Identify thermal equilibrium through correlations
Derive KMS detailed balance from the Gibbs trace while keeping real-time Fourier conventions and bosonic versus fermionic Green-function signs explicit.
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The question for today
What you’ll understand
- Derive the equilibrium relation between greater and lesser correlations.
- Distinguish a trace identity from signs introduced by fermionic Green-function definitions.
- Test thermal detailed balance in a finite-level model.
A stationary expectation value does not by itself establish thermal equilibrium. Thermal correlations obey an additional relation between positive and negative energy transfer, fixed by the Gibbs ensemble. The Kubo–Martin–Schwinger condition expresses that relation without requiring weak interactions or a particle picture. It becomes the bridge between imaginary time, spectral functions, and fluctuation–dissipation relations, provided the operator definitions and Fourier signs are kept consistent.
Declare the ensemble and time convention
Use , metric , and Heisenberg evolution . Temperature therefore has energy units, and has inverse-energy units. Our real-time Fourier transform uses , with inverse factors of two pi. For a neutral Hermitian bosonic operator A, define raw unordered correlations without factors of i. These conventions will also fix the retarded signs later in the module. Chemical potentials are set to zero throughout these elementary relations.
The Gibbs state commutes with H, giving time-translation invariance. Cyclicity of the trace, combined with the Boltzmann weight, relates an operator moved around that trace to evolution by an imaginary time interval. The resulting KMS identity holds in the appropriate analytic strip for well-defined correlations. It is stronger than stationarity and does not assume free fields. With nonzero conserved-charge chemical potentials, charged operators acquire additional charge-dependent factors; substituting a chemical potential by intuition would not preserve the present formulas.
Translate KMS into energy-transfer balance
Fourier transforming the imaginary-time shift yields under our positive-sign forward transform. A spectral decomposition makes the factor transparent: swapping the initial and final energy eigenstates changes their Gibbs probabilities by the exponential of the exchanged energy. For a Hermitian A, the lesser spectrum at positive frequency equals the greater spectrum at negative frequency. Positive-frequency fluctuations can therefore outweigh negative-frequency fluctuations without violating stationarity. The ratio is a thermal population factor, not an independently adjustable emission parameter.
Fermionic signs require separating raw products from signed Green functions. For an annihilation operator, the raw greater product and raw lesser product still satisfy a positive Boltzmann ratio from the ordinary trace. Standard fermionic conventions instead define the greater function with minus i and the lesser with plus i. Their KMS relation consequently contains a minus sign. Fermionic imaginary-time antiperiodicity additionally follows from fermionic time ordering. Attributing every minus sign directly to cyclicity would conflate three different operations and spoil the occupation factors.
Use detailed balance as a diagnostic
A finite system diagonal in its energy basis is stationary for any chosen populations. Only special population ratios correspond to a Gibbs temperature. Checking correlations at several transition frequencies can distinguish those cases, whereas fitting one transition can always produce a misleading effective temperature. In a field theory, operator choice and accessible frequency range similarly determine how demanding the diagnostic is. An equilibrium claim should be supported by compatible spectral ratios and conserved quantities rather than a single approximately constant occupation number.
KMS does not say that a thermal state has no fluctuations or no dissipation. It constrains how fluctuations and response are related. Conversely, a driven stationary state may have constant macroscopic properties while violating this thermal relation. Nonequilibrium contour methods can describe such states without imposing KMS. Reserve the thermal identity for an actual equilibrium ensemble or a controlled local-equilibrium approximation, and record which time and length scales justify using the latter. A transient fit to a Boltzmann-looking slope is not a proof of global equilibrium.
Work it through
Detailed balance in a two-level probe
A two-level Hamiltonian has energies zero and , with . The Hermitian operator A exchanges the two states with unit matrix element. Find the Gibbs populations and the ratio of the positive- and negative-frequency weights in .
The partition function is . Thus the ground-state probability is and the excited-state probability is .
Expanding the correlation gives . Under the declared Fourier transform, these terms sit at positive and negative frequency, respectively.
The common delta-function normalization cancels in the ratio: the weights at and are in the ratio three. This equals and checks the KMS sign convention.
The populations are three quarters and one quarter, with a three-to-one greater-spectrum weight ratio. Nonzero negative-frequency weight represents the finite thermal population of the upper level.
The living notebook
Explore the model
Interactive lab · probability
Inspect a declared population law
Reset and set success probability to 0.25 and trials to 4. Predict mean count 1 and variance 0.75. Compare after a fresh Reset with p = 0.5 and n = 4, where mean is 2 and variance 1. The lab displays exact independent binomial probabilities, not thermal operator correlations or sampled experiments. It does not derive a temperature from those populations or implement a KMS test.
- Mean · np
- 5
- Variance · np(1−p)
- 2.5
- Total probability
- 1
These are exact binomial probabilities for independent trials with one fixed success probability. Playback tours the distribution; it does not resample outcomes. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forA population model is an input; thermal detailed balance is an additional relation between transitions.
Pause & reason
Check your understanding
Your turn
Try it yourself
A free fermionic level of energy has . Calculate its occupation and the coefficients of in and . State the corresponding ratio for the signed Green functions defined above.
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
The empty and occupied probabilities add to one. The greater raw product detects an available empty state, while the lesser detects an occupied state.
Compare with the solution
The occupation is . Thus and . Their coefficient ratio is positive three. Multiplication by the specified prefactors gives . The minus sign changes the Green-function convention, not the positivity of the occupation. This single-mode example assumes a Gibbs ensemble, zero chemical potential, and a positive level energy.
Keep the idea
Take it with you
- KMS is an equilibrium analytic relation stronger than time-translation invariance.
- Real-time Fourier signs and Green-function prefactors determine spectral signs.
- Bosonic and fermionic thermal factors must be derived with the operator definitions held fixed.
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