advanced27 min studyLesson 494 in Physics

Structure factors and extinction rules

Compute coherent basis amplitudes, derive centring absences, and distinguish exact symmetry cancellations from weak peaks caused by chemical contrast or form factors.

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What you’ll understand

  • Add scattering amplitudes with their basis phases before squaring.
  • Derive conventional bcc and fcc reflection conditions.
  • Explain when chemical inequivalence removes an apparent extinction.

Reciprocal geometry selects candidate diffraction peaks, but a crystal's motif decides whether their amplitudes survive. Waves scattered by different atoms within one repeated cell can cancel exactly. The structure factor makes that cancellation calculable and shows why intensities must be found from the square of a coherent sum. We will distinguish genuine centring absences from a superficially similar two-species structure whose odd reflections remain visible.

Factor the lattice sum from the motif

For atomic positions R plus tau, the kinematic elastic amplitude separates into a translation sum and a basis factor. Define S(G)=∑sfs(G)eiG⋅τsS(\mathbf G)=\sum_s f_s(\mathbf G)e^{i\mathbf G\cdot\boldsymbol\tau_s}, choosing the plus phase convention for the basis amplitude. Its complex conjugate convention gives the same intensity for the simple real form factors used here. The atomic factor f includes the probe's scattering response, while the phase includes the atom's position. Sum those complex amplitudes first; summing their individual intensities would erase interference.

The intensity contains the modulus squared of S multiplied by the lattice peak envelope and experimental factors. X-ray atomic factors generally depend on wavevector magnitude and electronic structure, while neutron scattering lengths have different species and isotope dependence. Thus a motif's geometric phases alone do not set every relative intensity. We will hold the atomic factors constant in the hand calculations to isolate interference. Exact extinction means an amplitude is forced to vanish under the stated symmetry and contrast assumptions, not merely that the measured peak is too weak to detect.

A(Q)∝(∑ℓeiQ⋅Rℓ)S(Q),S(Q)=∑sfs(Q)eiQ⋅τs,I∝∣A∣2A(\mathbf Q)\propto\left(\sum_\ell e^{i\mathbf Q\cdot\mathbf R_\ell}\right)S(\mathbf Q),\qquad S(\mathbf Q)=\sum_s f_s(\mathbf Q)e^{i\mathbf Q\cdot\boldsymbol\tau_s},\qquad I\propto|A|^2
This factorization assumes coherent elastic single scattering from repeated motifs. Atomic scattering amplitudes share compatible units; only consistently normalized intensity ratios are inferred below.↔ Scroll wide equations horizontally.

Conventional-cell centring produces parity rules

Represent an identical-atom bcc arrangement using a conventional simple-cubic grid and offsets zero and half the body diagonal. For G=(2π/ac)(h,k,l)\mathbf G=(2\pi/a_c)(h,k,l), their phase difference is pi times the sum of the three indices. Even sums add and odd sums cancel. The conventional grid is deliberately nonprimitive for bcc: the extinction rule removes candidate simple-cubic reciprocal points that are not reciprocal vectors of the true bcc Bravais lattice. It does not mean the true primitive reciprocal lattice has arbitrary missing points.

The conventional fcc cell has offsets zero and the three face-centre representatives. Its structure factor is f times one plus three parity factors. All indices even or all odd give constructive addition; mixed parity cancels. A further motif can impose additional absences beyond this centring rule. For example, a diamond-type two-atom motif on an fcc Bravais lattice adds another phase factor. One should apply the Bravais selection and motif amplitude consistently rather than mixing a primitive reciprocal indexing scheme with a conventional cubic parity rule.

Sbcc=f[1+(−1)h+k+l],Sfcc=f[1+(−1)h+k+(−1)h+l+(−1)k+l]S_{\mathrm{bcc}}=f[1+(-1)^{h+k+l}],\qquad S_{\mathrm{fcc}}=f[1+(-1)^{h+k}+(-1)^{h+l}+(-1)^{k+l}]
These expressions use conventional cubic hkl indices and identical scattering factors. Bcc requires an even index sum; fcc requires all three indices to have the same parity. They are amplitudes, whose squares determine the corresponding intensity factors.↔ Scroll wide equations horizontally.

