advanced35 min studyLesson 900 in Physics

Mass loss and final remnants

Apply distinct wind momentum, energy, and angular-momentum budgets and connect envelope stripping to conditional remnant outcomes.

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What you’ll understand

  • Distinguish a wind momentum comparison from the photon-tiring energy limit.
  • Compute an instantaneous isotropic wind torque under explicit rotation assumptions.
  • Explain why final remnants depend on core evolution and mass-loss history rather than one universal initial-mass threshold.

Mass loss changes both the material available for later burning and the envelope through which a star radiates. It can expose a processed core, alter rotational evolution, and change the conditions before a compact remnant forms. We define a positive outward wind mass-loss rate, so the stellar mass derivative is negative. A hydrostatic interior can coexist with a flowing exterior, but the accelerating wind itself requires a momentum equation rather than static force balance. Numerical wind examples below use supplied hypothetical parameters, not empirical mass-loss rates or dated measurements of named stars.

Wind momentum is not the same budget as wind energy

A steady spherical wind obeys mass conservation through every radius if there are no additional mass sources. Comparing its terminal momentum flux with radiative luminosity divided by light speed defines a useful dimensionless momentum number. A value above unity is not automatically an energy violation: photons can interact more than once and transfer momentum through an optically thick or multiline flow. Whether a particular wind is driven requires a force calculation using its opacity, velocity field, ionization, and geometry.

Energy conservation imposes a different necessary condition. Radiation-powered material must gain enough energy both to escape the gravitational potential and to reach its terminal speed. Neglecting base speed, enthalpy changes, and additional energy sources gives a mechanical luminosity to compare with luminosity entering the wind base. If the demanded mechanical power exceeds that supply, the assumed steady escaping solution cannot be maintained. Satisfying the energy bound is necessary but not sufficient: it does not prove the required local radiative acceleration or a stable mass flux exists.

M˙w=4πr2ρv,η=M˙wv∞cLb,Lmech=M˙w(v∞22+GMR)≤Lb\dot M_w=4\pi r^2\rho v,\qquad \eta=\frac{\dot M_wv_\infty c}{L_b},\qquad L_{\rm mech}=\dot M_w\left(\frac{v_\infty^2}{2}+\frac{GM}{R}\right)\le L_b
The outward mass-loss rate is kg s⁻¹, v and v∞ are m s⁻¹, and Lb is radiative power entering the wind base in W. η is dimensionless. The energy bound assumes a stationary radiatively powered wind with negligible omitted base/enthalpy terms; other energy sources require their own accounting.↔ Scroll wide equations horizontally.

The rotation lever arm determines the torque

For a slowly rotating spherical star, an isotropic nonmagnetic wind leaving a rigidly rotating surface carries specific axial angular momentum proportional to the square of the cylindrical launch radius. Averaging the squared sine of colatitude over a sphere supplies a factor of two thirds. This gives an instantaneous angular-momentum loss rate in terms of surface radius and angular velocity. The result assumes uniform mass flux per solid angle and no additional torque once matter has left the surface.

Magnetic stresses can maintain coupling to a larger effective lever arm, while rapid rotation changes surface shape and latitude-dependent flux. Those cases require a different torque model. Even the elementary torque does not alone determine the future angular velocity, because the stellar moment of inertia changes with mass, radius and internal redistribution. A small-step loss fraction can be estimated from the initial torque, but holding the initial angular velocity and radius fixed throughout a large evolutionary change would be inconsistent. Structural spherical symmetry also requires centrifugal acceleration to remain small relative to gravity.

dMdt=−M˙w,dJdt=−23M˙wR2Ω,J=kIMR2Ω,Ω2R3GM≪1\frac{dM}{dt}=-\dot M_w,\qquad \frac{dJ}{dt}=-\frac23\dot M_wR^2\Omega,\qquad J=k_I MR^2\Omega,\qquad \frac{\Omega^2R^3}{GM}\ll1
J is axial angular momentum in kg m² s⁻¹ and Ω is s⁻¹. kI is a dimensionless moment-of-inertia coefficient, not a polytropic index. The torque is an isotropic nonmagnetic surface-launch approximation. Magnetic winds can have an Alfvén lever arm larger than R.↔ Scroll wide equations horizontally.

