advanced28 min studyLesson 465 in Physics

Anharmonic vibrations and Morse potentials

Use the Morse model to separate local force constants, decreasing vibrational spacings, dissociation thresholds, and isotope-dependent zero-point energy.

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What you’ll understand

  • Derive the local harmonic curvature of a Morse potential.
  • Calculate anharmonic level spacings and distinguish D e from D zero.
  • Apply reduced-mass scaling while retaining one potential-energy convention.

A harmonic bond cannot dissociate because its potential rises without bound at large extension. A real molecular surface approaches separated fragments, so its highly excited vibrational levels crowd toward a finite threshold. The Morse potential supplies an analytically tractable model of that behavior while retaining a harmonic minimum. We will declare the energy zero at the minimum, distinguish angular frequency from spectroscopic wavenumber, and compare the well depth with the smaller energy needed to dissociate a molecule already carrying zero-point vibration.

A finite well depth changes the oscillator

Let x=R−Rex=R-R_e and choose the model potential V(x)=De(1−e−ax)2V(x)=D_e(1-e^{-ax})^2, with positive depth parameter DeD_e and inverse-length parameter a. The minimum is zero at x = 0 and the dissociation limit is DeD_e as x tends to positive infinity. Expanding the exponential near zero gives leading potential Dea2x2D_ea^2x^2, so the local spring constant is k=2Dea2k=2D_ea^2. The vibrational kinetic energy uses nuclear reduced mass, not total molecular mass.

The standard analytic solution treats this stretch coordinate on the full real line. A physical radial coordinate instead has R positive and an appropriate short-distance boundary; the extended Morse model is useful when the relevant bound states do not probe that artificial boundary. It is a model potential, not an exact statement about every diatomic electronic surface. In particular, its large-distance exponential approach does not reproduce every inverse-power molecular tail or coupled dissociation channel.

V(x)=De(1−e−ax)2,k=2Dea2,ω=a2Deμ,Ev=ℏω(v+12)−(ℏω)24De(v+12)2V(x)=D_e(1-e^{-ax})^2,\qquad k=2D_ea^2,\qquad \omega=a\sqrt{\frac{2D_e}{\mu}},\qquad E_v=\hbar\omega\left(v+\frac12\right)-\frac{(\hbar\omega)^2}{4D_e}\left(v+\frac12\right)^2
D e and E v are energies from the potential minimum, a is in inverse metres, mu in kilograms, and omega is angular frequency in radians per second. The level formula is exact for the ideal full-line Morse model.↔ Scroll wide equations horizontally.

Spectroscopic constants reveal unequal spacings

Spectroscopists often divide energy by h c and report a term value in inverse centimetres. Define ω~e=ω/(2πc)\widetilde\omega_e=\omega/(2\pi c) and ω~exe=(ℏω)2/(4Dehc)\widetilde\omega_ex_e=(\hbar\omega)^2/(4D_ehc), using c in centimetres per second for these wavenumbers. The symbol called omega e in a table can therefore be a wavenumber rather than an angular frequency. Unit labels determine which quantity is meant; inserting it directly into a time-domain oscillator equation would be incorrect.

Subtracting neighboring terms gives spacing ω~e−2ω~exe(v+1)\widetilde\omega_e-2\widetilde\omega_ex_e(v+1). A positive anharmonic constant makes this spacing decrease with excitation. Only a finite number of normalizable Morse bound states exist, with v+1/2<2De/(ℏω)v+1/2<2D_e/(\hbar\omega); equality at the threshold is excluded. Extending the quadratic term-value formula to arbitrarily large v would eventually turn the sequence downward and create spurious states, so the bound-state condition belongs alongside the energy formula.

G(v)=Evhc=ω~e(v+12)−ω~exe(v+12)2,Dehc=ω~e24ω~exe,D0=De−E0G(v)=\frac{E_v}{hc}=\widetilde\omega_e\left(v+\frac12\right)-\widetilde\omega_ex_e\left(v+\frac12\right)^2,\qquad \frac{D_e}{hc}=\frac{\widetilde\omega_e^2}{4\widetilde\omega_ex_e},\qquad D_0=D_e-E_0
G, both spectroscopic constants, and D e divided by h c share wavenumber units. D zero is the dissociation energy from the lowest vibrational level on the same surface, before additional rotational or channel complications.↔ Scroll wide equations horizontally.

