advanced26 min studyLesson 493 in Physics

Laue and Bragg diffraction conditions

Derive reciprocal-vector selection from coherent scattering, relate it to Bragg geometry, and separate geometrically allowed peaks from nonzero measured intensities.

On this page

What you’ll understand

  • Apply the elastic Laue condition with a declared momentum-transfer sign.
  • Convert between plane spacing, wavelength, Bragg angle, and scattering angle.
  • Identify finite-size and basis limits of a purely geometric diffraction prediction.

A diffraction pattern arises when waves scattered from many repeated cells add coherently. Reciprocal space expresses the phase-matching condition, while Bragg's law expresses the same condition through path differences between lattice planes. We will keep the angular wavevector convention and distinguish the angle measured from a plane from the full scattering angle. This prevents two common errors: losing a factor of two pi and confusing theta with twice theta.

Coherent lattice phases select reciprocal vectors

Choose incident and outgoing probe wavevectors with magnitude 2π/λ2\pi/\lambda for elastic scattering, and define momentum transfer Q=kout−kin\mathbf Q=\mathbf k_{\mathrm{out}}-\mathbf k_{\mathrm{in}}. The lattice amplitude contains a sum of phase factors over translation vectors. Large constructive peaks occur when each translation changes the phase by an integer multiple of two pi, giving Q equal to a reciprocal lattice vector. Reversing the definition of Q changes its sign but leaves the set of candidate reciprocal peaks unchanged because the lattice contains both G and minus G.

Elasticity adds an independent constraint: incoming and outgoing wavevectors have equal magnitude. Combining it with Q equal to G gives the Ewald-sphere geometry. A reciprocal point must be accessible for the chosen incident wavelength and orientation, not merely exist somewhere in reciprocal space. Rotating a single crystal or using many powder orientations can bring different points onto the elastic sphere. The Laue condition is therefore a selection rule within a scattering setup, rather than a promise that one fixed exposure records every reciprocal vector.

Q=kout−kin=G,∣kin∣=∣kout∣=2πλ,2kin⋅G+G2=0\mathbf Q=\mathbf k_{\mathrm{out}}-\mathbf k_{\mathrm{in}}=\mathbf G,\qquad |\mathbf k_{\mathrm{in}}|=|\mathbf k_{\mathrm{out}}|=\frac{2\pi}{\lambda},\qquad 2\mathbf k_{\mathrm{in}}\cdot\mathbf G+G^2=0
These equations describe elastic coherent diffraction with our outgoing-minus-incoming transfer convention. Wavevectors have inverse-length units; the physical probe momentum transfer is hbar times Q.↔ Scroll wide equations horizontally.

Plane geometry gives Bragg's law

For a family of parallel planes separated by d, waves reflected from successive planes have path difference 2dsin⁡θ2d\sin\theta, where theta is the grazing angle measured from the planes. Constructive interference requires that difference to be an integer number n of wavelengths. The angle between the incident and outgoing beams is twice theta. With our reciprocal convention the fundamental plane-normal vector has magnitude two pi divided by d, and its nth harmonic supplies the nth diffraction order.

In a cubic cell, plane spacing indexed by h, k, l is the conventional edge divided by the square root of the sum of their squares. This simple formula depends on cubic metric geometry and cannot be copied unchanged for an oblique cell. Bragg order and Miller indices also overlap in their description: an nth-order reflection of one plane family can be indexed as the first-order reflection of multiplied indices. Count the physical reciprocal vector once, rather than treating these two descriptions as different scattered beams.

2dsin⁡θ=nλ,∣Q∣=22πλsin⁡θ=2πnd,dhkl=ach2+k2+l2for cubic indexing2d\sin\theta=n\lambda,\qquad |\mathbf Q|=2\frac{2\pi}{\lambda}\sin\theta=\frac{2\pi n}{d},\qquad d_{hkl}=\frac{a_{\mathrm c}}{\sqrt{h^2+k^2+l^2}}\quad\text{for cubic indexing}
Theta is measured from the planes and the full scattering angle is 2 theta. Wavelength and d use the same length units. A Bragg order is geometrically inaccessible when n lambda exceeds 2d.↔ Scroll wide equations horizontally.

