advanced30 min studyLesson 214 in Physics

Double-slit visibility and path information

Relate fringe contrast to amplitude balance, mutual coherence, polarization overlap, and explicitly defined path-marker distinguishability.

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What you’ll understand

  • Calculate visibility without assuming equal slit intensities.
  • Identify which averaged cross term a detector actually measures.
  • State the assumptions behind a path-distinguishability equality.

Two open slits do not guarantee high-contrast fringes. The detector must receive overlapping fields with a stable enough relative phase, compatible polarization, and sufficient intensity balance. Quantum path markers add another possibility: a record correlated with the path can reduce interference in an unconditioned measurement. These mechanisms share related mathematics, but measuring low visibility alone does not identify which mechanism caused it or establish that a path measurement occurred.

A detector averages the cross term

Let the two scalar detector fields include the same polarization and geometry, and define their mutual coherence by a time or ensemble average. The detector averages a squared field over many optical cycles. Expanding that square leaves two individual intensities and a complex cross correlation. Scanning an extra phase changes the real part of the cross term while leaving the individual intensities fixed. Its magnitude determines the possible contrast if the envelopes vary negligibly during the scan.

Define γ12=⟨U1∗U2⟩/⟨∣U1∣2⟩⟨∣U2∣2⟩\gamma_{12}=\langle U_1^*U_2\rangle/\sqrt{\langle|U_1|^2\rangle\langle|U_2|^2\rangle} for the scalar phasor envelopes U1,U2U_1,U_2. Cauchy–Schwarz bounds its magnitude by one. Temporal fluctuations, extended-source spatial incoherence, or uncontrolled phase drift can reduce that magnitude. Orthogonal vector polarizations make the vector cross term vanish even for otherwise coherent waves. One may factor temporal coherence and polarization overlap only when the statistical and polarization assumptions actually allow that separation.

I(ϕ)=I1+I2+2I1I2 ∣γ12∣cos⁡(ϕ+arg⁡γ12),V=Imax⁡−Imin⁡Imax⁡+Imin⁡=2I1I2∣γ12∣I1+I2I(\phi)=I_1+I_2+2\sqrt{I_1I_2}\,|\gamma_{12}|\cos(\phi+\arg\gamma_{12}),\qquad V=\frac{I_{\max}-I_{\min}}{I_{\max}+I_{\min}}=\frac{2\sqrt{I_1I_2}|\gamma_{12}|}{I_1+I_2}
I1 and I2 are irradiances in W/m² at the detector, gamma12 is dimensionless normalized first-order coherence, and phi is a controlled phase in radians. The scan assumes fixed local envelopes and a linear detector with no added background.↔ Scroll wide equations horizontally.

Balance and coherence are independent limitations

Even perfectly coherent fields cannot cancel completely if their magnitudes differ. For an amplitude ratio aa, the visibility is 2a/(1+a2)2a/(1+a^2) when the polarizations match. Taking one slit almost dark drives visibility toward zero, despite perfect relative-phase stability. Conversely, equal mean intensities do not imply full contrast: a fluctuating phase can wash out the average pattern while each short-time realization remains strongly modulated.

Finite slit widths multiply the two-slit modulation by a diffraction envelope, and distant fringes may sample unequal envelope values. Visibility should therefore be interpreted locally or through a controlled phase scan. Stray light and detector dark offsets raise the minimum without being a fundamental coherence effect. Before interpreting a contrast measurement, measure the individual slit signals and background separately, using the same collection geometry and integration time as the interference measurement.

Path records need a stated discrimination task

For an ideal balanced coherent two-path quantum input with normalized pure marker states ∣d1⟩|d_1\rangle and ∣d2⟩|d_2\rangle, ignoring the marker multiplies the interference cross term by their overlap. The unconditioned visibility is the magnitude of that overlap. Here distinguishability means the optimal advantage in guessing which marker state was prepared, with equal prior probabilities. It is not a vague statement about how much someone happens to know.

