research28 min studyLesson 867 in Physics

Carry an initial fluctuation through linear matter evolution

Separate growth in time, transfer across scales, gauge choice, and observable bias.

On this page

What you’ll understand

  • Solve growing and decaying density branches in an Einstein–de Sitter example.
  • Use a transfer function only with its normalization and physical regime stated.
  • Explain why a nearly constant potential can accompany a growing density contrast.

A primordial curvature spectrum is not yet a late-time matter spectrum. Radiation-era processing, baryon dynamics, neutrino motion, expansion history, and gravitational growth alter the relation between initial fluctuations and matter density. In a restricted pressureless linear regime, scale dependence and time evolution can often be separated into a transfer function and a growth factor. This is a useful approximation with defined normalization, not a universal property of every species or epoch. Gauge conventions and the physical meaning of a density contrast remain essential on the largest scales.

Derive a growth equation within its scale range

For weak scalar potentials, nonrelativistic pressureless matter, negligible velocity dispersion and scalar anisotropic stress, and wavelengths well inside the Hubble radius, combine linear mass conservation, Euler acceleration, and the Poisson equation. In cosmic time the density growth obeys a second-order equation balancing expansion drag against gravity. Here Φ is the lapse potential in the preceding conformal Newtonian metric. With the Fourier sign fixed earlier, an overdensity corresponds to negative Φ in the usual isolated-well convention because −k²Φ is positive.

This Newtonian sub-Hubble density contrast agrees with an appropriate relativistic density variable only within the stated approximation. Near or outside the Hubble scale, use the relativistic constraint and evolution system and specify the slicing; an arbitrary gauge density cannot be inserted into the small-scale Poisson rule. Pressure, radiation driving, modified gravity, or free-streaming components can make growth scale dependent, so the simplest common growth factor should not be imposed before checking those effects.

δ¨+2Hδ˙−4πGρˉmδ=0,−k2Φ=4πGa2ρˉmδin the stated sub-Hubble dust regime\ddot\delta+2H\dot\delta-4\pi G\bar\rho_m\delta=0,\qquad -k^2\Phi=4\pi Ga^2\bar\rho_m\delta\quad\text{in the stated sub-Hubble dust regime}
Dots denote cosmic-time derivatives, H=ȧ/a, and k is comoving. Φ and δ are dimensionless in c=1 units. The displayed Poisson relation is an approximation with its density slicing understood.↔ Scroll wide equations horizontally.

Keep both independent branches until initial conditions select one

In an Einstein–de Sitter background, matter dominates with negligible curvature and cosmological constant. The independent density solutions scale as a and a⁻³ᐟ². A pure growing mode has logarithmic growth rate f=1, but an arbitrary initial density value does not select that branch; its initial velocity or time derivative is also needed. A decaying admixture can change an early inferred growth rate without modifying gravity or the primordial spectrum.

For the growing branch, background matter density falls as a⁻³ while δ rises as a. The combination a²ρmδ sourcing the potential is therefore constant at fixed k. A nearly constant Φ is perfectly compatible with growing density contrast. This statement uses matter domination and the relevant mode branch; it need not hold through radiation–matter transition, dark-energy domination, or significant anisotropic stress. Confusing density growth with potential growth can give the wrong sign and time dependence in an observational transfer calculation.

δ(a)=Aa+Ba−3/2,f≡dlog⁡D+dlog⁡a=1for D+∝a in Einstein–de Sitter\delta(a)=A a+B a^{-3/2},\qquad f\equiv\frac{d\log D_+}{d\log a}=1\quad\text{for}\ D_+\propto a\ \text{in Einstein--de Sitter}
A and B encode initial density and velocity information for each Fourier mode. This exact background example is not a fit to the present expansion history.↔ Scroll wide equations horizontally.

Normalize the transfer before squaring it

When the physics allows separation, write a late density mode as D(a)T(k) times a defined seed mode. Specify the reference epoch where D=1 and the long-wavelength normalization of T, with the seed chosen consistently. Matter–radiation equality, photon–baryon acoustics, and free streaming leave characteristic scale dependence; they are not generated by the late pressureless growth equation alone. Galaxy counts additionally involve bias, velocities, selection, and projection rather than equaling matter density directly.

