research30 min studyLesson 612 in Physics

Higgs doublet vacuum and gauge-boson masses

Extract charged and neutral gauge masses from the Higgs kinetic term with explicit vacuum and quadratic-form normalization.

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What you’ll understand

  • Normalize the Higgs vacuum and scalar excitation consistently.
  • Read a neutral gauge mass matrix with the correct one-half factor.
  • Identify the unbroken electromagnetic direction and count physical modes.

A gauge-boson mass matrix follows from the scalar kinetic term evaluated near a chosen vacuum. Its entries are not independent assignments. With one complex Higgs doublet of hypercharge one half, one neutral gauge combination remains massless and three vector fields acquire longitudinal polarizations. We derive these statements at tree level in a perturbative gauge-fixed description, distinguishing physical mass predictions from a gauge-dependent choice of vacuum orientation. All numerical inputs below are hypothetical teaching parameters.

The vacuum scale is not its component value

Choose a potential with a negative quadratic coefficient and a positive quartic coefficient. Its minimum fixes the Higgs norm, but gauge-equivalent vacuum orientations describe the same physics. In a convenient orientation the lower neutral component has expectation value v divided by square root of two. The canonically normalized real fluctuation h enters with the same divisor. Confusing v with the component expectation value changes vector masses by a square-root-of-two factor.

Expanding the potential around this minimum gives the radial scalar mass squared equal to twice lambda times v squared. The doublet contains four real components. In perturbation theory three would-be Goldstone modes account for the additional longitudinal polarizations of the charged W pair and Z, leaving one physical scalar excitation. This is degree-of-freedom bookkeeping; local gauge symmetry is a redundancy and its orientation is not itself an observable that spontaneously selects a detector direction.

V(H)=−μ2H†H+λ(H†H)2,H=12(0v+h),v2=μ2λ,mh2=2λv2V(H)=-\mu^2H^\dagger H+\lambda(H^\dagger H)^2,\qquad H=\frac1{\sqrt2}\begin{pmatrix}0\\v+h\end{pmatrix},\qquad v^2=\frac{\mu^2}{\lambda},\quad m_h^2=2\lambda v^2
Here μ² and λ are positive, v and h have energy dimension one, and λ is dimensionless. The displayed H uses unitary gauge locally around the chosen vacuum; mass relations are tree-level.↔ Scroll wide equations horizontally.

The kinetic term fixes the mass coefficients

Act with the covariant derivative on the vacuum. The charged weak generators rotate its lower component into the upper component, generating mass terms for W-one and W-two. Their complex charged combinations have a mass term of the form mass squared times W-plus times W-minus. The neutral generators instead act on the same lower component, producing the square of g times W-three minus g-prime times B.

For real neutral fields, compare the quadratic expression with one half of the row vector times the mass-squared matrix times the column vector. This extra one half is required when reading eigenvalues. The neutral matrix has determinant zero and positive trace, hence one zero eigenvalue and one positive eigenvalue. A null eigenvector proportional to the couplings in reversed order identifies the photon; the orthogonal combination becomes Z. Diagonalizing the matrix explains the zero without adjusting a photon mass by hand.

Lmass=g2v24Wμ+W−μ+v28(gWμ3−g′Bμ)2,M02=v24(g2−gg′−gg′g′2)\mathcal L_{\rm mass}=\frac{g^2v^2}{4}W^+_\mu W^{-\mu}+\frac{v^2}{8}(gW^3_\mu-g' B_\mu)^2,\qquad M_0^2=\frac{v^2}{4}\begin{pmatrix}g^2&-gg'\\-gg'&g'^2\end{pmatrix}
The neutral convention is Lmass=(1/2)(W³,B)M₀²(W³,B)ᵀ. Thus mW=gv/2 and mZ=v√(g²+g′²)/2, with mass in the same energy units as v.↔ Scroll wide equations horizontally.

