de Sitter and anti-de Sitter geometries
Relate cosmological constant to curvature scale and distinguish observer horizons, cosmological patches, and timelike boundaries.
On this page
The question for today
What you’ll understand
- Compute curvature invariants from a declared cosmological length.
- Identify the domain of the de Sitter static chart and a flat FLRW patch.
- Explain why global anti-de Sitter evolution needs boundary conditions.
Vacuum need not mean flat spacetime. With a cosmological constant, the four-dimensional field equation admits maximally symmetric solutions whose curvature is fixed everywhere by one length scale. Positive Lambda gives de Sitter geometry and negative Lambda gives anti-de Sitter geometry. These are analytic backgrounds with strong symmetry assumptions, not complete models of the observed universe at every epoch. We keep Lambda on the geometric side and set nongravitational stress-energy to zero here; moving it to an effective fluid is an equivalent bookkeeping choice, not an extra source.
Maximal symmetry fixes the full curvature
The vacuum equation requires the Ricci tensor to equal Lambda times the metric. Maximal symmetry further fixes the full Riemann tensor to the constant-curvature form, a stronger statement than the vacuum equation alone. Schwarzschild with Lambda, for example, need not be maximally symmetric. Define a positive length L through the absolute magnitude of Lambda. Scalar curvature changes sign between the two maximally symmetric cases, while the contracted curvature square has the same positive value for equal L.
Neither the sign of scalar curvature nor the word vacuum determines whether a particular chart has a horizon. A horizon is a causal feature, whereas the displayed invariants describe local curvature. Changing L rescales curvature continuously: doubling L divides scalar-curvature magnitude by four and the curvature square by sixteen. The positive-Lambda effective fluid has positive energy density and negative pressure as discussed earlier, violating the strong energy condition without contradicting the field equation. Negative Lambda cannot simply be described by the same positive-density fluid.
de Sitter has several useful but incomplete charts
In a static de Sitter chart the metric factor is one minus radius squared over L squared. Static observers exist for radius less than L; the chart’s horizon at L is not a curvature singularity. It depends on the observer’s causal patch rather than enclosing a localized central mass. A different family of comoving observers yields a spatially flat FLRW patch whose scale factor grows exponentially with constant Hubble rate c divided by L. This flat spatial slicing does not make the four-dimensional spacetime flat.
The static and expanding descriptions cover different patches and use different observer families. They are not competing predictions about whether the same invariant geometry changes with time. The flat FLRW patch does not cover all of global de Sitter, and its exponential scale factor should not be generalized to a universe containing arbitrary matter, radiation, or spatial curvature. The exact vacuum relation between H and L follows from the specified solution. Perturbations and realistic cosmic history require additional equations and initial data.
Anti-de Sitter has a timelike conformal boundary
The global static anti-de Sitter metric instead has factor one plus radius squared over L squared. It stays positive at every nonnegative radius, so this chart contains no de Sitter-like zero of its static factor. The universal covering spacetime unwraps the periodic time associated with the simplest hyperboloid embedding, avoiding that embedding’s closed timelike circles. Statements about the global geometry should identify this cover rather than silently treating periodic and unwrapped time as the same spacetime.
Radial light can reach the conformal boundary in finite global time. That boundary is timelike, so specifying data on a bulk spacelike slice alone does not determine later incoming influence. A well-posed field evolution must include suitable boundary conditions, such as an explicitly chosen reflecting prescription; different matter and gravitational problems need compatible choices. Other anti-de Sitter patches can have coordinate horizons, so the absence of a zero in this global static factor is not a claim about every chart. The quadratic instrument below contrasts signed scalar labels only, not these global causal properties.
Work it through
A positive curvature scale and exponential expansion
For a de Sitter solution let , with positive length unit . Find Lambda, R, H, and the time required for the spatially flat patch’s scale factor to double.
The cosmological constant is . Its traced vacuum curvature is , with the positive sign fixed by the declared convention.
The flat-patch Hubble rate is . This has inverse time units because c converts the length scale to a time scale.
Set . Therefore ; the result concerns the comoving observers of this patch.
Lambda is 1/(3L_*²), R is 4/(3L_*²), H is c/(3L_*), and the flat-patch doubling time is 3L_* ln2/c.
The living notebook
Explore the model
Interactive lab · function
Separate curvature sign from squared curvature
Reset and set coefficient , position ; predict height +1 and slope +2. Repeat from Reset with both controls , ; predict height −1 and slope −2. Use the heights as opposite signed scalar-curvature labels at a common L only; their squares agree. The parabola has no Lorentzian metric, expanding patch, curvature-tensor computation, or cosmological horizon.
- y at chosen x
- 0.608
- Tangent slope · 2ax
- 1.35
- Signed area · ax³/3
- 0.182
This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forOpposite scalar-curvature signs can share the same curvature-square magnitude; a signed algebraic illustration cannot establish global causal structure.
Pause & reason
Check your understanding
Your turn
Try it yourself
For anti-de Sitter space with , compute R and the curvature square. Does its global static factor vanish at any nonnegative radius, and what is the center-to-boundary radial light time?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Use the sign-sensitive trace and sign-insensitive curvature square, then inspect the static factor and the radial-null integral.
Compare with the solution
The scalar is , while is positive. The global static factor has no zero for real nonnegative r. A radial null ray obeys , giving total travel time to the conformal boundary. Negative scalar curvature is therefore compatible with a positive curvature square and a finite boundary light-travel time; it does not remove the need for boundary conditions.
Keep the idea
Take it with you
- Maximal symmetry fixes the full curvature and adds an assumption beyond the vacuum Einstein equation.
- de Sitter’s static and expanding patches describe different observer families within one geometry.
- Global covering anti-de Sitter has a timelike boundary whose conditions are part of the evolution problem.
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