A quasiparticle mixes particle and hole amplitudes
Diagonalize one BdG block and distinguish coherence weights, electron occupations, and thermal excitation probabilities.
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The question for today
What you’ll understand
- Diagonalize the homogeneous two-component BdG block.
- Compute particle and hole coherence weights.
- Distinguish electron occupation from quasiparticle thermal occupation.
Excitations above a paired ground state are not simply bare electrons promoted across an ordinary band gap. A Bogoliubov quasiparticle combines particle and hole amplitudes because the pairing field couples their sectors. The energy spectrum and the amplitudes follow from a two-component eigenproblem. We will solve that block, interpret its normalized weights, and use a finite-temperature example to show why a hole weight is not itself the probability that a quasiparticle is thermally excited.
Pairing turns an electron equation into a two-component problem
For a translationally invariant spin-singlet mean-field state, group an electron amplitude at momentum k with the corresponding opposite-spin hole amplitude at −k. Relative to the chemical potential, their diagonal entries are ξ and −ξ. The off-diagonal pairing field mixes them. This particle–hole doubling is a useful representation of the fermionic problem, not two independent physical particles for each original electronic state. The negative eigenvalue accompanies the positive one through the redundancy of the BdG description.
The determinant gives energies whose squares equal ξ² plus the squared gap magnitude. Choose the positive branch as the quasiparticle excitation energy. Even at ξ=0 this energy is the nonzero gap magnitude in a fully gapped state. Thus the normal-state Fermi surface becomes the location of minimum excitation energy rather than a set of zero-energy electron states. A spatially varying gap, a vortex, or a boundary requires a differential or real-space matrix problem; the homogeneous block alone does not describe localized core or surface levels.
Normalized coherence weights interpolate across the Fermi surface
Solving the eigenvector equation and normalizing gives particle weight one half times one plus ξ/E, with the complementary hole weight. Far above the chemical potential the positive-energy excitation is mostly particle-like; far below it, mostly hole-like. At ξ=0 the weights are equal. The relative phase between u and v tracks the pairing phase under the declared matrix convention. Scattering and response matrix elements can depend on products of these amplitudes, so retaining only the energy spectrum can omit physically important interference factors.
The thermal Fermi factor f(E) specifies how often a quasiparticle mode is occupied. It is different from either coherence weight. At zero temperature, no positive-energy quasiparticles are occupied, yet the electron occupation is generally v squared. At finite temperature the occupation receives a contribution from both adding a quasiparticle and removing its paired partner. In the spin-balanced equilibrium model this gives v squared plus the particle-minus-hole weight times f. Setting electron occupation equal to f(E) would incorrectly erase the paired ground-state distribution.
Spectra and amplitude-sensitive probes carry complementary information
In a clean isotropic fully gapped model, converting the normal-state energy density of states to quasiparticle energy produces an inverse-square-root gap-edge feature. Ideal singularities are rounded by lifetime effects, disorder, temperature, and instrumental resolution. A tunneling spectrum is also weighted by matrix elements. Observing a gap-like suppression does not by itself determine the sign of the pairing function, and the absence of an infinitely sharp peak does not invalidate particle–hole mixing. One needs to distinguish the underlying excitation structure from the measurement process.
The quantum lab illustrates normalized two-component weights without implementing fermionic quasiparticle dynamics. Reset and set both controls to θ=60 degrees and φ=0 degrees, predicting basis weights three quarters and one quarter. Reset and set θ=120 degrees and φ=0 degrees, predicting the reversed weights. Assign these geometrically to particle and hole components. They correspond to opposite ξ/E of magnitude one half if used as BdG eigenvector examples. Playback only precesses relative phase; the lab supplies neither a pairing field nor a thermal Fermi factor or electron-occupation readout.
Work it through
Diagonalize a 3–4–5 quasiparticle block
Take a real positive gap Δ=4 meV and normal-state energy ξ=3 meV. Find the positive quasiparticle energy, the particle and hole weights, and their positive amplitude product in this matrix convention.
The positive energy is E=√(3²+4²)=5 meV. The negative partner is a BdG representation partner rather than a separate negative excitation cost.
The ratio ξ/E is 3/5. Thus |u|²=(1+3/5)/2=4/5 and |v|²=(1−3/5)/2=1/5. Their sum is one.
For the real positive off-diagonal gap, choose u and v positive. Their product is √((4/5)(1/5))=2/5=0.4, also equal to Δ/(2E).
The excitation energy is 5 meV, with particle weight 0.8, hole weight 0.2, and uv=0.4 in the chosen real-positive convention.
The living notebook
Explore the model
Interactive lab · quantum
Reverse particle–hole weights geometrically
Reset and set BOTH controls to θ=60° and φ=0°, predicting P(0)=3/4 and P(1)=1/4. Reset and set θ=120° and φ=0°, predicting reversed weights. This is a Nambu-amplitude analogy, not a BdG or thermal-occupation solver.
- Probability |0⟩
- 71.1%
- Probability |1⟩
- 28.9%
- Bloch (x, y, z)
- 0.78, 0.45, 0.42
A normalized two-level pure state, not an interacting field simulation. Playback adds one radian per second to the relative phase; basis probabilities stay fixed. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forCoherence weights are normalized amplitudes; the probability of thermally exciting the mode is an additional quantity.
Pause & reason
Check your understanding
Your turn
Try it yourself
Reverse the normal-state energy to ξ=−3 meV while keeping Δ=4 meV. A thermal quasiparticle occupation f(E)=0.10 is supplied. Compute E, both coherence weights, and the electron occupation nₖ.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
Changing the sign of ξ exchanges the two weights without changing E. Insert the supplied f into the electron-occupation formula.
Compare with the solution
E remains 5 meV. The particle weight is (1−3/5)/2=0.2 and the hole weight is 0.8. Therefore nₖ=0.8+(0.2−0.8)×0.10=0.74. It is neither the thermal quasiparticle occupation 0.10 nor the zero-temperature hole weight 0.8; thermal excitations reduce the electron occupation for this negative ξ.
Keep the idea
Take it with you
- BdG eigenvectors mix particle and hole components of a paired system.
- A nonzero minimum excitation energy can coexist with equal coherence weights.
- Quasiparticle population and electron occupation must be distinguished.
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