Remnant classification needs the evolved core

A star that sheds its envelope without proceeding through all advanced burning stages can leave a cooling white dwarf supported predominantly by electron degeneracy. The cold nonrelativistic mass–radius approximation eventually changes as electrons become relativistic; finite temperature, composition, interactions and captures matter for quantitative limits. An envelope lost early through binary interaction can leave a different core composition than isolated single-star evolution would produce. A stellar wind estimate alone therefore does not select whether the remaining white dwarf is helium-rich, carbon–oxygen-rich, or another composition.

More advanced cores can undergo collapse, with neutron-star or black-hole outcomes affected by dense-matter physics, explosion dynamics, neutrino transport, rotation and fallback. Initial mass is informative but is not a universal one-to-one remnant label across metallicities, binary histories and mass-loss prescriptions. We assert no numerical observational threshold here. A useful bookkeeping separation is to evolve core growth and envelope stripping together, then ask which support and nuclear processes remain available. The loss of a visible envelope and the collapse of a compact core are physically distinct events with different timescales.

M=Mc+Menv,dMenvdt=−M˙w−dMcdt(no accretion or other exchange)M=M_c+M_{\rm env},\qquad \frac{dM_{\rm env}}{dt}=-\dot M_w-\frac{dM_c}{dt}\quad\text{(no accretion or other exchange)}
Mc is the defined core mass and Menv the remaining envelope mass in kg. Core growth here reclassifies processed material from envelope to core; it does not create stellar mass. This schematic mass balance ignores small nuclear mass defects and requires a consistent core boundary and no unmodeled mass exchange.↔ Scroll wide equations horizontally.

Check two wind budgets

A hypothetical radiation-powered wind has Lb=10³⁰ W, outward rate 10¹⁵ kg s⁻¹, terminal speed 10⁶ m s⁻¹, surface escape speed 10⁶ m s⁻¹, and c=3 × 10⁸ m s⁻¹. Neglect base kinetic and enthalpy terms. Find η, mechanical luminosity, and its fraction of Lb. Does passing this test prove a driven steady solution?

  1. The momentum number is η=1015106(3×108)/1030=0.3\eta=10^{15}10^6(3\times10^8)/10^{30}=0.3. It compares fluxes with dimensions of force.

  2. The potential energy per unit mass is half the escape speed squared. Adding it to terminal kinetic energy gives 1012 J kg−110^{12}\ {\rm J\,kg^{-1}}.

  3. The mechanical luminosity is 10²⁷ W, or 10⁻³ of the supplied base luminosity. Energy is available in this budget, but an actual driving force and a consistent steady flow still need to be established.

The result

η=0.3 and Lmech=10²⁷ W=0.001Lb. This necessary energy check passes without proving that radiation can launch and accelerate the stipulated wind.

Explore the model

Interactive lab

Interactive lab · function

A torque grows with lever arm squared

Reset and set BOTH Coefficient a to 0.5 and Position x to 1; predict y=0.5. Then Reset and set BOTH a to 0.5 and x to 2; predict y=2. With x as a dimensionless lever arm and fixed coefficient representing the other torque factors, doubling that arm multiplies the quadratic by four. This instrument computes no mass flux, magnetic coupling, angular-velocity evolution, wind acceleration, or final remnant.

A torque grows with lever arm squaredThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA torque’s lever-arm dependence can be checked separately from the physical model that sets the lever arm.

Check your understanding

What does Lmech ≤ Lb establish for the stated radiation-powered steady-wind approximation?

Try it yourself

An initially rigidly rotating spherical toy star has J=kI MR²Ω with kI=0.10. Its isotropic nonmagnetic wind removes a small positive mass fraction ΔMw/M=0.001. Using the initial R and Ω only for this first-order loss step, find ΔJlost/J. Explain why this is not a complete spin-evolution law.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Divide the initial wind-specific angular momentum (2/3)R²Ω by the initial mean specific angular momentum kI R²Ω.

Compare with the solution

The ratio of specific angular momenta is (2/3)/0.10=20/3(2/3)/0.10=20/3. Thus ΔJlost/J is approximately (20/3)(0.001)=0.00667, about 0.667 percent. The stellar angular momentum decreases by this amount. Subsequent angular velocity depends on the changing moment of inertia and internal transport, so this initial-rate estimate cannot be extended unchanged through substantial mass loss or structural evolution.

Take it with you

  • Wind momentum and photon-tiring energy comparisons impose different constraints.
  • A torque requires a stated angular-momentum lever arm and does not alone determine changing spin.
  • Remnants depend on evolved core properties, envelope stripping, interactions and collapse physics.

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