The heat lab illustrates scale-dependent attenuation only. Reset and set mode 1,diffusivity0.5, then Step twice to time 1; predict amplitude exp(−0.5). Reset and set mode 2,diffusivity0.5, then Step twice; predict exp(−2). The higher wave number is more strongly suppressed because this model’s rate is κn². It is analytic periodic diffusion, not a radiation-era transfer function, gravitational instability calculation, or matter-power inference. Its lab time is not the cosmological scale factor.

δ(k,a)=D(a)T(k)δseed(k),Pδ(k,a)=D(a)2∣T(k)∣2Pseed(k)\delta(\mathbf k,a)=D(a)T(k)\delta_{\rm seed}(\mathbf k),\qquad P_\delta(k,a)=D(a)^2|T(k)|^2P_{\rm seed}(k)
This factorization assumes the stated common linear growth and a consistent seed normalization. Multiple coupled species can instead require a matrix of transfers and cross spectra.↔ Scroll wide equations horizontally.

Grow density while keeping its potential constant

Assume a pure growing dust mode in Einstein–de Sitter. At a=0.10 its density contrast is 0.002. Find δ at a=0.50, the ratio of its power to the initial power, and the time scaling of its potential at fixed k.

  1. The growing factor is 0.50/0.10=5, so the later density contrast is 5×0.002=0.010. It remains small in this stipulated linear example.

  2. Power is quadratic in amplitude, so the ratio is 5²=25. This temporal ratio does not require changing the mode’s transfer normalization.

  3. The Poisson source a²ρmδ scales as a²×a⁻³×a=a⁰. Thus the potential stays constant for this mode, with its sign fixed by the chosen Fourier and metric conventions.

The result

The contrast becomes 0.010, its power grows by 25, and the matter-era growing-mode potential stays constant.

Explore the model

Interactive lab

Interactive lab · heat

Inspect a scale-dependent suppression

Reset and set n=1,κ=0.5, then Step twice to t=1; predict amplitude exp(−0.5). Reset and set n=2,κ=0.5, then Step twice; predict exp(−2).

Inspect a scale-dependent suppressionThe exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Current readings: Current amplitude: 1; Spatial L² norm: 1.772; Decay rate · κn²: 3.6 /s. All parameters are adjustable with the labeled controls below.Periodic heat equation mode 3 at time 0: the amplitude is 1.0π/2π3π/22π−1−0.500.51x · periodic intervalTemperature perturbation uExact mode · n = 3
Current temperature modeInitial sineCurrent amplitude
Current amplitude
1
Spatial L² norm
1.772
Decay rate · κn²
3.6 /s
t = 0 s

The exact periodic heat-equation mode is u(x,t) = exp(−κn²t) sin(nx), on [0,2π]. Playback advances physical time. The initial sine is shown separately, and the unnormalized L² norm is √π exp(−κn²t). This analytic instrument does not run a finite-difference solver or test discretization stability. Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.

Look forThis exact diffusion rate scales as n². It does not calculate cosmological transfer, matter growth, or a galaxy power spectrum.

Check your understanding

Why can a matter-era growing density mode coexist with an almost constant Φ?

Try it yourself

In the same background let δ(a)=0.010a+0.002a⁻³ᐟ². Find δ and dδ/dlna at a=1, the instantaneous logarithmic rate there, and δ at a=4. Would multiplying δ(1) by 4 give the exact answer?

Take a moment to make a prediction or work it out on paper. Open a hint when you need one.

Give me a hint

Differentiate both branches and retain the decaying contribution rather than treating the entire initial contrast as growing.

Compare with the solution

At a=1, δ=0.012 and dδ/dlna=0.010−0.003=0.007, giving instantaneous rate 7/12≈0.5833. At a=4, δ=0.040+0.002/8=0.04025. Multiplying the total initial contrast by 4 would give0.048 and overestimate it, because the second branch decays rather than grows. An initial velocity condition is needed to exclude that branch.

Take it with you

  • Late-time growth and early scale-dependent transfer are different physical operations.
  • Density and potential can have different time dependence in the same mode.
  • Initial velocities, density slicing, and transfer normalization belong to a linear prediction.

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