advanced30 min studyLesson 50 in Physics

Path integrals and generating functions

Build the sum-over-histories viewpoint with a regulator, connect sources to correlations, and identify what the formal notation does not prove.

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What you’ll understand

  • Explain how discretized quantum evolution motivates a field path integral.
  • Generate time-ordered correlations through derivatives of a source functional.
  • Distinguish Lorentzian phases, Euclidean weights, regularization, and a proven continuum limit.

Canonical quantization emphasizes operators and states. Path integrals reorganize the same physics, where the formulations are well defined and equivalent, into an integral over histories. This makes symmetries and perturbative expansions particularly transparent. The notation is compact enough to conceal major analytic assumptions, so we will first understand a finite Gaussian example and only then explain the formal field-theory extension.

A sum over histories needs a definition

Use ℏ=c=1\hbar=c=1 and Lorentzian metric (+−−−)(+---). Break a time interval into small steps and insert complete position bases between short-time evolution operators. For ordinary quantum mechanics this motivates integrals over intermediate positions weighted by complex phases. Discretizing space as well gives finitely many field coordinates at a finite cutoff. The continuum symbol Dϕ\mathcal D\phi summarizes a limit of such constructions; it is not an ordinary uniform measure on every imaginable field.

The Lorentzian factor eiSe^{iS} has no positive-probability interpretation. Contributions can cancel by interference, and the bare oscillatory integral may need an iϵi\epsilon prescription or a specified integration contour. A vacuum generating functional also needs its state and boundary prescription. Dividing by the zero-source functional removes a normalization factor; it does not by itself prove convergence or define every interacting continuum field theory.

Z[J]=∫Dϕ exp⁡ ⁣(iS[ϕ]+i∫d4x J(x)ϕ(x))∫Dϕ eiS[ϕ],Z[0]=1Z[J]=\frac{\int\mathcal D\phi\,\exp\!\left(iS[\phi]+i\int d^4x\,J(x)\phi(x)\right)}{\int\mathcal D\phi\,e^{iS[\phi]}},\qquad Z[0]=1
This is formal continuum notation for a specified regulated vacuum construction with the appropriate prescription. J is a classical source; normalization assumes the denominator is defined and nonzero.↔ Scroll wide equations horizontally.

Sources turn one function into many questions

Differentiating with respect to J(x)J(x) brings down a field insertion and a factor of ii. Repeating this produces time-ordered vacuum correlations in the appropriate vacuum path integral. The source is a device for organizing questions; setting it to zero after differentiation returns the undriven theory. For a free action, completing the Gaussian square determines all correlations from the two-point function, reproducing the pairing structure used in Wick’s theorem.

Expanding an interaction inside the integral generates the same vertex insertions and contractions as operator perturbation theory. A useful consistency check is to reproduce a simple low-order amplitude in both languages under matching conventions. The path integral is therefore more than a new metaphor: it changes the organization of a calculation. Yet it does not make arbitrary strong-coupling integrals easy, and a formal rearrangement does not establish convergence of the rearranged series.

1inδnZ[J]δJ(x1)⋯δJ(xn)∣J=0=⟨0∣Tϕ(x1)⋯ϕ(xn)∣0⟩\left.\frac{1}{i^n}\frac{\delta^n Z[J]}{\delta J(x_1)\cdots\delta J(x_n)}\right|_{J=0}=\langle0|T\phi(x_1)\cdots\phi(x_n)|0\rangle
The relation uses the normalized vacuum functional and its time-ordering prescription. Functional derivatives are understood through test sources or a regulator, especially at coincident insertions.↔ Scroll wide equations horizontally.

Euclidean methods help, with conditions

Under suitable analyticity and boundary assumptions, rotating to imaginary time turns a stable scalar theory into a Euclidean weight e−SEe^{-S_E}. A positive real weight can be sampled numerically in many bosonic lattice models. This is not an automatic operation for every contour, state, or theory. Fermion determinants and finite-density systems can introduce sign or complex-weight problems, and recovering real-time quantities from Euclidean data is often ill-conditioned.

A finite lattice provides a regulator and a concrete finite-dimensional integral. Removing its spacing while holding physical scales fixed requires tuning and a justified continuum limit. The existence of the finite integral does not guarantee that desired limit exists or is interacting. Gauge theories also need control of gauge redundancy; gauge fixing and its Jacobian enter continuum treatments. These issues connect the elegant generating-function notation to the renormalization and nonperturbative questions of the next module.

