A weak drive accumulates a complex transition amplitude
Use the interaction picture and finite-time interference while keeping time ordering and perturbative limits explicit.
On this page
The question for today
What you’ll understand
- Define the interaction-picture state and perturbation.
- Derive a first-order transition amplitude with its phase convention.
- Explain time ordering and the breakdown of a large first-order probability.
A time-dependent perturbation does more than shift stationary energies: it can transfer amplitude between unperturbed states. Contributions created at different times carry different phases and can reinforce or cancel. The interaction picture separates the known free evolution from this additional dynamics. We will derive a finite-pulse transition amplitude, identify the meaning of resonance, and show why a small coupling still requires a bound on how long first-order theory is trusted.
Remove only the evolution already solved
Let H₀ be time independent and exactly understood, with a perturbation V(t). Define the interaction-picture state by multiplying the Schrödinger-picture state by exp(+iH₀t/ħ). Differentiating shows that it obeys a Schrödinger equation driven by V_I(t)=exp(+iH₀t/ħ)V(t)exp(−iH₀t/ħ). This is an exact change of representation; no approximation has yet been made. The initial state and measurement operators must be transformed consistently when comparing physical predictions.
The exact interaction-picture propagator is a time-ordered exponential. Expanding its integral equation gives a first integral, then nested integrals with later operators on the left. Operators at different times need not commute, so replacing the propagator by an ordinary exponential of the integral can erase physical effects. Truncating the expansion is the actual perturbative step. It is justified only when the relevant accumulated transition amplitudes and neglected corrections remain small over the specified protocol.
The first-order amplitude is an interference integral
Prepare an unperturbed eigenstate i at time zero. At first order, the coefficient of a different eigenstate f is minus i over ħ times the time integral of the perturbation matrix element, multiplied by exp(iω_fi t), where ω_fi=(E_f−E_i)/ħ. This positive phase follows from the chosen interaction-picture definition. The integral preserves phase information: probabilities from different creation times cannot generally be added before their amplitudes are combined.
For a pulse whose relevant matrix element is v exp(−iωt), constant in magnitude between zero and T, define detuning δ=ω_fi−ω. The amplitude is proportional to T times sinc(δT/2), with a midpoint phase exp(iδT/2). At resonance the contributions align and amplitude grows linearly with duration, so the leading probability grows quadratically. Off resonance their phase winds and can suppress the result. A real cosine drive supplies Fourier components of half its peak matrix element; that amplitude convention must be included when assigning v.
A transition estimate has a finite validity window
The leading transition probability is the squared first-order amplitude when the initial population remains close to one. A result larger than one is not a prediction of impossible quantum behavior; it means the truncation has failed. On resonance an isolated driven two-level system instead develops coherent oscillations when the full evolution is retained. Detuning zeros in the first-order integral likewise establish cancellation at that order, not an automatic all-orders prohibition on transitions.
The waves lab isolates interference between two contributions. Reset and set both controls to phase zero degrees and ratio one, predicting a sum amplitude of two. Reset again and set phase 180 degrees and ratio one, predicting cancellation. These two same-frequency waves can represent two phase contributions to the integral only as an analogy. They are not initial and final energy levels, and the instrument has no pulse duration, detuning, matrix element, or time-ordered quantum propagator. Its playback changes the shared wave phase rather than applying a physical drive.
Work it through
A short resonant pulse
For the specified Hermitian rotating coupling, take v/ħ=0.1 per time unit, detuning zero, and pulse duration T=2 time units. Find the first-order transition amplitude and probability. Compare with the exact resonant two-level result sin²(|v|T/ħ).
At zero detuning, the midpoint phase is one and sinc has its limiting value one. The first-order amplitude is −ivT/ħ=−0.2i.
Square its modulus to obtain transition probability 0.04. The small transferred weight supports a short-time perturbative estimate; it is not exact population conservation to every order.
The exact probability is sin²(0.2)≈0.03947. Its closeness to 0.04 confirms the leading small-pulse expansion, while longer resonant pulses would require the coherent full solution.
First-order theory gives amplitude −0.2i and probability 0.04, close to the exact resonant value 0.03947.
The living notebook
Explore the model
Interactive lab · waves
Transition contributions can cancel
Reset and set BOTH controls to phase 0° and ratio 1; predict amplitude 2. Reset and set phase 180° and ratio 1 for a separate cancelling pair. The fixed-frequency waves are an amplitude-addition analogy, not a driven quantum system.
- Sum at x = 0
- 0.866
- Resultant amplitude
- 1.732
- Phase difference
- 60°
Two waves share the same frequency and wave number. Playback advances t in sin(2x − t) + a sin(2x − t + phase). Parameter changes pause playback and recompute the model at the current elapsed time. Reset restores both parameters and returns time to zero. Playback starts paused. Adjust either parameter, then choose Play or Step.
Look forFirst combine complex contributions, then square their sum. This lab has no detuning or pulse-duration control.
Pause & reason
Check your understanding
Your turn
Try it yourself
Use the same square-pulse matrix element with v/ħ=0.1, but choose T=4 and detuning δ=π/2 per time unit. Evaluate the first-order amplitude. Does its value prove the exact transition probability is zero?
Take a moment to make a prediction or work it out on paper. Open a hint when you need one.
Give me a hint
The sinc argument is δT/2; distinguish a perturbative cancellation from an exact selection rule.
Compare with the solution
The sinc argument is (π/2)×4/2=π, so the first-order amplitude vanishes despite the nonzero coupling. Contributions across the pulse cancel at this order. Higher-order terms need not vanish, and this finite-pulse cancellation is not a symmetry selection rule or a proof of exactly zero transition probability.
Keep the idea
Take it with you
- The interaction picture is exact; truncating its Dyson series is the approximation.
- Finite-time transitions add complex amplitudes with detuning-dependent phases.
- Small coupling must be paired with a controlled duration and small transferred population.
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