advanced28 min studyLesson 267 in Physics

The covariant Maxwell equations

Recover all four Maxwell equations from tensor equations, derive current conservation from antisymmetry, and distinguish dynamical equations from potential identities.

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What you’ll understand

  • Expand the sourced tensor equation into Gauss and Ampère–Maxwell laws.
  • Recover the homogeneous equations from the cyclic derivative identity.
  • Explain why compatible electromagnetic sources must conserve charge.

Maxwell's four familiar vector equations become two compact spacetime statements. The compression is useful only if their content survives: source signs, displacement current, magnetic divergence, and Faraday induction must all reappear when the equations are expanded. We will check representative components and then use antisymmetry to derive a source consistency condition. This reveals that charge conservation is built into Maxwell dynamics rather than an optional assumption that can be attached to arbitrary prescribed sources afterward.

The sourced equation contains two familiar laws

Use η=diag⁡(1,−1,−1,−1)\eta=\operatorname{diag}(1,-1,-1,-1), x0=ctx^0=ct, F0i=−Ei/cF^{0i}=-E_i/c, Fij=−ϵijkBkF^{ij}=-\epsilon^{ijk}B_k, and Jμ=(cρ,j)J^\mu=(c\rho,\mathbf j). Then the sourced equation is ∂μFμν=μ0Jν\partial_\mu F^{\mu\nu}=\mu_0J^\nu. For the temporal choice of the free index, only the spatial derivatives survive and give ∇⋅E/c=μ0cρ\nabla\cdot\mathbf E/c=\mu_0c\rho. Since μ0ϵ0c2=1\mu_0\epsilon_0c^2=1, this is Gauss's electric law. One power of c comes from the field component and another from the current's time component; both are required.

For a spatial free index, the temporal derivative contributes minus the time derivative of E divided by c squared, while spatial derivatives produce the curl of B. Rearranging gives the Ampère–Maxwell law. The displacement-current term follows from the same tensor equation as electric Gauss law; it is not a separate correction chosen only for capacitors. In SI the common vacuum coefficients ensure the equations have one invariant propagation speed. Macroscopic material equations additionally require specified polarization, magnetization, and constitutive assumptions.

∂μFμν=μ0Jν⟺∇⋅E=ρϵ0,∇×B−1c2∂tE=μ0j\partial_\mu F^{\mu\nu}=\mu_0J^\nu\quad\Longleftrightarrow\quad \nabla\cdot\mathbf E=\frac{\rho}{\epsilon_0},\qquad \nabla\times\mathbf B-\frac{1}{c^2}\partial_t\mathbf E=\mu_0\mathbf j
These are microscopic vacuum-coefficient equations with total charge and current as sources. The derivative has units m⁻¹, F has units T, and mu0 J consequently has units T/m.↔ Scroll wide equations horizontally.

The homogeneous equation is a derivative identity

Write the second tensor statement using lower field indices: the cyclic sum of three derivatives vanishes. With three spatial indices it becomes zero magnetic divergence. With one temporal and two spatial indices it becomes Faraday's induction law, including its minus sign. This notation avoids introducing an additional orientation convention for the four-dimensional dual tensor. It uses the same lower components already established, especially F0i=+Ei/cF_{0i}=+E_i/c, so no new field convention is hiding in the compact expression.

If Fμν=∂μAν−∂νAμF_{\mu\nu}=\partial_\mu A_\nu-\partial_\nu A_\mu for a sufficiently smooth local potential, the cyclic identity follows because mixed derivatives commute. Thus the homogeneous equations are automatically satisfied by the potential representation, while the sourced equations determine its dynamics. This argument is local; nontrivial topology can require different potential patches. Magnetic monopoles, if introduced into a different theory, would modify this homogeneous structure. We assume ordinary Maxwell electrodynamics without magnetic charge throughout the present module.

∂αFβγ+∂βFγα+∂γFαβ=0⟺∇⋅B=0,∇×E+∂tB=0\partial_\alpha F_{\beta\gamma}+\partial_\beta F_{\gamma\alpha}+\partial_\gamma F_{\alpha\beta}=0\quad\Longleftrightarrow\quad \nabla\cdot\mathbf B=0,\qquad \nabla\times\mathbf E+\partial_t\mathbf B=0
The cyclic identity is the Bianchi identity for an electromagnetic field derived locally from a smooth potential. It contains no electric charge or current source terms.↔ Scroll wide equations horizontally.

Sources and initial data must be compatible

Take another divergence of the sourced equation. The derivative pair is symmetric, while the contracted field indices are antisymmetric, so ∂ν∂μFμν=0\partial_\nu\partial_\mu F^{\mu\nu}=0. It follows that ∂νJν=0\partial_\nu J^\nu=0. A proposed external current that violates local continuity cannot be a source for any solution of these Maxwell equations. Smoothness can be relaxed to distributions when derivatives are treated consistently, allowing point sources and idealized surfaces, but arbitrary inconsistency cannot be repaired by changing gauge.