The unbroken generator predicts the photon

The vacuum's lower component has electric charge zero because its T-three and hypercharge eigenvalues cancel. Therefore the electromagnetic generator annihilates the vacuum and its gauge-field direction receives no mass from this doublet. The statement links the scalar representation, its vacuum, and the neutral null eigenvector. A different scalar representation or additional expectation values can alter vector-mass relations, so the result is not a property of every imaginable symmetry-breaking sector.

These tree-level masses describe parameters in the leading Lagrangian. Precision comparisons use pole definitions, radiative corrections, and an input scheme, with unstable-vector line shapes treated consistently. Increasing v at fixed dimensionless couplings rescales these leading masses, but is a theoretical parameter variation rather than an experimental procedure that holds every measured electroweak input fixed. The same distinction applies to the illustrative scalar mass: its quartic coupling is not predicted merely by knowing the gauge group.

Read a rank-one neutral mass matrix

Use toy couplings g=0.8, g′=0.6 and v=250 GeV. Compute the neutral mass matrix, its eigenvalues, and the charged W mass.

  1. The common mass-squared factor is v²/4=15,625 GeV². Multiplying gives the neutral matrix [[10,000,−7,500],[−7,500,5,625]] GeV², whose determinant vanishes.

  2. The trace is 15,625 GeV², so the eigenvalues are 0 and 15,625 GeV². Taking nonnegative square roots gives photon mass zero and Z mass 125 GeV.

  3. The charged mass is gv/2=0.8×250/2=100 GeV. The normalized neutral null vector in the (W³,B) basis is (0.6,0.8), and direct multiplication returns zero.

The result

The toy spectrum is mγ=0, mW=100 GeV and mZ=125 GeV; the neutral matrix’s one-half Lagrangian convention is essential.

Explore the model

Interactive lab

Interactive lab · function

Inspect a quadratic curvature

For each fresh comparison, Reset and set both controls. Reset and set coefficient a=0.5 and position x=1. Predict y=0.5 and tangent slope 1. Compare a fresh run with both controls a=1 and x=1, giving y=1 and slope 2. This illustrates how a quadratic coefficient controls curvature near a minimum; the lab has no Mexican-hat potential, Higgs doublet, gauge fields, mass matrix, or negative-mode dynamics.

Inspect a quadratic curvatureThis lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Current readings: y at chosen x: 0.608; Tangent slope · 2ax: 1.35; Signed area · ax³/3: 0.182. All parameters are adjustable with the labeled controls below.−2.4−1.201.22.4−9−4.504.59xy(x, ax²)
y = ax²TangentSigned integral
y at chosen x
0.608
Tangent slope · 2ax
1.35
Signed area · ax³/3
0.182
t = 0 s

This lab uses only y = ax². Playback traces the curve within the fixed integration interval from 0 to x; it does not estimate numerical error or change the chosen point. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forA local quadratic coefficient must be matched to the canonical mass-term normalization before calling it a mass squared.

Check your understanding

Why is the neutral eigenvalue not read directly from the coefficient v²(g²+g′²)/8 in the Lagrangian?

Try it yourself

Keep v=250 GeV and choose toy λ=0.08. Compute the radial Higgs mass and μ, then check the location of the potential minimum in H†H.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Use both stationarity and the radial curvature; μ is the positive square root of μ².

Compare with the solution

The scalar mass squared is 2×0.08×250²=10,000 GeV², so mh=100 GeV. The potential parameter is μ²=λv²=5,000 GeV², giving μ=50√2≈70.7107 GeV. The minimum occurs at H†H=μ²/(2λ)=31,250 GeV², equal to v²/2. The vacuum component is v/√2, not v; the radial fluctuation is canonically normalized by the same square-root factor.

Take it with you

  • The conventional v is √2 times the neutral Higgs-component expectation value.
  • A neutral real-field quadratic form includes a factor one half when masses are extracted.
  • The unbroken electromagnetic generator gives a massless photon at tree level.

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