selected final matrix. This illustrates a change of coordinates only, not background charges, mixed coefficients, or anomaly cancellation.

Change a basis without removing its structureThe selected matrix is A = [[a,b],[0,1]]. Playback interpolates geometry between the identity and A; readouts always describe A. Its determinant is a and its singular values come from AᵀA. Positive a makes every supported matrix invertible. This two-dimensional family is not a general eigensolver or a learned network. Current readings: Area scale · det A: 1.4; Singular values · σmax, σmin: 1.597, 0.876; Condition number · κ₂(A): 1.823. All parameters are adjustable with the labeled controls below.Matrix A with first row 1.4, 0.6 and second row zero, one; display interpolates between identity and A while final determinant remains 1.4.−4−2024−2−1012x · equal geometric scaleyA = [ 1.4 0.6 ; 0 1 ]Display blend: 0% · final values below
Interpolated geometryOriginal unit squareSelected final transform
Area scale · det A
1.4
Singular values · σmax, σmin
1.597, 0.876
Condition number · κ₂(A)
1.823
t = 0 s

The selected matrix is A = [[a,b],[0,1]]. Playback interpolates geometry between the identity and A; readouts always describe A. Its determinant is a and its singular values come from AᵀA. Positive a makes every supported matrix invertible. This two-dimensional family is not a general eigensolver or a learned network. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forChanging a representation can rearrange components without removing an invariant obstruction; the matrix lab does not calculate anomaly classes.

Check your understanding

What can a local Bardeen counterterm do to a nontrivial mixed background anomaly?

Try it yourself

Replace the example's charge pairs by (2,1)(2,1) and (2,−1)(2,-1). Recompute C_XYY, C_XXY, C_YYY, and C_XXX. At the same specified background integral and in the same Y-preserving scheme, what is the isolated mixed phase variation?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The XYY coefficient is linear in x, whereas the XXX coefficient is cubic in x. Use the unchanged descent normalization.

Compare with the solution

The results are CXYY=2+2=4C_{XYY}=2+2=4, CXXY=4−4=0C_{XXY}=4-4=0, CYYY=1−1=0C_{YYY}=1-1=0, and CXXX=8+8=16C_{XXX}=8+8=16. The mixed polynomial coefficient is 4/2=24/2=2 and its variation is [i4/(8π2)](4π2ϵ)=2iϵ[i4/(8\pi^2)](4\pi^2\epsilon)=2i\epsilon. Doubling x doubles this mixed response but multiplies its pure cubic coefficient by eight. The different scaling demonstrates why one coefficient cannot substitute for the complete anomaly audit.

Take it with you

  • Background probing and dynamical gauging are different operations.
  • A counterterm may preserve one Ward identity by shifting violation into another.
  • Anomaly coefficients constrain responses but do not alone determine a state-dependent transport current.

Read further

Original sources and deeper explanations to follow at your own pace.

Optional progress, saved in this browser when available. Revisit any lesson at any time.

Lesson not marked complete.