Support a white dwarf with occupied electron states
Connect Fermi momentum, composition, and nonrelativistic electron pressure to Newtonian hydrostatic support.
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The question for today
What you’ll understand
- Derive the density exponent of cold electron pressure.
- Distinguish the particles supplying pressure from those carrying most mass.
- Check temperature, momentum, and gravitational regimes separately.
A white dwarf can remain supported after fusion has ceased because its electrons occupy a filled sea of momentum states. Compressing that sea raises its kinetic energy and produces pressure even at zero temperature. The ions usually carry most of the mass while the electrons supply most of the pressure. This separation makes composition central to the mass–radius relation and prevents a simple ideal-gas temperature argument from describing the star.
Count electrons before evaluating their pressure
Use SI units here. Let denote baryonic rest-mass density, the atomic mass unit, and the number of electrons per baryon in fully ionized neutral matter. Then the electron density is fixed by composition rather than by temperature. Spin degeneracy two fills a sphere in momentum space up to the Fermi momentum. Coulomb interactions, crystallization corrections, and finite-temperature tails are omitted in this first electron equation of state.
The nonrelativistic limit requires , while strong degeneracy requires , with the kinetic Fermi energy used in the latter test. These are independent inequalities. A low temperature does not guarantee nonrelativistic electrons: sufficiently high density raises their Fermi momentum. Conversely, massive nuclei can remain nonrelativistic while their supporting electrons have become relativistic. Always identify the species and energy scale to which a regime statement refers.
Differentiate energy to obtain support
For nonrelativistic electrons, integrating the occupied kinetic states gives energy density proportional to . Differentiating energy with respect to volume at fixed electron number yields two thirds of that kinetic energy density as pressure. Thus the pressure is a polytrope with exponent five thirds at fixed composition. It is momentum-space occupation, rather than a mechanical repulsion between stationary electrons, that generates this leading degeneracy pressure.
In a cool low-mass white dwarf, combine this pressure with Newtonian spherical hydrostatic balance. The enclosed mass is dominated by ions, so their rest density enters gravity even though their thermal pressure may be small. Dimensional balance gives a radius that decreases approximately as mass to the negative one third for a fixed nonrelativistic polytrope. This scaling is not an exact stellar solution; the numerical coefficient requires the radial density profile and a surface boundary.
Audit what the approximation leaves out
A real white dwarf has an atmosphere and a temperature-dependent outer envelope, even when its interior electrons are strongly degenerate. Ionic heat capacity can control cooling while contributing little to mechanical support. Coulomb corrections alter the pressure and crystallization releases energy during cooling. These statements concern different derivatives of the thermodynamic energy: dominance of one species in pressure does not imply dominance in heat capacity or luminosity.
Increasing mass compresses the star and eventually invalidates the nonrelativistic electron approximation. Electron capture can also change , and nuclear burning can intervene in an accreting star. Rotation, strong fields, and general relativity require additional checks. The next lesson follows the electron dispersion crossover, but a limiting mass derived from an ideal polytrope should never be interpreted as a universal ignition mass or a complete prediction of the endpoint of stellar evolution.
Work it through
A controlled compression comparison
Two cold configurations have the same composition and densities in the ratio eight. Initially . Find the ratios of Fermi momentum, kinetic Fermi energy, and pressure, and check the final momentum regime.
Because and composition is unchanged, an eightfold density increase doubles the Fermi momentum.
The kinetic energy and Fermi temperature scale as momentum squared. Their ratios are therefore four, whereas pressure scales as density to the five thirds and increases by .
The final momentum is , still below the relativistic crossover. The cold-pressure comparison also requires the final and initial temperatures to remain small relative to their respective Fermi temperatures.
The momentum, kinetic energy, and pressure ratios are two, four, and thirty-two. The large pressure increase follows from occupied kinetic states, with both momentum and temperature conditions retained.
The living notebook
Explore the model
Interactive lab · function
Inspect a quadratic kinetic-energy analogy
Reset and set a = 0.5 and x = 1, predicting y = 0.5 and slope 1. Compare after a fresh Reset with a = 0.5 and x = 2, predicting y = 2 and slope 2. This quadratic illustrates a nonrelativistic momentum-squared dependence only; it has no filled Fermi sea, composition, hydrostatic profile, or white-dwarf solver.
- y at chosen x
- 0.608
- Tangent slope · 2ax
- 1.35
- Signed area · ax³/3
- 0.182
This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forDegeneracy pressure depends on occupied momenta and composition.
Pause & reason
Check your understanding
Your turn
Try it yourself
Compare fully ionized helium and iron-56 at the same rest-mass density in this ideal nonrelativistic model. Use and . Find the electron-pressure ratio iron to helium.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
At fixed mass density the electron-density ratio equals the electron-fraction ratio; apply the pressure exponent afterward.
Compare with the solution
The electron-density ratio is . Hence . Iron supplies fewer electrons per unit mass and therefore less electron support at that density. This compares prescribed cold compositions; it does not calculate an electron-capture reaction, a burning history, or the full equilibrium masses of two stars.
Keep the idea
Take it with you
- Degeneracy pressure depends on occupied momenta and composition.
- Cold and nonrelativistic are separate approximations.
- Hydrostatic structure needs a profile and boundary beyond a local pressure law.
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