research35 min studyLesson 740 in Physics

Numerical bootstrap bounds and truncation control

Read an exclusion as a conditional consistency result and separate it from constructing a conformal theory.

On this page

What you’ll understand

  • Derive the sign logic of a separating functional.
  • Identify derivative, spin and block-approximation controls.
  • Distinguish exclusion, nonexclusion, optimization failure and theory existence.

The numerical conformal bootstrap turns crossing and positivity into a search for consistency or contradiction. Its strongest basic output is often an exclusion: no spectrum satisfying a stated set of assumptions can obey the exact constraints if a valid functional certificate exists. An unexcluded point is not automatically a CFT, and a solver's failure to find a certificate is not a proof of feasibility. Numerical precision, block approximations and the treatment of infinitely many dimensions and spins determine how strong the conclusion actually is.

Specify the hypothesis before optimizing

Fix spacetime dimension, external operators, internal symmetries and correlation functions. State any assumed gaps, parity sectors, conserved currents and uniqueness conditions. These assumptions define the allowed exchanged operators and their nonnegative coefficient structure. For a single identical real scalar, crossing is a vector equation after selecting a set of derivatives or other linear measurements. Mixed-correlator problems generally replace scalar nonnegative coefficients by positive semidefinite matrices and require corresponding matrix constraints.

A linear functional acts on the crossing vectors. If it is positive on the fixed identity contribution and nonnegative on every allowed exchanged contribution, applying it to the crossing sum gives a strictly positive number that cannot equal zero. This separates the proposed spectrum from the crossing cone. The sign convention can be reversed consistently, but identity and exchange signs must be checked together. A functional verified only at a few sampled dimensions does not prove positivity between those samples.

F1+∑OpOFO=0,pO≥0,α(F1)>0,α(FO)≥0 for every allowed OF_{\mathbf1}+\sum_{\mathcal O}p_{\mathcal O}F_{\mathcal O}=0,\quad p_{\mathcal O}\ge0,\qquad \alpha(F_{\mathbf1})>0,\quad \alpha(F_{\mathcal O})\ge0\ \text{for every allowed }\mathcal O
The identity has unit coefficient. These conditions provide an exclusion certificate only if all allowed dimensions, spins and sectors are covered with controlled numerical or analytic errors.↔ Scroll wide equations horizontally.

Keep finite functional searches distinct from spectrum cutoffs

Using finitely many derivatives restricts the space of functionals one searches. For exact blocks and certified positivity over the full allowed spectrum, a functional in that smaller space can still establish a valid exclusion; failing to find one is weaker evidence. Increasing derivative order can strengthen ideal exact bounds. Actual computations also approximate blocks, use finite precision and select spin treatments, so observed monotonic convergence must be checked rather than assumed from the ideal argument.

A finite spin list without a valid remaining-spin treatment leaves a gap in a claimed universal exclusion. Polynomial or rational block approximations used in semidefinite programs also need accuracy control on the relevant dimension domain. Primal and dual residuals, positivity margins, repeated precision settings and stable changes of derivative order are practical diagnostics. They do not automatically make an output mathematically certified unless approximation errors and all omitted sectors are rigorously bounded.

α=∑m+n≤Λamn∂zm∂zˉ n∣z=zˉ=1/2,pO=λϕϕO2≥0\alpha=\sum_{m+n\le\Lambda}a_{mn}\left.\partial_z^m\partial_{\bar z}^{\,n}\right|_{z=\bar z=1/2},\qquad p_{\mathcal O}=\lambda_{\phi\phi\mathcal O}^2\ge0
Λ is a dimensionless derivative cutoff for a chosen functional basis, not a cutoff that deletes high-dimension operators from the exact CFT. z and z̄ parametrize u = zz̄ and v = (1−z)(1−z̄).↔ Scroll wide equations horizontally.

Interpret bounds and islands with the assumptions attached

A narrow allowed island can strongly constrain a known theory when multiple correlators and justified gaps are included. Its shape remains conditional on those assumptions and on the numerical treatment. An extremal functional can suggest approximate operator dimensions, but extracting them is an additional inference rather than an existence theorem. A complete local theory requires compatible correlators and operator products beyond a finite collection of necessary constraints, even if those constraints are solved to impressive precision.

