Four-current and charge conservation
Transform charge and current density together, derive local continuity, and distinguish invariant total charge from observer-dependent density.
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The question for today
What you’ll understand
- Transform a four-current with consistent velocity and density units.
- Use local continuity to relate charge accumulation to boundary flux.
- Explain how invariant charge can coexist with frame-dependent charge density.
Charge is conserved, but a measured charge density changes when the observer changes. This is not a contradiction because density refers to a spatial volume measured at one observer's simultaneous time. The current density supplies the rest of the relativistic information. Combining both into a four-current makes local conservation transparent and prevents a common error: transforming a density while leaving the associated current unchanged. We will connect the tensor notation to charge flowing through an ordinary laboratory box.
Density and flux form one four-vector
Keep signature and . Define , with charge density rho in coulombs per cubic metre and current density j in amperes per square metre. Multiplying rho by c makes all four components share the latter units. Under a passive boost along x, J transforms exactly like any other four-vector. The density equation contains ; the current equation contains . Both combinations have the correct units before the common gamma factor is applied.
For one species moving with ordinary velocity v, its convection current is . If its proper density is , the four-current is . A mixture need not have any frame where total current vanishes. Oppositely charged populations can carry a net current while their total charge density cancels. Treat each population consistently before summing; using one species' rest density as if it were the net laboratory density is a frequent source of incorrect wire and beam calculations.
Continuity is a local spacetime statement
The four-divergence expands to because the c factors cancel in the temporal derivative. Setting it to zero says that charge can accumulate only when more charge enters a region than leaves. Integration over a fixed laboratory volume and the divergence theorem yield the boundary-flux version. The surface normal points outward, so positive outward flux decreases the enclosed charge. This sign is more reliable than a memorized verbal rule about incoming or outgoing current.
A total-charge statement alone would allow charge to vanish at one place and appear instantly elsewhere. Local continuity is stronger: intermediate transport must account for the change. For an isolated system, sufficiently rapid decay of current at spatial infinity gives a time-independent total charge in each inertial frame. Boundary assumptions matter. A finite open region can lose enclosed charge while obeying exact continuity; that does not violate charge conservation. The lost charge has simply crossed the chosen boundary.
Total charge needs a spatial slice
Relativistically, total charge is the flux of the four-current through a spacelike hypersurface. With the present normalization it is . On a constant-time slice this reduces to the familiar integral of rho over volume. Continuity makes the result independent of deformations of the slice when no current escapes through the side boundary. This is how different observers can agree on total isolated charge while disagreeing on the density and on which separated events are simultaneous.
A stationary uniform charge cloud illustrates the density effect simply. An observer moving along positive x sees the charges move along negative x, measures a density enhanced by gamma, and measures a negative x current. The cloud's contracted volume compensates for the density increase, leaving its total charge unchanged. For an infinite cloud, an infinite total charge is not a useful invariant number; the local transformation remains valid. Always distinguish local density calculations from finite-system global charge claims.
Work it through
Boost a stationary charged cloud
A finite cloud has uniform rest density and rest volume . A primed observer moves at along x. Find its density, current density, volume, and total charge. Use .
In the original rest frame and . Therefore . The charges move in the negative x direction for the primed observer.
The current is . Equivalently it is .
Only the dimension parallel to motion contracts, so the simultaneous primed volume is . Its total charge is , equal to the rest-frame value.
The moving observer measures higher density and a negative current, while the cloud still contains exactly 8 nC of charge.
The living notebook
Explore the model
Interactive lab · spacetime
The same boost mixes temporal and spatial components
For each fresh comparison, Reset and set BOTH β = 0, ct = 1, then Reset and set β = 0.6, ct = 1. Predict that the event's normalized component pair (1, 0.6) becomes (0.8, 0). This is the same algebra used to find the rest frame of a timelike current with jx/(cρ) = 0.6. Inspect paused readouts or Step.
- Lorentz factor γ
- 1.12
- Event x′
- 0.168
- Event ct′
- 0.817
A fixed x = 0.6 event is Lorentz transformed with c = 1. Playback highlights the relation between coordinate descriptions; it does not move the event. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe instrument transforms a fixed event, not an actual current or a charge cloud. Its normalized pair illustrates four-vector algebra and cannot display density, current, or a contracted volume.
Pause & reason
Check your understanding
Your turn
Try it yourself
In a one-dimensional slab , the current density is with , and the cross-sectional area is . Find the charge-density rate and enclosed-charge rate.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Differentiate the current density locally, then compare the result with the current leaving the right face minus that entering the left face.
Compare with the solution
The divergence is , so . The slab volume is , giving . The left-face current is zero, while the right-face outgoing current is , confirming the sign and magnitude. This is an instantaneous continuity calculation; the assumed current profile needs suitable sources or evolution to persist.
Keep the idea
Take it with you
- Charge density and current density are observer-dependent parts of one four-current.
- Local continuity accounts for charge changes through boundary transport.
- Invariant isolated charge requires consistent hypersurfaces and boundary conditions.
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