Geometry is only part of an observed peak

A finite crystal produces peaks of finite width rather than exact reciprocal delta functions. A longer coherent array gives a narrower principal peak because its phase sum tolerates a smaller mismatch before cancellation. Atomic form factors, basis interference, polarization, thermal motion, and experimental geometry affect intensity. The next lesson examines exact basis cancellations. Until then, distinguish a reflection that is geometrically accessible from one with a nonzero scattering amplitude under the chosen probe and crystal structure.

The derivation assumes coherent scattering and a kinematic single-scattering treatment. Strong multiple scattering can redistribute intensity and requires dynamical diffraction theory. Inelastic neutron or x-ray scattering also transfers energy, changing the equal-wavevector-magnitude condition and revealing lattice vibrations. These processes are not failures of reciprocal reasoning: they use additional energy and momentum accounting. For basic elastic indexing, however, the safest procedure is to compute the reciprocal vector, check the wavelength constraint, assign the correct angular geometry, and only then evaluate its structure factor.

Find a Bragg angle and accessible orders

A plane family has spacing d = 0.20 nm and is illuminated elastically with wavelength 0.20 nm. Find the first-order Bragg and scattering angles, the first-order momentum-transfer magnitude, and the highest geometrically allowed order.

  1. For first order, sin⁡θ=λ/(2d)=0.20/0.40=1/2\sin\theta=\lambda/(2d)=0.20/0.40=1/2. Thus the grazing Bragg angle is 30 degrees and the full beam scattering angle is 60 degrees.

  2. The transfer magnitude is 2π/d=10π nm−12\pi/d=10\pi\,\mathrm{nm^{-1}}. Equivalently it is twice the incident magnitude times the sine of the Bragg angle, giving the same angular-wavevector units.

  3. Accessibility requires nλ≤2dn\lambda\le2d, so n can be at most 2. That second order has theta equal to 90 degrees and corresponds to the exact backscattering limit; orders above two require an impossible sine.

The result

The first-order beam scatters through 60 degrees with transfer 10 pi per nanometre. Second order is the limiting geometrically allowed backscattering case.

Explore the model

Interactive lab

Interactive lab · waves

Phase alignment controls coherent addition

Reset and set BOTH Phase difference = 0° and Amplitude ratio = 1; predict a doubled sum amplitude. For a fresh run, Reset and set Phase difference = 180° and Amplitude ratio = 1; predict cancellation. Inspect the waveform or Play each independently reset run.

Phase alignment controls coherent additionTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe lab adds two equal-frequency co-propagating sine waves. It illustrates coherent phase addition, not a lattice diffraction calculation, adjustable wavelength, reciprocal-space scan, or phonon dispersion.

Check your understanding

In Bragg's law as used here, what is the angle between the incident and outgoing beams?

Try it yourself

A cubic crystal has conventional edge 0.60 nm. For a geometrically considered (200) reflection and wavelength 0.30 nm, calculate plane spacing, first-order Bragg angle, and full scattering angle. What information is still needed before predicting a visible peak?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the cubic plane-spacing metric first. The Laue and Bragg conditions do not calculate the basis amplitude.

Compare with the solution

The spacing is d200=0.60/4=0.30 nmd_{200}=0.60/\sqrt4=0.30\,\mathrm{nm}. First order gives sin⁡θ=0.30/(2×0.30)=1/2\sin\theta=0.30/(2\times0.30)=1/2, so theta is 30 degrees and the full scattering angle is 60 degrees. A visible peak additionally requires nonzero structure factor and appropriate probe intensity and geometry. This calculation establishes accessibility, not whether an unknown cubic basis extinguishes the (200) amplitude.

Take it with you

  • Elastic diffraction requires reciprocal phase matching and equal incoming and outgoing wavevector magnitudes.
  • Bragg angle and full scattering angle differ by a factor of two.
  • Accessible reciprocal geometry does not guarantee nonzero diffraction intensity.

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