Double-slit visibility and path information
Relate fringe contrast to amplitude balance, mutual coherence, polarization overlap, and explicitly defined path-marker distinguishability.
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The question for today
What you’ll understand
- Calculate visibility without assuming equal slit intensities.
- Identify which averaged cross term a detector actually measures.
- State the assumptions behind a path-distinguishability equality.
Two open slits do not guarantee high-contrast fringes. The detector must receive overlapping fields with a stable enough relative phase, compatible polarization, and sufficient intensity balance. Quantum path markers add another possibility: a record correlated with the path can reduce interference in an unconditioned measurement. These mechanisms share related mathematics, but measuring low visibility alone does not identify which mechanism caused it or establish that a path measurement occurred.
A detector averages the cross term
Let the two scalar detector fields include the same polarization and geometry, and define their mutual coherence by a time or ensemble average. The detector averages a squared field over many optical cycles. Expanding that square leaves two individual intensities and a complex cross correlation. Scanning an extra phase changes the real part of the cross term while leaving the individual intensities fixed. Its magnitude determines the possible contrast if the envelopes vary negligibly during the scan.
Define for the scalar phasor envelopes . Cauchy–Schwarz bounds its magnitude by one. Temporal fluctuations, extended-source spatial incoherence, or uncontrolled phase drift can reduce that magnitude. Orthogonal vector polarizations make the vector cross term vanish even for otherwise coherent waves. One may factor temporal coherence and polarization overlap only when the statistical and polarization assumptions actually allow that separation.
Balance and coherence are independent limitations
Even perfectly coherent fields cannot cancel completely if their magnitudes differ. For an amplitude ratio , the visibility is when the polarizations match. Taking one slit almost dark drives visibility toward zero, despite perfect relative-phase stability. Conversely, equal mean intensities do not imply full contrast: a fluctuating phase can wash out the average pattern while each short-time realization remains strongly modulated.
Finite slit widths multiply the two-slit modulation by a diffraction envelope, and distant fringes may sample unequal envelope values. Visibility should therefore be interpreted locally or through a controlled phase scan. Stray light and detector dark offsets raise the minimum without being a fundamental coherence effect. Before interpreting a contrast measurement, measure the individual slit signals and background separately, using the same collection geometry and integration time as the interference measurement.
Path records need a stated discrimination task
For an ideal balanced coherent two-path quantum input with normalized pure marker states and , ignoring the marker multiplies the interference cross term by their overlap. The unconditioned visibility is the magnitude of that overlap. Here distinguishability means the optimal advantage in guessing which marker state was prepared, with equal prior probabilities. It is not a vague statement about how much someone happens to know.
Under those pure-state, balanced, otherwise ideal assumptions, visibility and optimal distinguishability obey an equality. Mixed markers, additional dephasing, or imperfect collection generally permit an inequality instead; unequal priors require an appropriately defined discrimination problem. Measuring a marker in another basis and selecting subensembles may reveal conditional fringes, but adding those subensembles restores the original unconditioned result. Human attention is not the mechanism: correlations and averaging are.
Work it through
Unequal slit amplitudes
At a chosen screen point the separate slit irradiances are and . The fields have matching polarization and . A phase shifter scans a complete fringe. Find the maximum, minimum, and visibility, with no detector background.
The baseline is . The geometric mean is , which uses field amplitudes rather than the arithmetic intensity mean.
The oscillating cross-term amplitude is . The cosine can reach plus and minus one, so the measured extrema are 19 and .
Form the contrast from the extrema: . Equivalently the modulation amplitude divided by the baseline is .
The scan ranges from 7 to 19 W/m² and has visibility about 0.462; coherence magnitude alone is not the visibility for unequal intensities.
The living notebook
Explore the model
Interactive lab · waves
Amplitude balance limits cancellation
For each comparison, Reset and set BOTH Phase difference and Amplitude ratio. With ratio 0.50, compare 0° and 180°, predicting intensity proxies 2.25 and 0.25 from squared sum amplitudes. Then repeat both phases with ratio 1. Play shows coherent equal-frequency waves; the lab has no coherence, marker, or detector-noise control.
- Sum at x = 0
- 0.866
- Resultant amplitude
- 1.732
- Phase difference
- 60°
Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe lab can test amplitude imbalance and phase cancellation, but cannot model partial coherence, path records, or measurement collapse.
Pause & reason
Check your understanding
Your turn
Try it yourself
A balanced ideal two-path experiment has pure marker overlap magnitude . Calculate its unconditioned visibility, optimal equal-prior distinguishability, and optimal marker-guessing success probability. Assume no extra dephasing.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use the pure-state equality for D, then relate the discrimination advantage to success probability through .
Compare with the solution
The visibility is the overlap magnitude, . The distinguishability is . For equal priors the best marker-state guessing succeeds with probability . Thus is not itself the success probability. The check confirms the ideal equality. If an independent noisy phase reduced visibility while leaving these marker states fixed, this marker discrimination would remain the same and the equality would become a strict inequality.
Keep the idea
Take it with you
- Visibility depends on both mutual coherence and local intensity balance.
- Low contrast alone does not identify path information as its cause.
- Pure-marker complementarity needs explicit priors, state purity, and collection assumptions.
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