There is also a useful initial-value interpretation. Electric Gauss law and zero magnetic divergence constrain an initial spatial slice, while the curl equations evolve the fields. Taking divergences of the evolution equations shows that compatible constraints remain satisfied when continuity holds. This does not remove the need for boundary conditions or supply an instantaneous action-at-a-distance solver. The tensor form guarantees consistent transformation between observers; constructing a particular physical solution still requires sources, initial data, boundaries, and an appropriate causal prescription.

A uniform changing electric field requires current

In an ideal local region let E=atx^\mathbf E=at\hat{\mathbf x} with a=2.00×106 V m−1 s−1a=2.00\times10^6\,\mathrm{V\,m^{-1}\,s^{-1}}, and let B vanish. Find compatible rho and j using ϵ0=8.85×10−12 F m−1\epsilon_0=8.85\times10^{-12}\,\mathrm{F\,m^{-1}}.

  1. The electric field has no spatial dependence, so its divergence vanishes. Gauss law requires ρ=0\rho=0 within the region, rather than a density proportional to the field's time derivative.

  2. The magnetic curl is zero. The sourced spatial equation therefore gives j=−ϵ0∂tE=−ϵ0ax^\mathbf j=-\epsilon_0\partial_t\mathbf E=-\epsilon_0a\hat{\mathbf x}. Numerically this is −1.77×10−5 A m−2x^-1.77\times10^{-5}\,\mathrm{A\,m^{-2}}\hat{\mathbf x}.

  3. The current is spatially uniform, so its divergence is zero, consistent with stationary zero density. Faraday law also holds because both the electric curl and the magnetic time derivative vanish. The assumed local fields need external boundary and preparation conditions for a physical realization.

The result

The compatible local sources are zero charge density and a constant current density of 17.7 microamperes per square metre along negative x.

Explore the model

Interactive lab

Interactive lab · fields

Inspect source-like and curl-like geometry

For a fresh run, Reset and set BOTH q = 1 and Ω = 0; predict a radial pattern. Then Reset and set q = 0 and Ω = 1; predict a circulating pattern with no radial arrows. Inspect paused patterns or Step before relating divergence and curl to the equations.

Inspect source-like and curl-like geometryThe softened illustration is q·r/(r² + 0.2) + Ω(−y, x). Moving markers indicate local direction, not integrated particle paths or a Maxwell solution. Current readings: Fx at (1, 0): 0.833; Fy at (1, 0): 0.5; Field magnitude there: 0.972. All parameters are adjustable with the labeled controls below.−3.2−1.601.63.2−1.5−0.7500.751.5xyq = 1
Local field directionSource strength
Fx at (1, 0)
0.833
Fy at (1, 0)
0.5
Field magnitude there
0.972
t = 0 s

The softened illustration is q·r/(r² + 0.2) + Ω(−y, x). Moving markers indicate local direction, not integrated particle paths or a Maxwell solution. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe softened planar field separates two geometric tendencies. It does not implement electric and magnetic fields, Maxwell evolution, displacement current, or boundary conditions.

Check your understanding

Why must a prescribed source satisfy local charge conservation in Maxwell theory?

Try it yourself

A static local field is E=kxx^\mathbf E=kx\hat{\mathbf x} with k=4.00×103 V m−2k=4.00\times10^3\,\mathrm{V\,m^{-2}}, and B = 0. Find rho and j, then check the temporal tensor equation explicitly. Use the same epsilon0 and c=3.00×108 m s−1c=3.00\times10^8\,\mathrm{m\,s^{-1}}.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The spatial derivative of E supplies charge; a field magnitude itself does not. Use F10, not F01, in the temporal equation.

Compare with the solution

The divergence is k, so ρ=ϵ0k=3.54×10−8 C m−3\rho=\epsilon_0k=3.54\times10^{-8}\,\mathrm{C\,m^{-3}}. The static zero magnetic field requires j=0\mathbf j=0. In tensor notation ∂1F10=k/c=1.33×10−5 T m−1\partial_1F^{10}=k/c=1.33\times10^{-5}\,\mathrm{T\,m^{-1}}. The source side is μ0cρ=ρ/(ϵ0c)=k/c\mu_0c\rho=\rho/(\epsilon_0c)=k/c, agreeing exactly within the chosen rounded constants. The homogeneous equations hold because this electric field has zero curl and the magnetic field vanishes.

Take it with you

  • The sourced tensor equation combines electric Gauss law with the displacement-current equation.
  • The cyclic derivative identity combines magnetic Gauss law with Faraday induction.
  • Maxwell evolution admits only sources and initial constraints that satisfy local compatibility.

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