advanced30 min studyLesson 215 in Physics

Diffraction gratings and resolving power

Sum a finite array of slit amplitudes and derive spectral resolving power separately from angular dispersion and order efficiency.

On this page

What you’ll understand

  • Derive the principal orders of a normally illuminated grating.
  • Relate the first array minimum to ideal spectral resolution.
  • Distinguish line density, illuminated groove count, and order overlap.

A diffraction grating uses many equally spaced contributions to concentrate light into narrow angular peaks. Different wavelengths put those peaks at different angles, which turns the device into a spectrometer. Closely separated wavelengths are resolved only when their peak displacement competes successfully with the finite width of each peak. Large angular dispersion helps, but the illuminated number of grooves controls that peak width and is equally necessary in the resolution argument.

A finite geometric series creates sharp orders

Consider NN identical slits separated by pitch dd, illuminated coherently at normal incidence. In far-field direction θ\theta, adjacent slit contributions have phase difference of magnitude β=2πdsin⁡θ/λ\beta=2\pi d\sin\theta/\lambda. Using the negative sign appropriate to the aperture-transform convention, the array amplitude is a finite sum of e−ijβe^{-ij\beta}. Summing the geometric progression produces a sine ratio times an overall phase, which disappears from intensity.

Principal maxima occur when adjacent phases agree modulo 2π2\pi. Their amplitudes are NN times the contribution of one slit and their intensities N2N^2 times its intensity in that direction. This does not violate energy conservation: coherent addition narrows and redistributes the pattern. The finite width and transmission of each slit impose a separate envelope. A mathematically permitted grating order can be weak or entirely missing when that envelope has a zero there.

β=2πdsin⁡θλ,IN(θ)Ione(θ)=[sin⁡(Nβ/2)sin⁡(β/2)]2,dsin⁡θm=mλ\beta=\frac{2\pi d\sin\theta}{\lambda},\qquad \frac{I_N(\theta)}{I_{\mathrm{one}}(\theta)}=\left[\frac{\sin(N\beta/2)}{\sin(\beta/2)}\right]^2,\qquad d\sin\theta_m=m\lambda
d and lambda are lengths, theta is the outgoing angle from the normal, m is an integer diffraction order, and N is the coherently illuminated slit count. The apparent zero-over-zero at a principal order has limit N². These formulas assume normal incidence and identical equally spaced apertures.↔ Scroll wide equations horizontally.

Derive resolution from width and displacement

Near a principal order, the first array zero occurs when the adjacent phase changes by 2π/N2\pi/N. Converting that phase difference to angle gives a one-sided peak width approximately λ/(Ndcos⁡θm)\lambda/(Nd\cos\theta_m). Differentiating the grating equation at fixed order gives angular dispersion m/(dcos⁡θm)m/(d\cos\theta_m). Both quantities grow near grazing propagation, so the angular magnification by itself does not give a free improvement in spectral resolving power.

For two narrow mutually incoherent spectral lines with comparable brightness, the Rayleigh convention places one peak at the first zero of the other. Equating displacement and one-sided width yields resolving power ∣m∣N|m|N. It is an ideal instrument criterion, not a universal theorem about detectability. A finite entrance slit, aberrations, pixel sampling, background, and line-shape fitting can change practical performance. The zero order has no wavelength dispersion and cannot use this spectral-resolution formula as a positive resolving power.

Δθzero≃λNdcos⁡θm,dθmdλ=mdcos⁡θm,R=λΔλ≃∣m∣N\Delta\theta_{\mathrm{zero}}\simeq\frac{\lambda}{Nd\cos\theta_m},\quad \frac{d\theta_m}{d\lambda}=\frac{m}{d\cos\theta_m},\quad \mathcal R=\frac{\lambda}{\Delta\lambda}\simeq |m|N
Angles and angular widths are in radians; the derivative has units rad/m. The small-separation Rayleigh estimate assumes a propagating nonzero order, many coherently illuminated grooves, negligible instrumental broadening, and narrow incoherent spectral lines.↔ Scroll wide equations horizontally.

Separate groove density from usable information

At fixed illuminated physical width, more grooves per millimetre increase the number of illuminated grooves and change the accessible orders. At fixed total groove count instead, changing pitch changes dispersion but leaves the ideal resolving power of a chosen order unchanged. A specification stating only groove density therefore does not determine resolution. The beam footprint, incidence geometry, and usable order must also be known before counting effective contributions.