Mass and anharmonicity have different roles

If isotope substitution retains the same leading electronic potential, D e and a stay fixed while angular frequency scales as the inverse square root of reduced mass. The anharmonic energy coefficient scales as inverse reduced mass. The zero-point energy therefore decreases for heavier isotopes, increasing D zero even though the electronic well depth has not changed. This distinction is essential when comparing a computed potential minimum with an experimental dissociation threshold.

Real spectra include additional terms, rotation-vibration coupling, and perturbations from other surfaces. A fitted pair of Morse-like constants can summarize low-lying levels without faithfully predicting all near-threshold states. Conversely, an accurate empirical potential may use many parameters rather than the simple Morse form. We will use a deliberately hypothetical set of wavenumbers below so the arithmetic illustrates the model and its consistency conditions, rather than implying measured constants for a particular molecule.

Well depth and zero-point dissociation

An ideal Morse model has ω~e=1000 cm−1\widetilde\omega_e=1000\,\mathrm{cm^{-1}} and ω~exe=20 cm−1\widetilde\omega_ex_e=20\,\mathrm{cm^{-1}}. Find the first two adjacent vibrational spacings, D e/(h c), the ground term G(0), and D zero/(h c).

  1. The 0 to 1 spacing is 1000−2(20)(1)=960 cm−11000-2(20)(1)=960\,\mathrm{cm^{-1}}. The 1 to 2 spacing is 1000−2(20)(2)=920 cm−11000-2(20)(2)=920\,\mathrm{cm^{-1}}, demonstrating the decreasing interval.

  2. The ideal well depth is 10002/[4(20)]=12500 cm−11000^2/[4(20)]=12500\,\mathrm{cm^{-1}} after division by h c. The ground term is 1000/2−20/4=495 cm−11000/2-20/4=495\,\mathrm{cm^{-1}}.

  3. Subtract zero-point energy to obtain D0/(hc)=12500−495=12005 cm−1D_0/(hc)=12500-495=12005\,\mathrm{cm^{-1}}. The depth and dissociation-from-ground values differ because the ground state is not at the bottom of the well.

The result

The spacings are 960 and 920 cm⁻¹, the well depth is 12500 cm⁻¹, and the ground-state dissociation energy is 12005 cm⁻¹ in this ideal model.

Explore the model

Interactive lab

Interactive lab · oscillator

The local harmonic limit

Reset, set Damping ratio ζ = 0 and Natural frequency ω₀ = 1, and predict undamped oscillation of unit initial displacement. For a fresh run Reset, set ζ = 0 and ω₀ = 2, and predict half the period. Interpret the comparison only as a change in the local harmonic frequency scale.

The local harmonic limitUnit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Current readings: Displacement x(t): 1; Velocity v(t): 0; Regime: underdamped. All parameters are adjustable with the labeled controls below.02.557.510−1.15−0.5700.571.15Time · sDisplacementunderdamped
Displacement x(t)Current time
Displacement x(t)
1
Velocity v(t)
0
Regime
underdamped
t = 0 s

Unit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThe instrument is a classical positive-stiffness oscillator with fixed x(0) = 1 and velocity(0) = 0. It has no Morse well, energy levels, dissociation threshold, amplitude-dependent period, or adjustable reduced mass.

Check your understanding

Why is D zero smaller than D e on a bound vibrational surface?

Try it yourself

In the preceding hypothetical Morse potential, increase reduced mass by a factor of four while retaining D e and a. Find the new harmonic wavenumber, anharmonic wavenumber coefficient, and fundamental 0 to 1 spacing.

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

The harmonic term scales as inverse square root of mass, while its quadratic anharmonic coefficient scales as inverse mass.

Compare with the solution

The new harmonic wavenumber is 1000/2=500 cm−11000/2=500\,\mathrm{cm^{-1}}. The anharmonic coefficient is 20/4=5 cm−120/4=5\,\mathrm{cm^{-1}}. The fundamental becomes 500−2(5)=490 cm−1500-2(5)=490\,\mathrm{cm^{-1}}. The electronic well depth remains 12500 cm−112500\,\mathrm{cm^{-1}} in this leading isotope model; changing nuclear mass does not automatically change the clamped-electronic potential.

Take it with you

  • The Morse model joins a harmonic minimum to a finite dissociation threshold with a declared energy zero.
  • Spectroscopic omega-like symbols can represent wavenumbers rather than angular frequency.
  • Heavier isotopes lower zero-point energy even when the leading electronic well is unchanged.

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