Under those pure-state, balanced, otherwise ideal assumptions, visibility and optimal distinguishability obey an equality. Mixed markers, additional dephasing, or imperfect collection generally permit an inequality instead; unequal priors require an appropriately defined discrimination problem. Measuring a marker in another basis and selecting subensembles may reveal conditional fringes, but adding those subensembles restores the original unconditioned result. Human attention is not the mechanism: correlations and averaging are.

s=⟨d1∣d2⟩,V=∣s∣,D=1−∣s∣2,D2+V2=1s=\langle d_1|d_2\rangle,\qquad V=|s|,\qquad D=\sqrt{1-|s|^2},\qquad D^2+V^2=1
s is the pure marker overlap and D is the equal-prior optimal discrimination distinguishability. This equality assumes balanced coherent paths, pure markers, ideal recombination and no other contrast loss; the more general duality statement is an inequality with carefully defined D.↔ Scroll wide equations horizontally.

Unequal slit amplitudes

At a chosen screen point the separate slit irradiances are 99 and 4 W/m24\,\mathrm{W/m^2}. The fields have matching polarization and ∣γ12∣=0.50|\gamma_{12}|=0.50. A phase shifter scans a complete fringe. Find the maximum, minimum, and visibility, with no detector background.

  1. The baseline is I1+I2=13 W/m2I_1+I_2=13\,\mathrm{W/m^2}. The geometric mean is 9×4=6 W/m2\sqrt{9\times4}=6\,\mathrm{W/m^2}, which uses field amplitudes rather than the arithmetic intensity mean.

  2. The oscillating cross-term amplitude is 2(6)(0.50)=6 W/m22(6)(0.50)=6\,\mathrm{W/m^2}. The cosine can reach plus and minus one, so the measured extrema are 19 and 7 W/m27\,\mathrm{W/m^2}.

  3. Form the contrast from the extrema: V=(19−7)/(19+7)=12/26=6/13≃0.462V=(19-7)/(19+7)=12/26=6/13\simeq0.462. Equivalently the modulation amplitude divided by the baseline is 6/136/13.

The result

The scan ranges from 7 to 19 W/m² and has visibility about 0.462; coherence magnitude alone is not the visibility for unequal intensities.

Explore the model

Interactive lab

Interactive lab · waves

Amplitude balance limits cancellation

For each comparison, Reset and set BOTH Phase difference and Amplitude ratio. With ratio 0.50, compare 0° and 180°, predicting intensity proxies 2.25 and 0.25 from squared sum amplitudes. Then repeat both phases with ratio 1. Play shows coherent equal-frequency waves; the lab has no coherence, marker, or detector-noise control.

Amplitude balance limits cancellationTwo waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Current readings: Sum at x = 0: 0.866; Resultant amplitude: 1.732; Phase difference: 60°. All parameters are adjustable with the labeled controls below.−3.14−1.5701.573.14−3.4−1.701.73.4x · radiansAmplitude
SumFirst componentSecond component
Sum at x = 0
0.866
Resultant amplitude
1.732
Phase difference
60°
t = 0 s

Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe lab can test amplitude imbalance and phase cancellation, but cannot model partial coherence, path records, or measurement collapse.

Check your understanding

In the ideal balanced pure-marker model, two orthogonal path-marker states are ignored at detection. What is the unconditioned visibility?

Try it yourself

A balanced ideal two-path experiment has pure marker overlap magnitude 0.800.80. Calculate its unconditioned visibility, optimal equal-prior distinguishability, and optimal marker-guessing success probability. Assume no extra dephasing.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use the pure-state equality for D, then relate the discrimination advantage to success probability through (1+D)/2(1+D)/2.

Compare with the solution

The visibility is the overlap magnitude, V=0.80V=0.80. The distinguishability is D=1−0.802=0.36=0.60D=\sqrt{1-0.80^2}=\sqrt{0.36}=0.60. For equal priors the best marker-state guessing succeeds with probability (1+0.60)/2=0.80(1+0.60)/2=0.80. Thus DD is not itself the success probability. The check 0.602+0.802=10.60^2+0.80^2=1 confirms the ideal equality. If an independent noisy phase reduced visibility while leaving these marker states fixed, this marker discrimination would remain the same and the equality would become a strict inequality.

Take it with you

  • Visibility depends on both mutual coherence and local intensity balance.
  • Low contrast alone does not identify path information as its cause.
  • Pure-marker complementarity needs explicit priors, state purity, and collection assumptions.

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