A one-variable Euclidean generating integral

Let a>0a>0 and define ZE(J)=∫dx e−ax2/2+Jx/∫dx e−ax2/2Z_E(J)=\int dx\,e^{-ax^2/2+Jx}/\int dx\,e^{-ax^2/2}. Compute the normalized mean and second moment at zero source. This is a finite-dimensional analogy, not a full QFT.

  1. Complete the square: −ax2/2+Jx=−a(x−J/a)2/2+J2/(2a)-ax^2/2+Jx=-a(x-J/a)^2/2+J^2/(2a). Shift the real integration variable, which is allowed for this convergent real Gaussian.

  2. The identical Gaussian integrals cancel, leaving ZE(J)=eJ2/(2a)Z_E(J)=e^{J^2/(2a)}. Differentiate once: ZE′(J)=(J/a)ZE(J)Z'_E(J)=(J/a)Z_E(J), so the zero-source mean is zero.

  3. Differentiate again to obtain ZE′′(0)=1/aZ''_E(0)=1/a. The variance is positive despite the zero mean, matching the distinction between a vanishing field expectation and nonzero fluctuations. Higher moments follow by further differentiation.

ZE(J)=eJ2/(2a),⟨x⟩=0,⟨x2⟩=1aZ_E(J)=e^{J^2/(2a)},\qquad \langle x\rangle=0,\qquad \langle x^2\rangle=\frac1a
This example uses a real Euclidean source without a factor of i; its derivative convention differs deliberately from the Lorentzian functional above.↔ Scroll wide equations horizontally.
The result

The source packages moments into derivatives of one normalized function. In a regulated free field, the inverse quadratic kernel replaces 1/a and organizes the propagator.

Explore the model

Interactive lab

Interactive lab · spectral

A cutoff changes the space being represented

Increase the number of modes N in the finite sine sum Σ sin(nx − t)/nᵖ and vary the coefficient decay p. Notice the additional spatial detail as more modes are retained, while the displayed field remains a finite expansion.

A cutoff changes the space being representedA finite sum of sin(nx − t)/nᵖ. Playback changes t; increasing the cutoff includes finer spatial scales. This is not a proof about a continuum limit or renormalization. Current readings: Sum at x = π/2: 0.867; Smallest wavelength: 2π / 5; Highest-mode coefficient: 0.2. All parameters are adjustable with the labeled controls below.01.573.144.716.28−2.56−1.2801.282.56x · radiansFinite sine sum
Finite sumHighest included mode
Sum at x = π/2
0.867
Smallest wavelength
2π / 5
Highest-mode coefficient
0.2
t = 0 s

A finite sum of sin(nx − t)/nᵖ. Playback changes t; increasing the cutoff includes finer spatial scales. This is not a proof about a continuum limit or renormalization. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThis is a truncation analogy, not a path-integral sampler, a Gaussian-field ensemble, or a proof of a continuum limit. Increasing N on a plot does not establish a renormalized quantum theory.

Check your understanding

What follows from having a finite, well-defined lattice integral at one lattice spacing?

Try it yourself

For the same Gaussian generating function, find ⟨x4⟩\langle x^4\rangle and compare it with ⟨x2⟩2\langle x^2\rangle^2. What does their relation suggest about pairings?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Expand eJ2/(2a)e^{J^2/(2a)} through J4J^4 and remember the fourth derivative multiplies that coefficient by 4!4!.

Compare with the solution

The J4J^4 coefficient is 1/(8a2)1/(8a^2), so ⟨x4⟩=24/(8a2)=3/a2=3⟨x2⟩2\langle x^4\rangle=24/(8a^2)=3/a^2=3\langle x^2\rangle^2. There are three pairings of four labeled entries. This finite Gaussian calculation motivates the pairing rule for a free regulated field; it does not imply that an interacting field’s higher correlations always factorize.

Take it with you

  • A path integral needs a regulator, boundary or vacuum prescription, and meaningful limiting procedure.
  • Source derivatives generate correlations with convention-dependent factors of i.
  • Euclidean positivity and an existing continuum theory are conditions to establish, not consequences of writing an integral symbol.

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