Chemical contrast can reveal a lost translation

Now place different atoms at the corner and body-centre offsets. The amplitude becomes fA+(−1)h+k+lfBf_A+(-1)^{h+k+l}f_B. Odd sums give a difference instead of zero unless the two scattering factors happen to match. This CsCl-type decoration has a simple-cubic Bravais lattice with a two-atom basis, rather than an identical-atom bcc Bravais lattice. The apparent extinction has disappeared because the body-centred translation no longer preserves chemical identity. A probe with accidentally equal contrasts can still hide that distinction.

Observed violations of an ideal absence can also involve defects, partial occupation, disorder, multiple scattering, or experimental contamination. Conversely, an allowed peak can be weak because form factors or thermal motion suppress it. Diffraction inference therefore combines systematic peak locations, relative intensities, probe contrast, and assumptions about the scattering regime. A single missing spot rarely identifies a unique structure by itself. The quantitative structure-factor calculation is valuable because it states exactly which equality of phases and amplitudes is being tested and what changes would remove the cancellation.

Two conventional bcc reflections

An identical-atom bcc structure has constant real atomic factor f = 2 in common amplitude units. Compute the conventional-cell structure factors and intensity factors for (110) and (100), ignoring all other experimental factors.

  1. For (110), the index sum is two, so the body-centre phase is ei2π=1e^{i2\pi}=1. The corner and centre amplitudes therefore add with the same phase.

  2. The (110) structure factor is S=2(1+1)=4S=2(1+1)=4, giving ∣S∣2=16|S|^2=16 in the corresponding squared-amplitude units. It would be wrong to add two atomic intensities and obtain eight.

  3. For (100), the index sum is one, so the relative phase is minus one. The structure factor is 2(1−1)=02(1-1)=0, and its ideal kinematic intensity factor vanishes despite geometric accessibility on the conventional cubic reciprocal grid.

The result

The (110) amplitude is 4 with intensity factor 16, while (100) is exactly extinct under the identical-atom and single-scattering assumptions.

Explore the model

Interactive lab

Interactive lab · waves

Unequal amplitudes prevent complete cancellation

Reset and set BOTH Phase difference = 180° and Amplitude ratio = 1; predict a zero sum. For a fresh comparison, Reset and set Phase difference = 180° and Amplitude ratio = 0.5; predict a residual sinusoid with amplitude 0.5. Inspect the waveform or Play each reset run.

Unequal amplitudes prevent complete cancellationTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe equal-frequency two-wave sum illustrates basis interference and unequal contrast. It does not calculate hkl phases, atomic factors, lattice diffraction intensities, or phonon bands.

Check your understanding

Which conventional cubic reflection can survive identical-atom fcc centring?

Try it yourself

A CsCl-type two-species basis has fA=3f_A=3 and fB=1f_B=1 in common real amplitude units. Calculate the (100) and (200) structure factors and their ideal intensity ratio I100/I200. Why is (100) not required to vanish?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Odd sums subtract the two species amplitudes, while even sums add them. Chemical identity changes the primitive translation symmetry.

Compare with the solution

For (100), S=fA−fB=2S=f_A-f_B=2, so its intensity factor is 4. For (200), S=fA+fB=4S=f_A+f_B=4, giving intensity factor 16. The ratio is therefore 1/41/4 under the constant-factor assumptions. The two species are inequivalent, so a body-centred translation is not a symmetry of the decorated crystal. Exact cancellation would occur only if this probe had equal factors for the two sites, which is an additional contrast condition rather than a geometric necessity.

Take it with you

  • Diffraction interference requires summing complex amplitudes before squaring.
  • Conventional centring absences encode the true primitive translation lattice.
  • Different species or probe contrasts can remove cancellations that identical atoms would produce.

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