Coherent states and minimum uncertainty
Construct displaced oscillator ground states, follow their moving means, and distinguish coherent widths from general uncertainty saturation.
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The question for today
What you’ll understand
- Relate a coherent-state parameter to position, momentum, and occupation.
- Calculate fixed variances and time-dependent means.
- Distinguish a coherent state from a number state, a mixture, and a squeezed minimum-product state.
A harmonic oscillator can have a localized wavepacket whose shape remains unchanged while its centre follows the classical oscillator equations. Such a coherent state is a superposition of infinitely many number states, rather than a single energy eigenstate. Its moving mean and irreducible width offer a precise connection between classical motion and quantum uncertainty, provided that mean motion is not mistaken for a particle trajectory measured without disturbance.
An annihilation eigenstate needs infinitely many levels
A coherent state is a normalized eigenstate of the annihilation operator, , with complex dimensionless parameter α. Expanding in number states and comparing adjacent coefficients gives a factorially weighted series. Normalization introduces the exponential prefactor. Squared coefficients form a Poisson distribution of occupation with mean . Despite the annihilation eigenvalue equation, it is not an eigenstate of the Hermitian number operator unless α is zero.
The complex parameter specifies two independent means: its real part fixes position and its imaginary part fixes momentum. Defining oscillator length , the means are and . A global phase of the whole ket does not change these means; changing the phase of α rotates the physical displacement in phase space. Confusing these two phases would erase the distinction between displaced position and displaced momentum.
Fixed widths accompany a moving mean
A coherent state has the same position and momentum variances as the oscillator ground state. Displacement changes the means but not these intrinsic widths. Under the positive quadratic Hamiltonian, α rotates as , while an additional overall phase has no effect on density. The packet stays Gaussian, and its means follow the classical sinusoid. Its energy expectation includes both the classical displacement energy and the nonzero ground-state contribution.
Number-state phases are responsible for that shape-preserving motion. The oscillator's equally spaced spectrum makes all their relative phases advance in a compatible way. An anharmonic potential generally changes this property, allowing distortion, spreading, or more complicated revivals. The constant-width result therefore belongs to an exact harmonic Hamiltonian, rather than to any localized quantum packet. Coupling to an environment can also alter widths and purity even when a classical damped mean remains a useful description.
Minimum product does not uniquely identify coherence
A displaced ground state saturates the position–momentum uncertainty product with the oscillator's natural equal scaled widths. A squeezed Gaussian can also saturate that product at a suitable phase while having a smaller position variance and larger momentum variance. General rotated squeezed states have position–momentum covariance and need the fuller uncertainty relation. Thus minimum product alone does not identify a coherent state unless its width and covariance properties are also specified.
A large makes the mean excursion large compared with the fixed width and makes relative occupation fluctuations small. It does not remove quantum uncertainty or turn an ensemble of measurements into one disturbance-free path. A statistical mixture can reproduce some means without reproducing the pure state's off-diagonal coherence. To diagnose a coherent preparation one needs appropriate quadrature or interference information, rather than merely a sharply peaked classical-looking average signal.
Work it through
A displaced packet at a quarter period
An exact oscillator has length and quantum . It starts in coherent state , real. Find initial position mean and both uncertainties, the position and momentum means after one quarter-period, and the mean energy.
Initially and . The packet widths are and . Their product is , independent of the displacement.
After , the parameter is . Thus and . The negative sign is consistent with motion from a positive initial displacement toward the origin.
The mean occupation is , giving . It remains constant during the rotation, as do both widths. The energy uncertainty is nonzero: .
The mean starts at 2√2 nm and reaches zero position after a quarter period with negative momentum −2√2ℏ/nm. Its widths stay at their ground-state values and mean energy stays 9 meV; it is not an energy eigenstate.
The living notebook
Explore the model
Interactive lab · oscillator
Follow the normalized coherent mean
For a real initial displacement and zero mean momentum, the normalized coherent position mean follows the undamped classical oscillator. Reset and set both controls to ζ = 0 and ω₀ = 1; predict a cosine with period 2π. Reset and set both controls to ζ = 0 and ω₀ = 2; predict period π, then Step or Play. This unit-mass positive oscillator plots only displacement and velocity; it has no quantum wavefunction, Gaussian width, number distribution, or uncertainty readouts.
- Displacement x(t)
- 1
- Velocity v(t)
- 0
- Regime
- underdamped
Unit mass, x(0) = 1 and v(0) = 0. The analytic solution includes underdamped, critically damped and overdamped cases; time is measured in seconds. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forThe lab can illustrate the exact harmonic mean equation, while the quantum packet's constant variances must be computed separately.
Pause & reason
Check your understanding
Your turn
Try it yourself
For a coherent state with initial , find mean occupation, probability of the vacuum number outcome, and mean energy in units of . After a quarter-period of harmonic evolution, determine the sign and value of the position mean in units of .
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
The vacuum coefficient is the n = 0 term in the normalized series, and multiplication by exp(−iπ/2) rotates i onto the positive real axis.
Compare with the solution
Initially , so mean occupation is one and the vacuum probability is . The mean energy is , although individual energy measurements give discrete number-state energies. A quarter-period later , making and mean momentum zero. The packet initially had positive mean momentum and zero position, so its later positive displacement is consistent with the phase-space rotation convention. Its intrinsic widths remain unchanged.
Keep the idea
Take it with you
- A coherent state combines infinitely many number levels with Poisson weights.
- Harmonic evolution rotates its mean displacement while preserving ground-state widths.
- Uncertainty saturation alone does not distinguish a coherent state from suitable squeezed states.
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