Different order-wavelength pairs can satisfy the same grating equation. For example, first-order light at one wavelength overlaps second-order light at half that wavelength. This ambiguity requires spectral filtering or another dispersive stage; sharper peaks alone cannot remove it. A blazed groove profile redistributes efficiency among orders but does not replace the finite-aperture resolution argument. Always distinguish order location, order brightness, and order width when interpreting a grating spectrum.

A five-millimetre illuminated grating

A transmission grating has 600 grooves per millimetre and a uniformly illuminated width of 5.0 mm5.0\,\mathrm{mm}. At normal incidence, estimate the first-order angle and ideal Rayleigh wavelength separation near 500 nm500\,\mathrm{nm}. Assume the slit envelope transmits the order.

  1. Convert line density to pitch: d=(600 mm−1)−1=1.667 μmd=(600\,\mathrm{mm^{-1}})^{-1}=1.667\,\mathrm{\mu m}. The illuminated count is N=600×5.0=3000N=600\times5.0=3000, ignoring endpoint rounding at this precision.

  2. For m=1m=1, the grating equation gives sin⁡θ=0.500/1.667=0.300\sin\theta=0.500/1.667=0.300. Thus θ≃17.46∘\theta\simeq17.46^\circ, a propagating order well away from the grazing limit.

  3. The ideal resolving power is ∣m∣N=3000|m|N=3000. Therefore Δλ≃500/3000=0.167 nm\Delta\lambda\simeq500/3000=0.167\,\mathrm{nm}. This uses the full illuminated groove count, not the numerical density alone.

The result

The first order is near 17.46° and the ideal Rayleigh separation is about 0.167 nm, before other spectrometer broadening.

Explore the model

Interactive lab

Interactive lab · spectral

More modes create finer structure

For each fresh run, Reset and set BOTH Mode count N and Coefficient decay p. Compare N=3 and N=12 at p=0, predicting additional small spatial features, then Step. This instrument sums sin(nx−t)/n^p; its N counts Fourier modes, not illuminated grooves, and its curve is not a grating intensity.

More modes create finer structureA finite sum of sin(nx − t)/nᵖ. Playback changes t; increasing the cutoff includes finer spatial scales. This is not a proof about a continuum limit or renormalization. Current readings: Sum at x = π/2: 0.867; Smallest wavelength: 2π / 5; Highest-mode coefficient: 0.2. All parameters are adjustable with the labeled controls below.01.573.144.716.28−2.56−1.2801.282.56x · radiansFinite sine sum
Finite sumHighest included mode
Sum at x = π/2
0.867
Smallest wavelength
2π / 5
Highest-mode coefficient
0.2
t = 0 s

A finite sum of sin(nx − t)/nᵖ. Playback changes t; increasing the cutoff includes finer spatial scales. This is not a proof about a continuum limit or renormalization. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forFinite sums can create fine spatial structure, but this lab does not measure grating resolving power, principal-order widths, or spectral line separation.

Check your understanding

Two ideal gratings illuminate the same number of grooves in the same nonzero order. One has twice the groove density. Which statement follows for λ/Δλ under the stated Rayleigh model?

Try it yourself

A normally illuminated grating has pitch 2.0 μm2.0\,\mathrm{\mu m}. Near 600 nm600\,\mathrm{nm}, what minimum illuminated groove count and width give ideal Rayleigh separation 0.10 nm0.10\,\mathrm{nm} in second order? Check that the order propagates.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Determine required resolving power, divide by the order, then multiply the groove count by pitch. Test the sine in the grating equation separately.

Compare with the solution

The target resolving power is 600/0.10=6000600/0.10=6000. With ∣m∣=2|m|=2, the ideal minimum count is N=3000N=3000. The illuminated width is approximately Nd=3000(2.0 μm)=6.0 mmNd=3000(2.0\,\mathrm{\mu m})=6.0\,\mathrm{mm}. The order satisfies sin⁡θ=2(0.600)/2.0=0.600\sin\theta=2(0.600)/2.0=0.600, so it propagates at about 36.87∘36.87^\circ. This is an ideal lower bound on the necessary footprint; an actual entrance slit or aberrated optic can demand a wider footprint or prevent the requested resolution altogether.

Take it with you

  • Principal-order positions come from phase agreement between neighbouring grooves.
  • Ideal spectral resolving power depends on order times illuminated groove count.
  • Order overlap and diffraction efficiency are separate from peak width.

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