The exact arithmetic of a small cone example makes the exclusion logic visible without pretending to run a CFT computation. By contrast, a finite feasible toy system illustrates only that selected equations have a solution. The optimization lab solves gradient descent for one quadratic objective; convergence there says nothing about conformal blocks, dual certificates or a physical theory. Neither a smooth displayed trajectory nor a tiny objective value can replace verification of the actual infinite positivity conditions.

F1=(−1,1),F(t)=(1,t), t≥2,α(x,y)=y−2x:α(F1)=3,α(F(t))=t−2≥0F_{\mathbf1}=(-1,1),\quad F(t)=(1,t),\ t\ge2,\qquad \alpha(x,y)=y-2x:\quad \alpha(F_{\mathbf1})=3,\quad \alpha(F(t))=t-2\ge0
This is an exact two-dimensional cone toy model with a continuous allowed parameter. It demonstrates a separating certificate, not a bound on any CFT dimension or a computed bootstrap functional.↔ Scroll wide equations horizontally.

An exact continuous-cone exclusion

In the displayed toy system suppose a proposed equation is F1+∑ipiF(ti)=0F_{\mathbf1}+\sum_i p_iF(t_i)=0 with pi≥0p_i\ge0 and all ti≥2t_i\ge2. Apply the given functional and decide whether any such finite sum can solve it.

  1. The identity vector gives α(−1,1)=1−2(−1)=3\alpha(-1,1)=1-2(-1)=3, which is strictly positive.

  2. Every allowed vector gives α(1,ti)=ti−2≥0\alpha(1,t_i)=t_i-2\ge0. Multiplying by a nonnegative coefficient preserves that sign, including the boundary case ti=2t_i=2.

  3. The functional of the full left side is 3+∑ipi(ti−2)≥33+\sum_i p_i(t_i-2)\ge3. It cannot be zero, so the proposed nonnegative decomposition is excluded. The inequality covers the entire stated parameter interval, rather than merely a sampled grid.

The result

No allowed finite nonnegative sum solves the toy crossing equation; the separating functional gives an exact contradiction.

Explore the model

Interactive lab

Interactive lab · optimization

Convergence is not a bootstrap certificate

Reset and set BOTH Step size η = 0.50 and Initial position x₀ = 2. Predict decay toward zero under xₙ = (1−η)ⁿx₀. Reset and set η = 2.20 and x₀ = 2; predict alternating growth and eventual Outside plot reporting. This is one quadratic iteration, not SDPB, a crossing solution, a positivity certificate or a CFT existence test.

Convergence is not a bootstrap certificateGradient descent on f(x) = x²/2: xₙ = (1 − η)ⁿx₀. Playback advances two discrete iterations per second. Values outside |x| ≤ 4 are explicitly reported. Current readings: Position x0: 2; Objective x²/2: 2; Iteration behavior: Stable step. All parameters are adjustable with the labeled controls below.−4−202402.174.356.528.7Parameter xf(x) = x²/2n = 0
ObjectiveDiscrete iterate
Position x0
2
Objective x²/2
2
Iteration behavior
Stable step
n = 0 · t = 0 s

Gradient descent on f(x) = x²/2: xₙ = (1 − η)ⁿx₀. Playback advances two discrete iterations per second. Values outside |x| ≤ 4 are explicitly reported. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forNumerical optimization and the logical meaning of a physical bound require separate checks.

Check your understanding

What does failure to exclude a proposed point with one finite functional search establish?

Try it yourself

A separate finite toy problem has identity vector (−1,−1)(-1,-1) and allowed vectors (1,0)(1,0) and (0,1)(0,1) with nonnegative coefficients a and b. Solve its two equations. Does this feasible result prove that a CFT with analogous proposed data exists?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Solve the vector equation component by component, then distinguish a finite necessary condition from a complete construction.

Compare with the solution

The components give −1+a=0-1+a=0 and −1+b=0-1+b=0, so a=b=1a=b=1, satisfying nonnegativity exactly. This proves feasibility of the stated two-equation toy model. It does not supply conformal blocks, a full operator spectrum, all crossing channels, locality or consistent higher correlators. Likewise, a numerical bootstrap point that remains allowed under a finite set of necessary conditions is not by that fact an existence proof, although further controlled constraints can make it informative evidence.

Take it with you

  • A valid functional excludes only the explicitly stated hypothesis class.
  • Finite derivative searches and uncontrolled spectral omissions have different logical effects.
  • Nonexclusion and numerical convergence do not construct a full conformal theory.

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